InvalidArgument=Value Of '2' Is Not Valid For 'index'?
Nov 4, 2010Dim group11_0_count = 0
Dim group11_1_count = 0
Dim group11_2_count = 0
[code].....
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[2008] Error: InvalidArgument=Value Of '6' Is Not Valid For 'index'. Parameter Name: Index
Mar 5, 2009I've got the web browser with tabs in all working fine, but there's one bug, i can add tabs, delete em, etc.. but when i delete a tab then go to create a new tab, it gives me the error: InvalidArgument=Value of '6' is not valid for 'index'. Parameter name: index '6' is the number of tabs i had open.Here's the bit of code i use to create the tabs with the browser in it:
vbcode
Dim browse As New WebBrowser
browse.Name = "b1"
browse.Dock = DockStyle.Fill
[code]....
VS 2008 InvalidArgument=Value Of '0' Is Not Valid For 'index'. Parameter Name: Index
Jul 26, 2009When the selected index changes I for a second time this code errors.
vb.net
lvReports.SelectedItems.Item(0).SubItems.Item(2).Text
with this error message
InvalidArgument=Value of '0' is not valid for 'index'. Parameter name: index
Why is this?It worked for the listviews.click event perfectly.
Error: InvalidArgument=Value Of '1' Is Not Valid For 'index'
Jul 9, 2009InvalidArgument=Value of '1' is not valid for 'index'. Parameter name: index
This is my code
Private Sub Button5_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button5.Click
Dim Conn As OleDbConnection = New
[Code]....
ERROR:"InvalidArgument=Value Of '5' Is Not Valid For >> Index.'
Apr 6, 2011My users are getting this error :
ERROR:"InvalidArgument=Value of '5' is not valid for >> index.'
They are getting this while they enter to this page. its a application issue or sth related to database which i need to work on? I really do not know that its right place or i have to choose different type?
List Veiws - InvalidArgument=Value Of '0' Is Not Valid For 'index'
Nov 1, 2011dim ItemNum As Integer = 0
Dim Selecteditem As ListViewItem = ListView1.SelectedItems(ItemNum)
Select Case ItemNum
[CODE]...
keeps telling me that InvalidArgument=Value of '0' is not valid for 'index'.
Error : System.ArgumentOutOfRangeException: InvalidArgument=Value Of '1' Is Not Valid For 'index'
Dec 12, 2009LoopBegin:
Do Until strXMLSingle.Contains("ENDOFXMLCHECK")
strXMLSingle = getTempFile.ReadLine
If strXMLSingle.Contains("<character") Then
[code]....
I have that so far. It was working great for the names part until I attempted to do the level part, now i get the following error:
System.ArgumentOutOfRangeException: InvalidArgument=Value of '1' is not valid for 'index'.
Also at the line where i use a goto statement to go back to the beginning of the loop, is there any way i can do that without a goto statement? Like a second loop statement or something?
Client / Server Application - Error: InvalidArgument Value Of 0 Is Not Valid For SelecteD Index
Apr 27, 2011I have created player to stream(broadcast) a video from server to clinet in Lan network,my problem is when I send URL of the video to client it take it and add to playlist but when I want to play it message box show's "InvalidArgument value of 0 is not valid for selecteD Index parameter name:selectedIndexSystem.windows. form" I will but the code of client and server but the I have determine the video which will be broacast in client side. [Code]
View 3 RepliesVS 2008 - Listview Selected Item Getting Error InvalidArgument=Value Of '0' Is Not Valid For 'index'?
Feb 12, 2010I have this code
[code]...
And I select one and it works! But when I try to select a different one it comes up with an error on..If ListView2.SelectedItems.Item(0).Text = "None" Then
The error..InvalidArgument=Value of '0' is not valid for 'index'. Parameter name: index
Index Error "InvalidArgument=Value Of '2' Is Not Valid For Index" For ListBox
Oct 16, 2011Im just going to have to get used to this language for the rest of the semester And smohd, I will get back to you with my problem. That "Me..." control is so random. Not like JAVA Why am I getting an error with totalGrade
[Code]...
Invalidargument=value Of "-1" Is Not Valid For Index
Sep 6, 2011I have this code and I getting this error "invalidargument=value of "-1" is not valid for index"
Private Sub lunachange_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles lunachange.Tick
If Listlog.Items.Count <> 0 Then
Dim count As Integer
count = Listlog.Items.Count
[code]....
