I have a dictionary(of someType, someOtherType) (the types are immaterial). With a given value, I need to find all the keys that have that value in the dictionary. What I am currently doing is this:
Dim foundList as New List(of someType)
For each key as someType in myDictionary.Keys
If myDictionary(key) = givenValue Then
[code]....
Very easy today, I think. In C#, its:
Dictionary<String, String> dict = new Dictionary<string, string>() { { "", "" } };
But in vb, the following doesn't work.
Public dict As Dictionary(Of String, String) = New Dictionary(Of String, String) (("",""))
I'm pretty sure there's a way to add them at declaration, but I'm not sure how. And yes, I want to add them at declaration, not any other time. :)
I've also tried:
Public dict As Dictionary(Of String, String) = New Dictionary(Of String, String) ({"",""})
And...
Public dict As Dictionary(Of String, String) = New Dictionary(Of String, String) {("","")}
And...
Public dict As Dictionary(Of String, String) = New Dictionary(Of String, String) {{"",""}}
I have the following dictionary:
Dim idQueuedJobs As IDictionary(Of Int32, KeyValuePair(Of String, Int32)) = New Dictionary(Of Int32, KeyValuePair(Of String, Int32))
Why duplicate KeyValue pair? This is because the first Int32 is just a normal index, and the String followed by another Int32 contains systemnames and the priority of the qued job in idQueuedJobs
I want to calculate the total number of systemnames in idQueuedJobs, how can i obtain this count by using the groupby method?
Something like this maybe?
numberOfSystems As Int32 = idQueuedJobs.Values.GroupBy(...)
I have this dictionary..
Dim Rooms As New Dictionary(Of Integer, Of Integer)
Rooms(1) = 101, 102, 109, 110
Rooms(2) = 103, 104, 105
Rooms(3) = 106, 107
I want to know if i can obtain how many keys are in the dictionary For example, in this dictionary i have 3 keys, and if i use Rooms.Count it returns me 9 thats each pair of keys-values, but i want to obtain 3, each diferent value as key.
EDIT: Sintax error P.D: I cant use now because i have to use in a webservice filtered by IP, but VS2010 if i use count on the dictionary, tells me that will contain the number of the keys/value pairs.
I have this dictionary..
Dim Rooms As New Dictionary(Of Integer, Of Integer)
Rooms(1) = 101, 102, 109, 110
Rooms(2) = 103, 104, 105
Rooms(3) = 106, 107
I want to know if I can obtain how many keys are in the dictionary. For example, in this dictionary i have 3 keys, and if I use Rooms.Count it returns me 9 that's each pair of keys-values, but I want to obtain 3, each different value as key. Syntax error. I cant use now because I have to use in a webservice filtered by IP, but VS2010 if I use count on the dictionary, tells me that will contain the number of the keys/value pairs.
I have a dictionary with the keys being integer and the values being string. I was wondering how can I sort the dictionary in DESCENDING order using its keys.
View 6 RepliesI have a case insensitive dictionary in asp.net/vb.net like this:
Dim caseInsensitiveDictionary = New Dictionary(Of String, Single)(StringComparer.OrdinalIgnoreCase)
it holds values like this
[code].....
Is there any reason to favor one of these approaches over the other when inserting into a generic dictionary with the possibility of a key conflict? I'm building an in-memory version of a static collection so in the case of a conflict it doesn't matter whether the old or new value is used.
If Not mySettings.ContainsKey(key) Then
mySettings.Add(key, Value)
End If
[code].....
I have a VB.NET project where I am able to iterate through the keys and values collections of a dictionary object using an index:
MyDictionary.Keys(idx)
MyDictionary.Values(idx)
When this code is taken from the test project and placed into the real project I get the following error:
'System.Collections.Generic.Dictionary(Of Double, String).KeyCollection' cannot be indexed because it has no default property.[code]...
In the line in sub search that says "dtf.Keys(idx) = 0" place your cursor after the right parenthesis and backspace you should get a tooltip that says, "<Extension> ElementAtOrDefault(index as Integer) as Double - index: the zero based element of the index to retrieve.
I have a generic dictonary which is templated in the following manner:
[code...]
If I wanted to omit certain list items against arbitrary keys (that is the items that are in the list contained within the value part of each of the key value pairs making up the dictionary) given some arbitrary condition (lets say omitting list items where a list item contained the string "abc")
I would expect to able to create/project into a new dictionary which would contain entries which contained lists WITHOUT those items whose name contained "abc"
How do I achieve this using a Lambda expression?
I was trying something like this:
[code..]
I have this dictoinary:
Dim chardict As Dictionary(Of Char, Integer) = Nothing
chardict.Add("A", 0)
chardict.Add("B", 1)
I wanted to do the following if statement but I am a bit stuck on the syntax:
if chardict.containskey("A")
'display the value that corrosponds to the letter "A"
'in this case display the character 0
[some code]
end if
There a dictionary object that gets loaded with the following key values:
[Code]...
In most situations, life is good and all the individual key values are needed/unique. But in certain situations, the keys with letters behind them (ie...189a, 189b, 189c) all mean the same thing (ie...189). So I need a way to see if a key value exists (like the containskey method) for only the first part of the key and then return true.
