Get The FileName For The Proces.Start(FileName) Method?
May 27, 2009
I have a Listview on my form with different files. I can selet a file en open it with the proces start method. To open the file i use the OpenFileDialog method and select the filename. This work very good. With the code below.
My question is if there is a method to get the selected file without using the OpenFileDialog Box. So when i dubbelclick the selected file the proces will start with open the selected file. Something like:
proc.StartInfo.FileName = Me.SelectedCell.FileName
instead of proc.StartInfo.FileName = Me.OpenFileDialog1.FileName
PS) May be i can preduce the Filename using the OpenFileDialog method on the background.
Private Sub ListView1_MouseDoubleClick(ByVal sender As Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles ListView1.MouseDoubleClick
If Me.OpenFileDialog1.ShowDialog() = Windows.Forms.DialogResult.OK Then
Quick query...I'm trying to scan a long string and return any values that occur between the tags <FileName> and </FileName> I've got a bit of code here to use regular expressions to return the position of the occurunces of both substrings..Just wanted to find out if there is any way to scan for both substrings within one loop (as im currently doing 2, one for the first substring and one for the 2nd) so I can use something along these lines:
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Dim patternstart As String = "<FileName>" Dim patternend As String = "</FileName>" Dim matchesstart As MatchCollection = Regex.Matches(XMLRESP, patternstart)
How would I do that? Sample code is below that demonstrated that the file I opened contained the full path and file name.
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If openFileDialog1.ShowDialog() = DialogResult.OK Then Properties.Settings.Default.persistConnectionType = openFileDialog1.FileName Properties.Settings.Default.Save();
Cannot start a process because a filename has not been provided.
Private Sub Backup_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdBackup.Click Process.Start(adbFind.adbLocation.Text, "pull /data/local/bootanimation.zip C:Backup.zip") End Sub
It was working fine now this is just started to appear, i have went back as far as i can where i only have that line of code and it still appears.
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I know how to launch a file or executable in VB .NET 2005. The file will launch and xecution in the code continues immediately.Process.Start("MyProg.exe")But what if I need to start the program, wait until it finishes executing, read the exit code that it sends back, and take some action based upon th
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If({FN} = "easter.exe") Then msgbox("You found a easteregg! :O") end
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Private Sub cmdExportToPDF_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles cmdExportToPDF.Click Dim SaveFileDialog1 As New SaveFileDialog()
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In the XP SaveFileDialog, the user is allowed to set the SaveFileDialog.FileName. I'm using Vista operating system and am using the VistaBridgeLibrary.dll so that I can get the Vista version of the Dialog Boxes. With the CommonSaveFileDialog (for Vista dialog), I'm unable to set the FileName property since it's read only.
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There is no editor available for '<filename>'.Make sure the application for the file type (.vb) is installed.I got this message after I updated a VB08 project to VB10. I tried to open a form when this message was shown. It happens to every form in the group (but not standard classes).
I'm working on a final project where I need to create a file for a recipe. I'm trying to take the name of the recipe as entered by the user in a specific text box and create a sequential access .txt file bearing the recipe's name.[code]...
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Dim folder2 As String = ComboBox2.SelectedItem 'rename the hap file Dim source As String = System.Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments)
I have an app that opens MS word. I then open Word's File open dialog and have it pointing to a specific directory to find a file for the user to open. What i cannot do is retrieve the file name the user selected to open. In a Window's fileopen dialog i can read the .fileopen property, however there doesn't seem to be a corresponding property to read in Word's dialog. Is this even possible? if so how do i do it?
i want to detect currently opened swf file name here is my code
Private Const GW_HWNDNEXT = 2 Private Declare Function GetWindow Lib "user32" (ByVal hWnd As Long, ByVal wCmd As Long) As Long Private Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As Long
[Code]....
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