InvalidArgument=Value Of '-1' Is Not Valid For 'start'
Dec 14, 2009InvalidArgument=Value of '-1' is not valid for 'start'
View 4 RepliesValue Of '0' Is Not Valid For 'index
Nov 1, 2011I have data that goes to another listview on the main form. Anyways, I have a user on a WinXP machine tell me about the following error[code]...
View 6 RepliesValue Of `6`is Not Valid For Index?
Feb 5, 2011I am trying to export the contents of a list view control to the clipboard in VB.NET and windows 7. With VS 2008 I had no problem but when I installed vs 2010 I am getting this error value of `6`is not valid for index.
View 11 RepliesListview - Value Of '0' Is Not Valid For 'index'
Jul 21, 2011I have this [Code] When I debug the program, I have a listview. I use another button to add items to the listview. When I highlight an item, it's fine; the item starts. The problem is that when I highlight a different item, I get this message,
InvalidArgument=Value of '0' is not valid for 'index'.
Parameter name: index
Specified Argument Was Out Of The Range Of Valid Values. Parameter Name: Index
May 15, 2009i'm trying to do a filename compare, sort of fuzzy match.Here's what code i have.First of all i load 2 directory's into 2 listbox's as strings and remove the filepath. Directory1
Code:
TextBox1.Text = FolderBrowserDialog1.SelectedPath
If TextBox1.Text = "" Then
Else
Then when i click the compare button i am trying to pass listbox1 and listbox2 through Distance and return the resulting fuzzy file matches.
Code:
Dim MyObject As New StringSift2
Dim ReturnVal As Single
ReturnVal = MyObject.Distance(ListBox1.SelectedItem, ListBox2.SelectedItem)
[code]....
But i get this error.
Code:
TreeView1.Nodes(lb1).Nodes.Add(ReturnVal.ToString())Specified argument was out of the range of valid values. Parameter name: index
Invalid Argument = Value Of "0" Is Not Valid For Index?
Nov 2, 2010I have a little program where the user can select an item out of a listview. In this particular listview there is this code under the listboxindex changed event:
Private Sub Lopd_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Lopd.SelectedIndexChanged
opdrachtgever = Lopd.SelectedItems.Item(0).SubItems(0).Text
[Code].....
InvalidArgument=Value In Listview?
Jan 4, 2010In my application i loop through the contents in a listview, then delete that value after i'm finished with it:
PHP
For x = 1 To listviewIDs.Items.Count
Print to screen the listview values
MessageBox.Show(listviewIDs.Items(x).Text)[code].....
The code works, it uses the values from the listview once it's finished it deletes them, but when it gets to 8 items left in the listview i get an error: InvalidArgument=Value of '8' is not valid for 'index'.Parameter name: index when i look in the listview there is 8 items still left in there, i'm not sure what i have done wrong.
Sql - Unable To Find Specified Column In Result Set Index Out Of Bounds Index Out Of Range Exception
Apr 23, 2012i am having trouble putting a value in a textbox. Each time a ticket is sold i put the total price in a textbox, each time a ticket is sold for the same concert it increases by adding its self to the total price. It works at the first sale, but after that it breaks down. here is the code
Private Function DisplayMoneyTaken() As Integer
Dim totalMoney As Integer
'open the database connection
[Code].....
VS 2005 Error:Index Was Out Of Range. Must Be Non-negative And Less Than The Size Of The Collection.Parameter Name: Index
Oct 23, 2009Getting error filling grid view from reading through data table:
Dim myDataTable As DataTable = myDataSet.Tables("SunTrust")
Dim myRow As DataRow
Dim i As Integer = 1
Try
[code]....
Error:Index was out of range. Must be non-negative and less than the size of the collection.Parameter name: index
Datagridview : Index Was Out Of Range. Must Be Non-negative And Less Than The Size Of The Collection. Parameter Name: Index?
Dec 9, 2009I am using Sub to format datagridview but during Form_Load this error occur. There are rows in datasource and dg.row.count is > 0.
.Columns(0).Width = 50 <==== ERROR HERE
.Columns(1).Width = 150
.Columns(2).Width = 80
.Columns(0).HeaderText = "ID"
[code].....
Error - Index Was Out Of Range. Must Be Non Negative And Less Than The Size Of The Collection. Parameter Name: INDEX
Jan 22, 2009What im trying to do is send vars to a flash file.The following is my code:
Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
Dim oTitle As New ArrayList
Dim oSub As New ArrayList
Dim oRate As New ArrayList
[code]....
