Splitting String And Converting To Double?
Apr 25, 2012
I'm new to VB, I'm now want to know how to convert received string to double.I'm receiving string as 420.8 280.9 140.2 like this from serial port.. and transferred it into textbox..I'm using following code to split string and to convert to double
Dim ReceivedText As String
ReceivedText = txtReceived.Text
Dim str_RY_1U, str_RY_1V, str_RY_1W As String
[code]....
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Apr 26, 2012
I'm new to VB, I'm now want to know how to convert received string to double. I'm receiving string like this 420.8 280.9 140.2 from serial port.. and transferred it into textbox.. I'm using following code to split string and to convert to double
[Code]...
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Jun 17, 2009
i am converting a string to double?i would like to know in advanced whether it would case an error to convert a string to a double. for example if i try to convert "hello" to a double, it would give me an error. is there a way for me to know ahead of time whether converting something will cause an error?
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Mar 25, 2010
The message does not appear if a number is not entered - why?
Dim
IAL As Double
Dim inputIAL As Double
[Code].....
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Nov 2, 2010
I was trying to convert from Double to String and everything working fine. But when I tried some bigger number with fractions in it. I got the number but rounded. I tried something like that:
Dim dd As Double = 1235212435.3453636
Dim str As String = dd
MsgBox(str)
But what I got is 1235212435.34536 instead of 1235212435.3453636
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Nov 1, 2009
Public Class frmWaiter
Private Sub btnCalculate_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnCalculate.Click
'Bill Amount Input Box
Dim txtBillAmount As String
[code]....
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Feb 24, 2012
I am storing a value (represented as a string originally) like this -2345678901234.12345678912 - in a double variable. After storing, it is represented in an exponential format (with an e). How do i convert this exponential representation to the original(string) representation?
[Code]...
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Nov 19, 2009
I want to convert an array of numbers to a string with a colon imbetween splitting it. I tried:
StringA = Join(Array(), ":")
I get the error: 'Number of indices is less than the number of dimensions of the indexed array.'I seem to get this error alot in my programming but don't exactly know what causes it. Even if I can fix this error I heard that Join only works for string arrays so this wouldn't work anyway.
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Nov 12, 2011
The only post I can find on this matter is one that coverts the double to a decimal before converting it into a string. However the numbers I'm using are far larger than what a decimal can store.
Example: 1/(16^10)
So how can I convert the solution to the problem above. Which equals 0.00000000000090949470177292824, to a string value that is exactly as it's shown?
Cause when I convert this to a decimal I still end up with a string in scientific notation..
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Mar 4, 2010
I'm trying to delete the 2 last characters of a string if they are "||". This is my
Dim MyReader As Microsoft.VisualBasic.FileIO.TextFieldParser
MyReader = My.Computer.FileSystem.OpenTextFieldParser(playlist)
Dim TextFields As String() = MyReader.ReadFields()
Dim last As String = TextFields.Last
If last.Substring(last - 2) = "||" Then
last.Remove(last - 2)
End If
But it gave me the following error on the highlighted line:
"The converting from the string to the type Double is not valid."
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Jan 31, 2010
I have a program that calculates commission, but if the commission is nothing then I do not want it to show a zero commission. I want a message box to show a message that there is no commission earned.
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Feb 15, 2012
i want to split the data from a text file and save it to the sql database.attached here is the .txt file and the format.this data is from a chronolog machine im thinking of using string token but it does not have a separator.how can i split the strings. this is the code that i've started. i've extracted the .txt file but i have no idea yet how to split it.
Set con = New ADODB.Connection
Set rec = New ADODB.Recordset
con.Open "DSN=chrono"
rec.Open "Select * FROM DT102T01.txt ", con, 3, 3
Set DataGrid.DataSource = rec 'display only to show that i get the data
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Oct 13, 2009
I need to split a string at all whitespace, it should ONLY contain the words themselves. How can I do this in vb.net? Tabs, Newlines, etc. must all be split! This has been bugging me for quite a while now, as my syntax highlighter I made completely ignores the first word in each line except for the very first line.
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Jun 16, 2009
Possible Duplicate: splitting a string i have a string which looks like this:[URL] i need to get each of the numbers and put them in an array in this order: 0, 50, 100, 100, 200, 400, 218, 9.8, ???, 6.65, 6.31 etc... i have the following code but for some reason it only does the first column, it only gives me 0, 50, 100, 100, 200, 400, 218, 9.8, ???
[Code]...
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Jan 11, 2012
I want to know on how to pass the string value after splitting them. For example, the string value is (Ron Male Norway).
after splitting them, i want these value being passed to an insert sql query. How would i do that.?
Dim str As String = RON MALE NORWAY
Dim strArr() As String
Dim count As Integer
[Code]....
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Jul 18, 2012
I am creating a recipe program that will allow the user to save recipes in an external file, retrieve them and work out a new value for ingrediants depending on how many people they want this time. However within my code errors keep appearing and I cannot work out why they do.
Imports System.IO
Public Class Form1
Dim Unit, nameofrecipe, nameofingrediant, oldrecipe, recipewanted, filecontents As String
Dim quantity, originalamountofpeople, newpeople As Integer
[code]....
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Jun 9, 2010
I am trying to split a string into array. I know about split, but it seems to need a separator of some type. Suppose I am going to be working with input like the following. 8561369 and I want to split each character of that string into an array. I tried something like this, but again Split seems to need a separator, I just keep getting the entire string in one entry of my array, not split. Dim values as String 'I am going to be populating this string variable via user input eventually, 'which is why I cannot just add spaces. values = "8561369"
[Code]...
