System.Text.RegularExpressions.Regex.Replace(item.Summary.Text, ????, "")
What would I put in the? to get only the domain from a URL: EG [URL] should turn into "Google".
I don't know how the regex works to make it do that. Would it be like "*/*..*" or something?
Here is my code:
Dim StartString As String = "Private Sub"
Dim EndString As String = "End Sub"
Dim SearchString As String = StartString & "(.+)" & EndString
[code].....
I have a string which i need to parse using Regex class of System.Text.RegularExpressions. I need to find if the first 2 characters of the string are either "00" or "07" or "16" or "23".
View 1 RepliesI've been hammering at this over the weekend with no joy - been through page after page of RegEx Language documentation too.It's very easy to negate a match on characters. For example:
Dim MatchString As System.String = "<test0><test0><test1></test1></test0></test0><test0></test0>"
Dim NegationPattern As System.String = "([^<>])"
Dim RepStr As System.String = ""
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I am having an issue where I am using regex.Replace to replace part of a string. The basic idea is that I want to capture the beginning of the string then replace the end of the string with a value from code. For an example pretend I have a string that says "Test Number " followed by number and I want to increment that number. I capture the "Test Number " but when I try to concatenate that capture with the new number it treats the capture ($1) as a literal and replaces the entire string with $1[new number].
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This will output "We are on Test Number 2", as expected. how I can use a variable in the replacement string portion of the Regex.Replace when including a captured group?
I am trying to think of a regex replace to replace double quotes with nothing. Example:
hello("hi there") would become hello(hi there)
"hi" would become hi
"example "3" would become example "3
-edit Maybe an easier way to explain this is, replace all " that do not have a backslash before them.
I'm creating a program in VB.NET to output multiple images. Some images will have the same file name. If there is multiple files with the same name I want to add "_1_" to the end of the file name. If the "_1_" file already exists I want to increment the 1 to be "_2_". If this file already exists I want to continue incrementing the number ultil it doesn't exist. So for example "filename", filename_1_", "filename_2_", etc. Here is the code that I have tried
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I am trying to filter out all unwanted characters from a string. All I want in the string is letters A-Z, numbers 0-9 as well as comma (,) plus (+) and quotes (").I figured how to do the letters and numbers, but the 3 special characters are giving me a problem. I also tried with the Chr(34) equivelant for the " sign, but no luck, as and " or , messes up the way the code is read. Here�s what I have so far, but it only works for A-Z and 0-9:
STR = System.Text.RegularExpressions.Regex.Replace(STR, "[^A-Z, 0-9, Chr(43) ]", "")
I'm using the following VB.net Code to find phone numbers in HTML and make them "clickable":
Regex.Replace(pDisp.Document.Body.innerHTML, "([0-9+ ]{3,6}[s]{1,1}[0123456789 -/]{4,15})", "<a href=http://DIAL/$1>$1</a>")
There appears an issue if the numbers contain white spaces, for example:
089 12233 455
This will be replaced with:
<a href=http://DIAL/089 12233 455>089 12233 455</a>
Is there a way to get
<a href=http://DIAL/08912233455>089 12233 455</a>
instead?
How can I convert [b]xxx[/b] to <strong>xxx</strong> using VB.NET Regex.Replace()?
View 2 RepliesI have a text file like this
4.5 28 Red (T1 ) [1 12.86 53.8] 229111 -28275 198452 -1309 | 11.0 28 Red (2 13.10 04.0) [T1 ] 130611 2948 229111 28275
1.5 28 Blue (T2 ) [1 07.06 59.1] 191611 51225 190456 39339 |
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I am trying to replace text in my xsl file. I have to replace all the http and https. But I can leave any links that start with <a href>
Ie; http://www.google.com has to replaced. But < a href="google.com">google.com</a> has to remain as it is.
I am using regex to find all the http(s) and a hrefs in the text. I am struck here.
