I have it set up so that the person hosting an event only has to copy the standardized form from a competitior's post on the forum. The basic format is as follows:
Quote:
Name
ISNAME
Gender
[Code]....
allHorses is a global 2D array for holding each horse as they're added to the roster. Right now I'm trying to get it to add the information for just one horse; once I get it worked out I'll make it dynamic and what not.
I'm trying to split a Yahoo historical stock price csv file, downloaded into a string, by what looks like a space character. I want a new row for each split. The split function works for other characters I see in the string. I suspect the characters may be a non breaking space character but I've been unable to split on them. This is the test csv file that is downloaded into the string: [URL] I'm trying to split the string like this:
[Code]...
I have a string like this
MRP^1^1~MRP|MRP+1^1^1~MRP+1|MRP+2^1^1~MRP+2|MRP+3^1^1~MRP+3|MRP+4^1^1~MRP+4
I want to split it and get the into an array like this in a single line operation.
MRP
MRP+1
MRP+2
MRP+3
MRP+4
My file has the data in this format:
Name,Sal,Address,Location
Mike,"£10,732",xxxxxx,GBR
Bob,"£6,450",xxxxxxx,Fra
Arthur,"£8,320",xxxxx,Spa
James,"£7,423",xxxxxxxxxxxx,IRE
I need to read this data into a string array. In my new file I need to write Name,Sal and Location columns only. Here is my code:
Dim ioReader As New System.IO.Streamreader("C:old.csv")
ioLines="Name,Sal,Location"
Dim ioWriter As New System.IO.StreamWriter("C:
[Code]....
When I am splitting the above data, the sal column values which already contains "," is splitting into 2 cells. I want to keep the sal column value as a single cell by ignoring "," in between numbers.
I have a string that I need to split. I need both parts of the string returned.
I need to split the string after the last alpha character and create a string array from the 2 seperate results.
The string will always varry, but there will always be at least 1 alpha char at the beginning of the string. Here are some examples:
AB1/2
Should return as "AB" and "1/2"
ABC1 1/4
[Code]....
Is there any way that I can use to split every character in a string?
Example:
[code...]
I want to get every character one by one and put it in array.I tried to use Split function but I think there is no delimiter for such kind.
How should I split a string separated by a multi-character delimiter in VB?
i.e. If my string is say - Elephant##Monkey, How do I split it with "##" ?
I am wondering if it is possible to take a string, split it at a certain character and then put the 2 parts in different text boxes.
For example:
String: PCNAME%Message
Textbox1: PCNAME
Textbox2: Message
I'm trying to copy only the first 15 characters(Including spaces) of a string from TextBox1 to Textbox2If the Text in TextBox1 is:abc1234 jklmnopqrst/uvxyThen the Text in TextBox2 should read as:
View 7 RepliesI have a String with 15 places that I would like to split into 3 pieces: (First 3 digits), (next 3 digits), (remaining 9 digits).
How in VB2008 can I do that? Everything I have read so far indicates seperating by a certain character (ie: "," or " ") but no mention of character place. Seems like a simple thing, but after 2 hours of searching I'm still coming up empty
I got a textbox containing eight characters.
I also go 8 seperate textboxs "txtPass0 , txtPass1" etc.
i need to know how i would split each character of the texbox into the eight separate textboxes
I am trying to populate a datagrid from a .txt file. I managed to do it with the split function Split(sr.ReadLine, " ") when I have all the rows identical with only one space, but the problem I have is that the txt file is not delimited and the "spaces" varies some time. This is a sample of my data:
Col1 Col2 Col3
1 Mary Yes
1234 John Yes
999 Leo No
So my question is how to delimit or split the line based when it finds the next character and ignore the empty spaces. This is the code I have.
OpenFileDialog1.Filter = "Text File|*.txt"
OpenFileDialog1.Title = "Open File..."
OpenFileDialog1.FileName = "test"
[code]....
Given an input string like the following:I, Need, Some, Coffee, Before, I, "Fall, Asleep" I need to split this into parts like so:
I
Need
Some
[code]...
Splitting on the comma character alone is easy enough, but how can I handle the quotationmarks? Regular expressions is not on my strong side, and I have been googling for quite a bit without any good results.
This is my Connection String :
cn.Open("Provider=Microsoft.Jet.OLEDB.4.0;" + "Data Source=" & PathtoTextFile & ";" + "Extended Properties=""text;HDR=YES;FMT=Delimited""")
[code].....
How do i use a while loop and MID$ function instead of the split function?
i'm trying to have the input (textbox) compared to a list(array) in a text document
i use this code to split a words:
Dim sWord As String = "Word1~Word2~Word3~Word4"
Dim sResult As String() = sWord.Split(New Char() {"~"c}, StringSplitOptions.RemoveEmptyEntries)
so that a messagebox can show
Word1
Word2
Word3
Word4
but how about if the character to split are 2 or more character instead of "~"? because sometimes "~" is used in some documentation.. i prefer to user "!~!" or "D-:" in splitting words..
