[2008] Error: InvalidArgument=Value Of '6' Is Not Valid For 'index'. Parameter Name: Index
Mar 5, 2009
I've got the web browser with tabs in all working fine, but there's one bug, i can add tabs, delete em, etc.. but when i delete a tab then go to create a new tab, it gives me the error: InvalidArgument=Value of '6' is not valid for 'index'. Parameter name: index '6' is the number of tabs i had open.Here's the bit of code i use to create the tabs with the browser in it:
vbcode
Dim browse As New WebBrowser
browse.Name = "b1"
browse.Dock = DockStyle.Fill
[code]....
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Jul 26, 2009
When the selected index changes I for a second time this code errors.
vb.net
lvReports.SelectedItems.Item(0).SubItems.Item(2).Text
with this error message
InvalidArgument=Value of '0' is not valid for 'index'. Parameter name: index
Why is this?It worked for the listviews.click event perfectly.
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Feb 12, 2010
I have this code
[code]...
And I select one and it works! But when I try to select a different one it comes up with an error on..If ListView2.SelectedItems.Item(0).Text = "None" Then
The error..InvalidArgument=Value of '0' is not valid for 'index'. Parameter name: index
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Oct 16, 2011
Im just going to have to get used to this language for the rest of the semester And smohd, I will get back to you with my problem. That "Me..." control is so random. Not like JAVA Why am I getting an error with totalGrade
[Code]...
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Jul 9, 2009
InvalidArgument=Value of '1' is not valid for 'index'. Parameter name: index
This is my code
Private Sub Button5_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button5.Click
Dim Conn As OleDbConnection = New
[Code]....
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Apr 6, 2011
My users are getting this error :
ERROR:"InvalidArgument=Value of '5' is not valid for >> index.'
They are getting this while they enter to this page. its a application issue or sth related to database which i need to work on? I really do not know that its right place or i have to choose different type?
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Dec 12, 2009
LoopBegin:
Do Until strXMLSingle.Contains("ENDOFXMLCHECK")
strXMLSingle = getTempFile.ReadLine
If strXMLSingle.Contains("<character") Then
[code]....
I have that so far. It was working great for the names part until I attempted to do the level part, now i get the following error:
System.ArgumentOutOfRangeException: InvalidArgument=Value of '1' is not valid for 'index'.
Also at the line where i use a goto statement to go back to the beginning of the loop, is there any way i can do that without a goto statement? Like a second loop statement or something?
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Apr 27, 2011
I have created player to stream(broadcast) a video from server to clinet in Lan network,my problem is when I send URL of the video to client it take it and add to playlist but when I want to play it message box show's "InvalidArgument value of 0 is not valid for selecteD Index parameter name:selectedIndexSystem.windows. form" I will but the code of client and server but the I have determine the video which will be broacast in client side. [Code]
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Nov 4, 2010
Dim group11_0_count = 0
Dim group11_1_count = 0
Dim group11_2_count = 0
[code].....
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Nov 1, 2011
dim ItemNum As Integer = 0
Dim Selecteditem As ListViewItem = ListView1.SelectedItems(ItemNum)
Select Case ItemNum
[CODE]...
keeps telling me that InvalidArgument=Value of '0' is not valid for 'index'.
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Oct 23, 2009
Getting error filling grid view from reading through data table:
Dim myDataTable As DataTable = myDataSet.Tables("SunTrust")
Dim myRow As DataRow
Dim i As Integer = 1
Try
[code]....
Error:Index was out of range. Must be non-negative and less than the size of the collection.Parameter name: index
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Jan 22, 2009
What im trying to do is send vars to a flash file.The following is my code:
Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
Dim oTitle As New ArrayList
Dim oSub As New ArrayList
Dim oRate As New ArrayList
[code]....
What I'm expecting the output to display is something like "t1=value&s1=value&r1=rate&t2=value&s2=value&r2=rat&t3=value&s3=value&r3=rat" But... i keep getting this exception: index was out of range. must be non negative and less than the size of the collection. Parameter name: INDEX.
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Aug 25, 2011
I have a datagridview, with 3 columns, each containing dropdown filters (in the column header). Of the 3 columns, 2 are working perfectly fine, but whenever I try to filter the 3rd column, it gives me this error: (Also all of the column's have the ColumnType property set to: DataGridViewAutoFilterTextBoxColumn) "Index was out of range. Must be non-negative and less than size of the collection. Parameter name: index." The error points to the part that begins with "If dgv1.Rows(e.RowIndex)..."
Private Sub dgvWPS_CellFormatting(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewCellFormattingEventArgs) Handles dgv1.CellFormatting
If e.ColumnIndex = 1 Then
[code]....
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Sep 6, 2011
I have this code and I getting this error "invalidargument=value of "-1" is not valid for index"
Private Sub lunachange_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles lunachange.Tick
If Listlog.Items.Count <> 0 Then
Dim count As Integer
count = Listlog.Items.Count
[code]....