My code is,
Dim href As New Regex("(<a.*?>.*?</a>)", RegexOptions.IgnoreCase)
Dim hrefs As New Regex("http(s)?://([w+?.w+])+([a-zA-Z0-9~!@#$\%^&*()_-=+\/?.:;',]*)?", RegexOptions.IgnoreCase)
[Code].....
I am trying to use Regex.Replace to replace my https. But I am unable to write the evaluate function.
My regex.replace replaces all the values with a single value.
Dim ab As String = "aaaextBox1.Text = Regex.Replace(TextBox1.Text, "Dim " + ab + " As String", "aab")That is the code I am using now. Problem is that it's output is only "aab".Is there any way to keep the structure, so it would be "Dim aab As String" instead of only "aab"?
View 2 RepliesI need to use RegEx.Replace to replace only certain named groups in my input string.
So I might have a pattern like:
"^(?<NoReplace>.+)(?<FirstPeriod>(d{2})|CM|RM|PM|CN|RN){1}(?<LastPeriod>(d{2})|CM|RM|PM|CN|RN){1}((#(?<NumberFormat>[#,.+-%0]+))*)$"
Tokens such as CM, RM are being replaced using Regex.Replace with a MatchEvaluator. However, this should only be replacing characters in the FirstPeriod and LastPeriod groups.
Example input:
"FIELDCNS 01CM"
Desired output:
[Code]....
Is this possible or am I best just pulling out the parts I want to replace and re-assembling afterwards?
I'm wanting to search a RTB for all X coordinate values and convert them to SI mm units.
I have two issues: 1. My code is stopping after the first instance of match.success, I'm guessing i'm using nextmatch incorrectly? I have also tried matchcollections with no success.
2. I fear once we get it progressing to the next X value, any multiple X values with the same dimension will be replaced with my replace command, causing the new value to be converted again.
Dim MatchObj As Match = Regex.Match(RichTextBox1.Text, "[Xx](?<X>(d*.{1,1}d{1,4}))(s)*")
If MatchObj.Success Then
[Code]....
I am working in VB.Net and trying to use Regex.Replace to format a string I am using to query Sql. What Im going for is to cut out comments "--". I've found that in most cases the below works for what I need.
string = Regex.Replace(command, "--.*
", "")
and
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I have a long string of HTML code that contains several quotes around objects in the string. I have a Regex.Replace() function to change the "img src" tag, due to the way its stored in a database.
Here is my string: <p><strong><u><font color="#cc0099">RICH TEXT BOLD UNDERLINE. PICTURE TO APPEAR BELOW</font></u></strong></p><p><strong><u><font color="#cc0099"/></u></strong></p><p><img src="/inlineimages/WorkOrder/6/1245981403232.jpg"/> </p><p /><p>W00T!</p>
[Code].....
Notice how the "<font color=" has single quotes around its value, and "<img src=" has single quotes, with a double quote jammed in between?
Also, is there an automated way to go from my initial string, to the "Dim input As String" I created? I had to manually type that out, editing the quotes just to try and make it work.
How can I replace all types of line breaks (CR, LF and CrLf) using Regex?
I´ve tried different combinations of "
" and "
" but none finds them all.
formatedString = System.Text.RegularExpressions.Regex.Replace(text, "
", "[Exp 1]")
The following code does the job but it bugs my that I can´t seem to replace the Line Feed using Regexp.
[Code]....
sTitle = Regex.Replace(sTitle, @"&w+;", "")
View 1 RepliesVB2005: I've been looking at regex for some hours now and cant seem to get my head around the .Replace for my case. I'm looking for two fields and then I want to replace those fields with new values. So my string looks like so:
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What do I put in MyRegexReplace? This is a simple two value replace but Im going to have possibly more so was thinking there has got to be a way to do this but need .
I am trying to perform calculations on Regex substrings. I would like to do something like (see $2)
lblResult.Text = reg_exp.Replace(txtInput.Text, "$1" & "$2" * 0.039 & "$3" & "$4" & "$5")
I can only do this like:
For Each RxMatch In reg_exp.Matches(Me.txtInput.Text)
Me.lblResult.Text = Me.lblResult.Text & _
RxMatch.Groups.Item(1).ToString & _
Math.Round(CDbl(RxMatch.Groups.Item(2).ToString) * 0.03937, 4) & _
[code]....
