I need a vb function to determine the last numerical characters in a string. For example, if the string is Step1, I need it to return 1. If the string is Step32, I need it to return 32.I'm aware of the string functions like Right, Instr, etc but I'm just not sure how to get what I need
View 1 RepliesThe string itself contains things like "random" & random.next(1,3) & "random2" etc. The string registers all of this as a string and doesn't actually calculate random numbers.Is there any way to fix this?
View 8 RepliesI'm having a problem converting a string of letters to a string of numbers. I've tried:
Dim A As String = ""
Dim strOutput As String = ""
Dim X As Integer = 0
[Code].....
I know you can just use integer.parse to convert a string to a integer, but I need something else.I have a String like this:
001010000000101
Now what I need to do is place al those digits in a array like this:
Dim example() As Integer = {0,0,1,0,1,0,0,0,0,0,0,0,1,0,1}
What I am doing now is this:
Dim text As String = "001010000000101"
Dim collection(15) As Integer = Nothing
For i = 0 To text.Length - 1
[code]....
i do have a medium knowledge of Python, HTML/CSS. I am working on my first basic program. a simple calculator. Buttons representing numbers 0-9 Buttons with + - x / = and a clear button.
So what ive done is created a string, and when the user hits the button, it adds that value to the string (hit buton 4, it adds a 4, hit the minus, it adds a -)
i need a "function" that grabs that string, uses logical math on it, to determine the answer. I know in Python you can use: Eval(STRING NAME)is there an equivelant for VB?
Dim number As String = "07747(a)" If number.... Then endif I want to be able to check inside the string to see if it only has number, if it does only contain numbers then run whatever is inside the if statment? What check do i use to check if the string only contains numeric and no alpha ot () etc ..? What i am trying to check for is mobile numbers, so 077 234 211 should be accepted, but other alphas should not be
View 3 RepliesI included all the code this time. In calculate click event the value is zero and I don.t understand where I went wrong. My work is due tomorrow, if anyone can tell me why I can not extract the price from the string. What this program is doing is taking items from the stockListBox and adding them to the shoppingList Box then extracting the price from the shoppingListBox and adding the prices together.
0
Public Class SupplyCalculator
Dim lists As String = "staple" & "stapler" & "folder" & "notebook" & "pencil" & "eraser" & "pen" & _
[Code].....
This is my second post on this topic. I included all the code this time. In calculate click event the value is zero and I don't understand where I went wrong. My work is due tomorrow, if anyone can tell me why I can not extract the price from the string. What this program is doing is taking items from the stockListBox and adding them to the shoppingList Box then extracting the price from the shoppingListBox and adding the prices together.t a note- in public class I changed the string and seperated the price from the item, not sure if I was suppose to do that.lso, everything works except the calculate event.
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Public Class SupplyCalculator
Dim lists As String = "staple" & "stapler" & "folder" & "notebook" & "pencil" & "eraser" &
[code].....
Can I have a List containing one string and two numbers? Or I can only have one type of element?
View 3 RepliesHow can you remove number from a sting. The numbers could be anywhere in the sting and they could be any combination of numbers but would be together in the string. Ie abcdefg321hijk....
View 4 RepliesOkay, so I know now how to replace vowels in a string. Is there any way I can use the Select Case similar to the code below to replace all numbers into letter Z.
[Code]...
i want to reverse some string with numbers how to reverse it
ex: "ABC 123" --> "123 CBA"
or
"ABC 123 DE" --> "DE 123 CBA"
reverse string without the numbers
I'm working in a program that reads sms from phone I have messages like "You have successfully transferred 100.00 EGP to 20119845844Balance 7555.00Transaction: 4620439" Stord in a string So I need to search the message for the numbers 100.00 , 20119845844 , 7555.0 and 4620439 and it's sure changed every message so the how to search for this Numbers and add every one in variable to use every number of them alone?
View 7 RepliesI currently have a string like MondayJohnsRoom1130D I want to split this up so I have Monday - Day of the week JohnsRoom - Room name 1130 - Time D - Means Daily I get given this format from another computer, the room name can vary in size but the last leter D will always be one letter and the time 4 characters.... HOw can I split this up?
View 19 RepliesI am trying to parse the digits to store in a variable from a string in VB.NET (would like to also include the decimal point).
Here is an example string: Refund issued for $27.74
I need to give comma(,) for every thousends. So I used DataFormatString="${0:#,#}". It is working fine. But when value is 0. It is showing $00. I just want to show only $0.
How can we do that?
I am trying to extract numbers from string text. e.g. 1 day (8 hours)' I need the one and the eight integers pulled out I would like to extract then store each number separately for use later. I am aware of techniques to count string text, but not pulling certain information from it.