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May 15, 2009
i'm trying to do a filename compare, sort of fuzzy match.Here's what code i have.First of all i load 2 directory's into 2 listbox's as strings and remove the filepath. Directory1
Code:
TextBox1.Text = FolderBrowserDialog1.SelectedPath
If TextBox1.Text = "" Then
Else
Then when i click the compare button i am trying to pass listbox1 and listbox2 through Distance and return the resulting fuzzy file matches.
Code:
Dim MyObject As New StringSift2
Dim ReturnVal As Single
ReturnVal = MyObject.Distance(ListBox1.SelectedItem, ListBox2.SelectedItem)
[code]....
But i get this error.
Code:
TreeView1.Nodes(lb1).Nodes.Add(ReturnVal.ToString())Specified argument was out of the range of valid values. Parameter name: index
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Dec 9, 2009
I am using Sub to format datagridview but during Form_Load this error occur. There are rows in datasource and dg.row.count is > 0.
.Columns(0).Width = 50 <==== ERROR HERE
.Columns(1).Width = 150
.Columns(2).Width = 80
.Columns(0).HeaderText = "ID"
[code].....
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Apr 13, 2010
i am trying to get the value into the cur_stock where item_id = datagrdiview.curentcell.value.I am lookin out for the solution since couple of days, but couldnt figure it out.Well, m trying to make this work on CellMouse click event
Below is my vb.net code:
Private Sub DataGridView_stockout_CellMouseClick(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewCellMouseEventArgs) Handles DataGridView_stockout.CellMouseClick
Dim i As Integer = Stock_checkDataSet1.Tables(0).Rows.Count - 1
[code]....
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Apr 20, 2012
I am running a VB.NET program and having an error of "Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: index".My code looks like below.
If Status.InvokeRequired Then
Try
Status.Invoke(New delegateoneArg(AddressOf onChangeEvent), ws)[code].....
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Aug 9, 2009
My text file lines look like this
------------------------------------------------------------------------------
AGILENT 3070 FIXTURE WIRING REPORT Sat Mar 07, 2009 06:43:05 PM
/var/hp3070/boards/Celestica/wbf303/fixture/wires
------------------------------------------------------------------------------
Fixture Type : Agilent SimPlate Express
[code]....
but this line Dim Iend As Integer = line.IndexOf(")", Istart) give me error
"Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: startIndex"
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Apr 17, 2009
this is not working?
[Code]...
End WhileI am trying to read from the ": " to the end of the line. I keep getting this error: Index and length must refer to a location within the string. Parameter name: length
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Nov 1, 2011
I have data that goes to another listview on the main form. Anyways, I have a user on a WinXP machine tell me about the following error[code]...
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Feb 5, 2011
I am trying to export the contents of a list view control to the clipboard in VB.NET and windows 7. With VS 2008 I had no problem but when I installed vs 2010 I am getting this error value of `6`is not valid for index.
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Jul 21, 2011
I have this [Code] When I debug the program, I have a listview. I use another button to add items to the listview. When I highlight an item, it's fine; the item starts. The problem is that when I highlight a different item, I get this message,
InvalidArgument=Value of '0' is not valid for 'index'.
Parameter name: index
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Jan 17, 2012
i was making program that updates data in the datagrindview1 in form1 to the form2 but after i click update in form2 im getting an error Index is out of range.[code]
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Aug 24, 2009
[URL] That's a picture of the error. For some reason, it's saying that CurrentPlayer is < 0, but I stepped into the program and it said that CurrentPlayer was 0.
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Aug 26, 2011
Below is my code wherein i am showing a query based on items selected in list box... My problem is that when i m selecting all the items in list box , results are showing but if i m selecting some items, it gives Index out of range error....
vb.net
Private Sub btn_show_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles btn_show.Click
Dim prod_name As String = String.Empty
[code]....
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Apr 23, 2012
i am having trouble putting a value in a textbox. Each time a ticket is sold i put the total price in a textbox, each time a ticket is sold for the same concert it increases by adding its self to the total price. It works at the first sale, but after that it breaks down. here is the code
Private Function DisplayMoneyTaken() As Integer
Dim totalMoney As Integer
'open the database connection
[Code].....
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Apr 18, 2009
I just recently started getting an index out of bounds error on one of my arrays at runtime. I was not having this issue previously. It only seems to happen when several items are added to a listbox.
Here is my declaration and code.
Dim ClientActiveMedProbs(frmmain.lstActiveMedProbs.Items.Count) As String
'store all active medical problem information in an array & build a string
For i As Integer = 0 To frmmain.lstActiveMedProbs.Items.Count - 1
ClientActiveMedProbs(i) = frmmain.lstActiveMedProbs.Items.Item(i).ToString
[Code] .....
The actual error message is:
Index was outside the bounds of the array.
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Dec 21, 2009
I am experiencing a perplexing error ("Index was outside the bounds of array") that did not surface a few days ago WITH THE CODE UNCHANGED.
I was even able to successfully create an executable file a few days ago. It was therefore a shock to be given this error when testing it today.
The snippet is shown below:
Dim GearArray(lines.GetUpperBound(0), 8) As String For x As Integer = 1 To lines.GetUpperBound(0)
Dim parts() As String = lines(x).Split(",")
[Code]....
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Oct 29, 2009
I have a combobox the has12345in it, Does a function, Then changes to the next one
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