I am using this example to open a text file. It works.
Imports System.IO
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal ByVale As System.EventArgs) Handles Button1.Click
Dim FileReader As StreamReader
[Code] .....
The form is made of Button1 and TextBox1 in multiline form and OpenFileDialog1 is inserted in the form. How to force a desired path so it will start in there instead of the default directory of the project?
I have files that start with unique numbers and are word documents. Say the document starts with "1234567" is there a way to make the OpenFileDialog filter to where only all the .doc files that start with "1234567" show up?
I want to save the directory that a user chooses when they open a file with the OpenFileDialog. I currently have
FileDir=My.Computer.FileSystem.CurrentDirectory
after the open dialog, and this works ok in Windows XP. But on Windows Vista this seems to give the Application (.exe) directory, whihc is not what we want.
I am developing in Visual Basic 2008 Express Edition under Vista Business SP2. I have an application with an OpenFileDialog and a SaveFileDialog. When I call the OpenFileDialog on first running the application, it defaults to the directory from which the Application last opened/saved a file. However, this directory IS NOT
When i open a file with the proces method en i try to open another file, the openFileDialog box start with the last directory and filename. In the property i write a initial directory. How can reach the situation that the box always start with the initial directory i give.
I need to have the user select a directory for the working directory. I know how to use the openfiledialog to list a file, but how do you do it for a directory?
This is my code at the moment. I want the TextBox to show the Directory of the file. (C:Documents and SettingsUserDesktopFile)
This is my TextBox Code
Private Sub TextBox1_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles TextBox1.TextChanged Me.Text = OpenFileDialog1.FileName End Sub
This is my Button Code
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click OpenFileDialog1.ShowDialog() End Sub
Im wondering why this doesn't work: It sets initialdirectory to directorypath and doesn't traverse into save folder. I've tried it all. Anyone have any ideas of how to get it to work? [Code]
I am working on an assignment, so need to pass the file to the instructor. I thought I remembered a way to input a placeholder character(s) that tells the computer that the path is flexible until the point where I declare the actual path.
For example: if the directory is C:documentsMyProjectinDebug on my machine, and is F:usersownerclass assignmentscis101StudentAMyProjectinDebug on the instructor's machine, can I put a "wildcard" type of character that points to the ...MyProjectinDebug file that will work on both machines in the Initial Directory property?
I am writing an application that in the end needs to execute another executable at some point, the problem is that the executable has dependencies in the directory it runs in that are required to operate. When I use the Process.Start to run the executable it errors out because it's looking for the dependencies in my applications directory.
I tried the startInfo.WorkingDirectory option but that didn't seem to do it either (not sure if I did it right) - here is how I used that:
Process.Start("my.exe").StartInfo.WorkingDirectory = "C:Test"For the life of me I cannot find how to set the "Start In" directory. I looked everywhere, so unless it's under a different name, I'm at a loss.
I am making a simple app to start external apps not built by me, already installed on my PC.
This:
Dim GenericExePath As String = Path.Combine(ProgramFiles, "Generic DirectoryGeneric.exe")
Works fine for most cases, but I have one exe that needs to be launched from within it's root directory.
Example: I have to go directly to the root folder to launch it.I have been able to physically create a shortcut in the root directory and launch that shortcut itself with my app and it works fine.But, how would I do this programatically without having to create that shortcut...
I have made my application to start automaticly when windows start (registry ../currentversion/run/appname + path). In this mode the application start minimized and an little icon appear in the notification icon area. With this icon you can maximize the app or exit it.If you exit the app and start it again using the Menu (Start/programs etc) than the application start in minimized mode (and in this case I would like to have it in normal mode) because the setting autostart is still true.Is there a way you can detect when the application start when windows startup using the above registry or when people click on an icon in the programs menu (or desktop)?
I am getting "The directory name is invalid" while calling process.start function.My code is
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click Dim p As New ProcessStartInfo p.UseShellExecute = False
I am writing a launcher program, and when I go to start the process I get the "The directory name is invalid" error. Here is the code that is launching the process:
I have custom asynchronous WebRequest class that I am testing to find out how fast the request will be cancelled and found some odd results, that starting 6 WebRequests with TPL and cancelling them right away takes 25 sec, but when I used just regular background threads it took only 5 sec.
Update: Running them without cancelling takes with Task.Start 9 sec and Thread.Start 3 sec accordingly. Imports System.Net Imports System.Threading
I'm using Process.Start to start an external command line application and using the StartInfo.Arguments method to send parameters to the application. I imagine I'll need to use a loop... but I can't figure out exactly how yet.I need to send anywhere from 1 - an infinite number of files names to this application. Each file has to be sent one after the other. So once the first one is done, I need to loop back around and past the second one.I can probably use the Directory.GetFiles method to get all of the files, but I don't know how to assign them.
I created 3 timers, i want each timer to take turn start which means timer1 stop then timer2 start, once timer2 stop timer3 start. But my code seem to be running together once i click the play button.And is there any ways to easy control how my picturebox move? Because my code for controlling it movement need to keep finding the correct number for it to move.
I've commented out various things to limit it to specifically this command (example, I can swap mklink out with notepad and it works fine). The command runs fine from a DOS window, but can't be found when I use it this way. I also tried using the SHELL command just to test and I get the same results. No idea why it can't be found, as like I said it executes from the command prompt just fine.
I am confused with the terms Build ,rebuild ,start , start without debugging in VS.NET.After writing the code what actually we want to do .We have to run directly by pressing F5 key or we have to build the solution .Usually i tried to run the application after coding and if shows any any errors i will fix that and run again .I never used build or rebuild thing .What exactly meant by building the solution .What is meant by rebuild and start without debugging.
I'm creating a simple .NET console application where I want to save a file in a folder that's part of the root project, like so: SolutionName.ProjectNameTestData. I want to put test.xml into the TestData folder. However, when I go to save my XDocument, it saves it to SolutionName.ProjectNameinx86Debug Console est.xml.
While i Minimized the program and clossing the program , next times i start the program, it also minimized. how can i prevent this problem happen!! And i want to start the program at position which start minimized. how can i do it!!!