View 7 RepliesI used a regular expression, which handles both numbers and letters in strings of arbitrary length, in one line of code.
dim rtn as String = Regex.Replace(input, "..", "$& ")
I'd like to take numeric strings of arbitrary length and insert a space every 2 characters.
So 1233456 becomes 12 33 45 6. Is there a way I can use format as string or IFormatProvider, like? That would put a limit on how long the string could be though, right? Since I'm casting to a long.
CLng((input)).ToString("## ")
I'd like to take strings of arbitrary length and insert a space every 2 characters.
123dssas4rr should become 12 3d ss as 4r r
I like to know to split a string value from a mixed value.[code]Now the result will be "Check".Is there any short ideas?
View 1 RepliesI have a program that throws out a string of six numbers from 1 to 37, what I need to do is check the the string for for a format you could say.I need to make sure the set of six numbers doesn't contain 4 or more numbers of the same numbers from the same set of ten(s).
Like this:I can't have: 1-3-6-7-8-12 Or 12-14-16-18-20-21 Or 21-23-26-28-30-31 Or 30-32-34-36-20-22
I can have : 1-3-6-12-17-23
////////////: 12-14-16-20-21-22
////////////: 20-1-13-23-26-30
////////////: 1-37-22-33-30-9
[Code]...
i have a number in this format: 123 and I want a select statement such as below for comparsion so i dont have as many if statements:
Select case numbers(i)
case is = "123"
case is = "234"
example but in real scenario numbers are random.
Heres my code in which all select cases dont get fired:
Public Function UserAdd() As String
On Error GoTo Errorhandler
Dim personcount As Integer
[Code]....
But the case is statements above dont fire when I know that number is correct above
I am trying to gather all numbers in this string which is the name of an image file. The name of the string is ABC09072009XYZ777000111.jpg. When I use
Dim rx as new Regex("d")
Console.Writeline(rx.match(input))
It only returns the first set of numbers before the xyz. I need them all.
Lets say I have the following String Array:
Code:
dim strArr(3) as String
strArr(0) = "15 Joseph"
strArr(1) = "24 Nick"
strArr(2) = "3 Mike"
[Code]...
I use Visual Basic 2008 with Mysql I have a table article with the following data :
Articlenb - Productcode - amount
1 - XXL - 1
2 - 12 - 1
[Code]......
I am needing to locate a given set of numbers in a string, and have limited success, it is almost always finding the numbers that I want, but I need it to be more reliable.Below is a test program that I am using to test with and also 2 picures that may explain better that I can put into words.
[Code]...
How can I generate a random string of 8 numbers and letters?
View 8 Repliesi am looking for some tip to format a datetime stamp to format Saturday, December 31, 2011. I am able to get day of week, month, year in numbers but not in string. I can create arrays for days,month but i don't want to use lots of memory, if theres a function i can use it.
View 3 RepliesI have to (for class) make a program that generates a safe passwords for people to use. My teacher wants us to make the passwords vary in length, include numbers, letters and upper case letters. I've been able to write code that prints out a random string but it includes unrecognized characters for most passwords. How would I write the code to create a random string that has parameters? (in this case upper case lower case letters and numbers).
View 9 Replies<edit> Now showing the difference as a DECIMAL. Result looks like zero every time. </edit>Disclaimer: This code is provided "as-is" and should be treated as Freeware.( However any donations would be welcome as I have a "so-so" part-time job ).Please note all real numbers to be used should be in this format
"0.000000000000"Do not use numbers in string format in scientific notation like "1.2345E -06"I was feeling bored and decided to add to the code from JohnWein in this thread where I have used a routine that will multiply the contents of two long strings together.>>[url]I have now added a bit of code so you can multiply two really long numbers with or without a decimal point as a full-stop ( period or dot, call it what you like ).
[code]...
I am trying to wirte a function for a Phone number class called "import phone number". It should take any string with 10 digits in it somewhere (and allow for an extension), and import them into it's own properties: AreaCode, Prefix, Suffix, and Extension (aaa-ppp-ssss-xxxx...).
I check the input with a regex to make sure it's valid, now i want to tokenize those pieces into their respective properties. What I have looks like this (incomplete):
Public Sub ImportPhoneNumber(ByVal anyNumber As String)
'phone number is 10-digits long, e.g.: 012-345-6789
Dim reg_exp_10 As New Regex("^((D*)d(D*)){9}((D*)d){1}(((x|ext){1}(d)+)?|D*)$", RegexOptions.IgnoreCase)
[Code].....