How To Start OpenFileDialog In Given Directory

Mar 30, 2010

I am using this example to open a text file. It works.
Imports System.IO
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal ByVale As System.EventArgs) Handles Button1.Click
Dim FileReader As StreamReader
[Code] .....
The form is made of Button1 and TextBox1 in multiline form and OpenFileDialog1 is inserted in the form. How to force a desired path so it will start in there instead of the default directory of the project?

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[Code]...

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[code]....

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[Code]....

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[Code]....

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