I was able to extract href value of anchors in an html string. Now, what I want to achieve is extract the href value and replace this value with a new GUID. I need to return both the replaced html string and list of extracted href value and it's corresponding GUID.
My existing code is like:
Dim sPattern As String = "<a[^>]*hrefs*=s*((""(?<URL>[^""]*)"")|('(?<URL>[^']*)')|(?<URL>[^s]* ))"
[code]......
I've used regular expressions in the past. I have an app that parses a .csv file and replaces certain characters (commas). Here's an example..
item1, item2, item3, fruits are apples, oranges, grapes. Squash is a vegetable, not a fruit.
What my app does is search each line between character1 and character18 and replace all "," with "~". How this is done through regular expressions?
To search a pattern containing parenthesis, they must be escaped using backslashes. So to search for (Streetname) you must use (Streetname). If you don't use , whatever is between () will be retained and available for reference through the variables $1, $2 etc... Exemple, in the sentence "It's worth noting that (StreetName) can be anything...(Post), (TreeStump)", $1=StreetName, $2=Post, $3=TreeStump
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For example, I want to match <Tag or <TAG and replace to <tag
Here's what I did(which obviously did not work): tmp = Regex.Replace(tmp, "<(.*)", LCase("$1"))
Just wondering what are some good ways to do this?
I want to select a random space in a string and replace it with a word (%word%) but there is a problem. The position cannot be fixed as i want it to be inserted at a random break. Few things which iam considering :
1)break the string at a space and merge it with the word
2) find a random space and replace it with the word. I like this point and so far all i have is break the selectedtext into string array and then iterate over each line. But i don't know how to find a random string position? Any short and sweet code please?
If (rtfArticle.SelectedText.Length > 0) Then
Dim strArray As String() = rtfArticle.SelectedText.Split(New Char() {ChrW(10)})
For Each str3 As String In strArray
[code]....
Using VB or C#, I am getting a string of variable length from the database. This information is sensitive information that only certain users will be able to see.I have two cases that will use the same logic (I think).scenario 1: replace all characters with xscenario 2: replace all characters with x except the last 4 characters (assume length > 4 - this check is being done).I thought that this would be easiest using Regex.Replace(input, pattern, replacestring). As opposed to a lot of string handling with substrings and forcing a length of 'x's.
View 2 RepliesYes, I've googled. But I must defer to the experts as time to study Regex is not available.
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Can these 3 lines be condensed into one line? If so, how? The purpose is to remove all spaces before and after all occurrences of & in a string.
I have this text:
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How to remove '; (anything):' and replace it with a single comma? I am sure RegEx can do it...
I've been working on this RegEx for the past day or so and I think I have it worked out so that it returns the data I want. First a little background.I have a content editor that users will be able to edit web pages. They can format text, add links, etc.. standard content editor stuff. When they click save, the editor provides the ability to get the content (editor.Content) and put it into a string. What I want to do is get any links (<a> tags) and find out if they are internal or external links and if they are PDF files.
Here is the Expression I've come up with:
<a[^<>]*hrefs*=s*[""'](?<domain>https?://[^/s'""]*)*/?(?<path>/?[^s""]+?)?[[>""']
With this, I am able to separate the domain (if it has one) and the path out. Then, I loop through the matches...
dim matchColl as MatchCollection = Regex.Matches(editorContent, regExString)
For Each m as Match in matchColl
If m.Groups("domain").value <> myInternalDomain and m.Groups("domain").value <> "" then
'this is an external domain... do some stuff
[code]....
My question is this... the parts where I 'do some stuff' to the values, what would be the best way to get that back into my 'editorContent' string? I could probably put the editorContent into a StringBuilder and do a whole bunch of replaces on it, but is that very efficient?So, for example, with the PDF, I want to specify that it open in a new window (target="_blank") and for the external URL, add some javascript code into the onclick attribute.