Pixels In Cm Or Mm?

Oct 16, 2009

i`m trying to find in cm or mm the area of a frame (capture image).The picturebox has dimensions height:456 and width:553 PIXELS.So the total number of pixels are 456 x 553 = 252,168

If i compare image 1 with image 2 i can locate and draw a rectangle around that area of pixels that are different.i can get the width and the height of this rectangle in PIXELS.e.g Height:49 Width:33 PIXELS

How can i covert these into cm or mm. What i need to know for the conversion?

I know dpi: dots per inch but what`s the value for my rectangle?

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Jul 27, 2009

I'm trying to make a -what i thought would be simple app.My intention was to build program that:1) i'd provide a grayscale image2) the program would count the black pixels the grey pixels the more grey pixels etc. (the hue) and the white3) would make the percentage sum of all pixels, that is: 300.000 black pixels (rgb 0 0 0) etc. given that 0 is the black, 100 the white. e.g a simple grayscale image is 55.2 white

This was my way and i don't think that is useful:

First of a button to convert the image to greyscale:

Dim bm as new Bitmap(source.Width,source.Height)

Dim x

Dim y

[CODE]...

Secondly, -and that's the stupid way- i did -or better i wanted to do- this: i put the code to dynamically create labels, each label having the colour of a pixel as background colour and as text the colour converted to rgb

The third step which i intended to do (i couldn't get pas two) was to sum up the labels etc.

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how to make this into useful code?

Imports System.Runtime.InteropServices
Public Class Form1
Private b1 As Bitmap

[Code].....

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[Code]...

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This explains a lot why I was having much trouble determining the color of pixels. They are inverted!
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Dim hWnd As IntPtr = GetDesktopWindow()
Dim hDC As IntPtr = GetWindowDC(hWnd)
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ReleaseDC(hWnd, hDC)
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I am trying to determine the length of a string in pixels.

I created a little test program for myself and placed three labels on it, each with the same font in a different size. I set the width of the label to 1024, the screenwidth. I used the same test text for each label, cutting it off at the last character that shows, so there is not hidden text running off the label to be included in the string width count.

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Here follows the whole test code. You can drop three labels on a form and run it to see what I mean.

Code:
Option Explicit On
Option Strict On
Public Class frmMain

[Code].....

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[Code]...

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