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Nov 15, 2011
How would I go on splitting a string into pairs of letter in VB?
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Mar 11, 2010
Im trying to work out how to do a project called pig latin in vb.net 2003... so far I've gotten it to work for a single word. If there are spaces it still acts like there is only one word with the rules (ex: monkey stuff = onkey stuffmay) I know that i have to figure a way to seperate the string up if there is a space and do the rules for pig latin for each word and then make it show up in a message box but I'm stuck... as soon as i can get it to split I have to calculate the number of words starting with a variable and percent of said words and so on which shouldnt be hard with an If Then statement
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Sep 9, 2009
I have lines like this
GND P3559 9812, 7993 p9910.26;
GND P3559 9812, 7993 p9910.26;
46N93 P594 40898, 35899 39MIL;
PHY2_P2_CONFIG0 P2767 34205, 33537 39MIL;
I want to get only the value that I highlighted. I split the line like this
Dim tfLines() As String = System.IO.File.ReadAllLines("C:\file.txt")
Dim sf As New System.IO.StreamWriter(drill, True)
For I As Integer = 0 To tfLines.Length - 1
Dim Words() As String = tfLines(I).Split(",")
Dim sWord() As String = Words(0).Split()
[Code] .....
From the code above I can write all the values that I highlighted in red. To get the blue colour value I try to split my line again like this:
Dim tWord() As String = Words(1).Split()
If I use this code it shows me error "Index was outside the bounds of the array." I don't know why I am getting this error.
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Sep 17, 2009
Here is an example "I want to split this string into 3 separate pieces" The above string contains 50 characters including the spaces.What I want to do is divide the string by 3 =16, but split it at the next space so the words stay whole, so they will read "I want to split this" = 20 "string into 3 separate" = 22
"pieces" = 6 With another string, it may need to be split into 4 = 12 characters each, but split it at the next space, so it would read:
"I want to split" = 15
"this string" = 12
"into 3 separate" = 15
"pieces" = 6
I would need to use the trim method to remove leading spaces and trailing spaces - I can do that but I can't work out how to split a string into 3 approximate equal lengths and keep words whole.
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Jul 11, 2011
I need to split one variable into 3 variables. For example I have a variable called Data and it contains AAA00000001. I need to have them be split between the "AAA", "0000000", and "1". I looked at the Split() function but didn't get a clear example for this situation. The reason I need to do this is because I want to store these 3 variables into fields for a MySQL database.
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Oct 16, 2009
I just can't seem to wrap my head around this.I wan to split a string up to a certain amount of characters.Eg if the string is "Hello"I want it to split up to 3 charactersthe result then would be "Hel".I tried various things, googled it, but I can't seem to find anything good.
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Apr 3, 2012
I am using a VB.NET(VS2010) to read data from serial port. I have 8-bit data to collect through rs232. This data is represented numbers. What reading method should I use and how to convert it to double format?
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Apr 25, 2012
how to convert received string to double.
I'm receiving string as 420.8 280.9 140.2 like this from serial port.. and transferred it into textbox..
I'm using following code to split string and to convert to double
Dim ReceivedText As String
ReceivedText = txtReceived.Text
Dim str_RY_1U, str_RY_1V, str_RY_1W As String
[Code]...
For calculating percentage RY_R is calculating fine.. But when it comes to RY_Y it showing error "string not in a correct format..."
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Jul 22, 2011
I want to separate Textbox1.Text into parts based on a custom separator, "-".I do it that way:Okay then, this is it:
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Aug 20, 2010
Basically, Im running an SQL query to the database, which obviously returns data in their fields. What I want to do is add each record into an ArrayList and split the string based on fields. I.E
CustomerID,Surname,GivenName etc
How do I go about this? so far I have:
alstData.AddRange(sLine.Split(","c))
sLine = the record from the database.
This doesnt seem to work, it just display's the data in one line with no split such as 20205SmithJohn?
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Sep 20, 2009
I am trying to make a simple smtp client and I would like to have it so it can add more then one recipient to the emailso I wanted to learn how to split a string using delimiters. I have only used delimeters in batch with a FOR loop but I don't know howThis is a sample I found on the net.
Private Function SplitStringIntoWords() As Integer
Dim strComplete As String = "This-is a complete sentence"
Dim strWords() As String
[code].....
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Jun 15, 2009
I have the following string:
[URL]
I need to separate each value and put it in an array. typically it would be done by ".split". however I need it to be split in this order: 0, 50, 100, 200, 400 etc.. In other words, I need it to read the rows left to right. I have no problem separating each number, I just need it to read it in the specified order. I've tried the regexp and I forgot to mention that after each line there is a line break. I am not sure if this would impact the regex, but in any case, after i do the regex, I get the following order: 0, 6.65, 84..??, 35.... etc
I am not getting the order I need as stated above
Expected results: 0, 50, 100, 100, 200, 400, 218, 9.8, ???, 6.65, 6.31 etc...
I am going to follow some of the suggestions below by splitting up the string into separate lines initially. this code almost does that:
Dim fields() As String
fields = calculationText.Split(vbCrLf)
Unfortunately for some reason the spaces are lost. When i look into the array, all the spaces between numbers are lost. why?????????
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Jun 14, 2011
I want to split a string with this array of char
Dim sepa As String = " '"",.;:(){}[]·#|-_<>+¿?=/&%$‚¬@!¡"
The question is how do I include in this string vbcrlf? So I can do the fallowing:
dim palabras as String() = RichTextBox1.Text.ToString().Split(sepa)
I tried:
Dim sepa As String = " '"",.;:(){}[]·#|-_<>+¿?=/&%$‚¬@!¡\r\n"
But it does not work.
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