What I'm expecting the output to display is something like "t1=value&s1=value&r1=rate&t2=value&s2=value&r2=rat&t3=value&s3=value&r3=rat" But... i keep getting this exception: index was out of range. must be non negative and less than the size of the collection. Parameter name: INDEX.
Error - Index Was Out Of Range. Must Be Non-negative And Less Than Size Of The Collection. Parameter Name: Index
Aug 25, 2011I have a datagridview, with 3 columns, each containing dropdown filters (in the column header). Of the 3 columns, 2 are working perfectly fine, but whenever I try to filter the 3rd column, it gives me this error: (Also all of the column's have the ColumnType property set to: DataGridViewAutoFilterTextBoxColumn) "Index was out of range. Must be non-negative and less than size of the collection. Parameter name: index." The error points to the part that begins with "If dgv1.Rows(e.RowIndex)..."
Private Sub dgvWPS_CellFormatting(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewCellFormattingEventArgs) Handles dgv1.CellFormatting
If e.ColumnIndex = 1 Then
[code]....
Index Was Out Of Range - Must Be Non-negative And Less Than The Size Of The Collection. Parameter Name: Index
Apr 13, 2010i am trying to get the value into the cur_stock where item_id = datagrdiview.curentcell.value.I am lookin out for the solution since couple of days, but couldnt figure it out.Well, m trying to make this work on CellMouse click event
Below is my vb.net code:
Private Sub DataGridView_stockout_CellMouseClick(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewCellMouseEventArgs) Handles DataGridView_stockout.CellMouseClick
Dim i As Integer = Stock_checkDataSet1.Tables(0).Rows.Count - 1
[code]....
Use An Array With Index Number To Insert The Text But Index Was Out Of Range?
Apr 30, 2012Trying to input a high setpoint, low setpoint, a % load, and number of compressors, then calculate the temp that all compressors are off. Then build a datagridview with the staging of compressors from all off to all on for each compressor up to 10 compressors.I am trying to insert headers from 1 to 10 compressors (Variable) with the text "Comp1", "Comp2", etc....Two rows with header. I am trying to use an array with index number to insert the text, but that is where my problem happens."Index was out of range".Here is my code
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim i As Integer, num1, num2, num3, num4, alloff As Single, stg As Single
TextBox1.Focus()[code].....
Comparing Array Index To Combo Box Index?
Nov 14, 2010I am coding a program for a movie trivia game that randomly shows a movie quote and the the user selects a movie name from a combo box that matches. I used a array for the movie quotes and a comboBox for the movie names. I have coded a portion of the program but I am stuck on how to compare the array quote being shown to what movie the user selects from the comboBox. I have tried numerous different things but none seem to work right. The way I have it coded now it shows that every movie I pick that it is right even if it is wrong. I am going to show part of the code here and also attach the entire solution for anyone that needs it .
[Code]...
DataGridView Index - Index Was Out Of Range?
Apr 14, 2009I am working in VB 2008 and I have set up a datagridview to display rows of data which can then be selected. When I select the first row I get the error: Index was out of range. Must be non-negative and less than the size of the collection. When I select any other row the program executes as it should. From what I have learned so far is that the DataGridView has an index of -1 and that it counts the header row as part of the index which is the -1.When I select the first row through either DataGridView1_RowHeaderMouseClick or DataGridView1_CellContentClick the index is 0 for the first record. If the index is 0 I think it would fire off, but I have no idea what is happening behind the scenes. I can check the index, so when it is 0 and the code attempts to access the row, that is when I get the message.On an index number of 1 and up the code executes fine.So, is there a way to re-index the DataGridView, or is there a work around/fix for this issue?
View 2 RepliesGet The Column Index And Row Index On ListView?
Apr 6, 2010How can i get the Column Index and the Row Index when I click on the ListView?The ListView1.FocusedItem.GetSubItemAt(e.X, e.Y).Text function only gets the text of the first column, I can't find the option of getting the Index of the Column and Row upon clicking.
View 9 Replies"Index Was Out Of Range. Must Be Non-negative And Less Than The Size Of The Collection. Parameter Name: Index"?
Apr 20, 2012I am running a VB.NET program and having an error of "Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: index".My code looks like below.
If Status.InvokeRequired Then
Try
Status.Invoke(New delegateoneArg(AddressOf onChangeEvent), ws)[code].....
Sort ListView By Image.Index If Index Over 4 Sort Rest Alphabetically
Apr 12, 2012Currently my ListView sorts items by image.index. So 0 is at the top, then 1, 2 and so on. Think of it as an IRC chat room nick list. Ops at top then the rest are sorted alphabetically
[Code]....