I can split the address in the rows as I want it with:Boughton Business ParkBell LaneLittle Chalfont
For x = 0 To datagrid1.Rows.Count - 1
If Not datagrid1.Rows(x).Cells("Business Street").Value Is Nothing Then
Dim rawString As String = Convert.ToString(datagrid1.Rows(x).Cells("Business
[code].....
I am trying to split a string but unable to do so.
Dim fields() as string = line.split(",")
The sample two lines of data is as follows
4,"ABCD",6,"FGHI,JKLM",4515,"4512"
7,"ABCD",7,"FGHI,JKLM,NOV",4515."4513"
actual number of columns are six(06), but it is returing seven (07) from fist line and eight (08) from other line.
I'm trying to get split to work.Here is my code
Public Sub CheckUpdate(ByVal FileURL As String)
Dim instance As WebClient = New WebClient
Dim ApplyTo As String = instance.DownloadString(FileURL)
asd = ApplyTo.Split(",")
End Sub
I use it like this
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
NewUpdate.CheckUpdate("version.txt")
Label1.Text = NewUpdate.asd(0)
End Sub
(yeah I know i use it on local txt for now!)So with asd(0) it reads the whole file. If i check asd(1) I get IndexOutOfRange . So how does Split() work?
Anyone know how to have this split with
start split = <pre class="codebox">
and
end split = </pre>
as the start and end split of a line in listview?[code]...
I am using this bit of
If (proxyListView.Items.Count > 0) Then
Dim ProxyArray As Array = Split(proxyListView.Items.Item(proxyListView.SelectedIndices), ":")
Dim ProxyServer As String = ProxyArray(0)
[code]....
to split a bunch of proxies in a listView, but i'm not sure the proper syntaxt to use at: proxyListView.SelectedIndices, i thought it was SelectedIndex but that doesn't seem to be an option in VS2008?
I had a question regarding the split function used in Visual Basic. As of now I have written a function that brings in a string value. The string value returned will probably look like this "List1;List2; Field1,Field2". My goal is to use the split function for this string to put all the lists in one array and to put the fields in another array.
The problem is between where List2 and Field1 are. I don't want Field1 to be placed in the list array. I'm thinking there might be a way to do this by parsing but I'm not sure. Here is my current code below.
Dim s As String = GetSetting("ReOrderList", properties.SiteId)
Dim affectedLists() As String = s.Split(";")
Dim affectedFields() As String = s.Split(",")
I am working on a project and I need to read information from a streamreader and put into an array and then use the split function to split the the lines read by the commas.
Example: Texas, USA, 123
And I need to split the three into separate arrays and then swap Texas and USA to make it USA, Texas, 123. I am using VB.net language and line.split(",") is not working.
[Code]...
I have an array with about 10 items in it. In order to get the desired functionality I need to append some text to each item in the array in order to sort it properly. Once it is sorted I want to remove the text I added and then just display the second half of each item in the array. The sort works great, but the split function is not worrk.
[Code]...
I am importing a string into my database using the following [code]...
View 9 RepliesHow can I "Split" a string in every 2 character? What is the fastes and easiest way to do it? (every string is 12 characters) exampel: 123456789011 I want it to be 12-34-56-78-90-11.
View 5 RepliesI'm using VB Express 2010.
I have coded a function (let's call it my_boolean_function) on a form. The last line in the function returns the value, i.e.,
Return my_boolean_function.
The function performs correctly, but I get the warning:
Variable 'my_boolean_function' is used before it has been assigned a value. A null reference exception could result at runtime.
A solution to this has been discussed recently on this forum. One contributor suggested something that would mean initializing my_boolean_function to null
However, wanting to dig a bit deeper, I'm asking why does a function return value have to be initialized (to null)? Variables don't have to be yet the warning calls my_boolean_function a variable.
Okay so what I'm trying to do is get the filename from OpenFileDialog/SaveFileDialog, only without the full path, and dump said filename into a variable so I can use it for other things.
Using the Split function, I can get any part of the array between the delimiters (""), but what I'm trying to do is get all the information after the LAST delimiter in the string.
My program uses parameters from the calling program in this format
parameter1/parameter2/parameter3
parameter2 is a datafile path which may sometimes have a space like :
C:Program Files est company
I did this as a work around
Sub Main(ByVal Args() As String)
dim cArgs as string=""
Dim J As Integer
For J = 0 To Args.Length - 1
cArgs = cArgs & " " & Args(J)
Next
And then used the string split function. Is there a proper way to work with spaces?
is it possible for a VB.net function with a return type of integer to return null ?
View 3 Replies