I have a problem detecting whether one of the arrow keys is pressed, all the other keys seem to be detected apart from the arrow keys??? I have set key preview to True........ It detects the arrrow keys BUT ONLY if I have NO other controls on the form??? example..
Me.Text = e.keycode
It works, but then if I add a button for example, it stops.
I want to group items from a linq query under a header, so that for each header I have a list of objects that match the header title. I assumed the solution would be to use ToDictionary to convert the objects, but this allows only one object per "group" (or dictionary key). I assumed I could create the dictionary of type (String, List Of()), but I can't figure out how to write it. As an example I have written a simplified version below.
[Code]...
I'm working on an application using VB 2005,, not VB 2008. Is it possible to still register VB 2005? I've attempted to do so, but I haven't received any keys in email and I also don't see any options in VB to enter a key.
View 3 RepliesI have problems about USB device drivers: I can see the driver correctly installed but application says device is not present.
I solved using Regedit:
in
HKEY_LOCAL_MACHINESYSTEMCurrentControlSetEnumUSB
I have to manually delete the key
HKEY_LOCAL_MACHINESYSTEMCurrentControlSetEnumUSBVid_04d8&Pid_8001
with all subkeys.
I've seen there are several examples managing registry keys using vb, but I can't understand how detect if the key is present and how delete it.
We have localized our application menubar(Ex: Spanish language).The menubar menuitems have few shortcut keys i.e CTRL + N along with the text. The shortcut key is diplaying in some dummy character.We want the menuitem (Ex: New File CTRL+ N) text in local language and CTRL+ N should display as English
cMenuBar.Font = New Font(Configfontname, Configfontsize)
strMenuText = rsManager.GetString("cbmNewFold")
cbmNewFold = New CommandBarButton(ilToolbar20.Images.Item(0), strMenuText, New
[code].....
I have created a class with a function in it. I have a collection of data I want to pass back. I tried an arraylist first. Now I am trying to use a dictionary. My problem is that it creates the dictionary ok, but I am only get the last row of data from my
Function GetWeldAuditInfo(ByVal ResourceId
As
String,
ByVal VendorId
[CODE].........................
I have the following object:
countDictionary As Dictionary(of Category, Dictionary(of Date, Integer))
The Class has a Enumeration Property. For the purposes of demonstration, I'll call it MasterCategory.I have been trying to get out an object that looks like the following:
groupedCountDictionary As Dictionary(of MasterCategory, Dictionary(of Date, Integer)
The best result I could get was:
Lookup(of MasterCategory, Dictionary(of Date, Integer))
From:
countDictionary.ToLookup(Function(o) o.Key.MasterCategory, Function(o) o.Value)
Which results in a IEnumerable (Of Dictionary(of Date, Integer)) for each MasterCategory value.However, I need that IEnumerable of Dictionary flattened to one dictionary with all the integers summed (total counts) for each date. I then tried to use various selects and group bys (from numerous stackoverflow posts) to "flatten" it, but my efforts have fallen short.
Current Code
[Category Class]
- MasterCategory As Enum
- Name As String etc
[code]....
I have created a Dictionary class (MyDictionary for the example). I am currently trying to pass MyDictionary into a function, filter it into a new instance of MyDictionary and pass this new instance into another method. When I am attempting to create the second instance from the filtered first instance of MyDictionary via Lambda Expressions and the ToDictionary Method, I am getting the following error:
Unable to cast object of type 'System.Collections.Generic.Dictionary`2[System.Int32,System.String]' to type 'MyDictionary'. I have simplified the example and recreated it in LINQPad and am getting the same error.
Here's the simplified version of my code:
[Code]...
I use VS2005 and I have just started working with the dictionary in particular the Dictionary.ContainsKey method. At the bottom of the page in the msdn library it says the following in the community content How to make sure that Contains functions properly.
View 3 Repliesjust wondering how i could give my auto typer hot keys, for example they press f1 to start the typer f2 to stop it.
[Code]...
I'm trying to create a shortcut which expands or collapses my treeview using the ctrl+alt+up-arrow or ctrl+alt+down-arrow:
If Keys.ControlKey And e.KeyCode = Keys.Alt And e.KeyCode = Keys.Down Then
mytreeview.ExpandAll()
End If
[code].....
How could I loop through a list of the keys that are available in the 'Keys' enumeration? It seems like it should be something easy to do, but I'm not having any luck finding a collection that I can loop through.
View 6 RepliesI am trying to edit childnodes by name rather then postion since the postion may change can
HTML
Dim xd As New XmlDocument()
xd.Load(path & "BPORES.XML")
[code].....
I have a number like 12000 10^(m-1) < 12000 < 10^(m)I wanted to know how to find m value.I am new in VB.Net programming...
View 1 RepliesI have a group of controls dynamically added to a forms with a name like "OptionID_#" where the "#" is unique number.1st I need to check if these controls are checked/unchecked, but am having a difficult time even finding them to make that first check.I thought controls.find might work, but Controls.Find ("Option ID_" True) dues not seem to find my controls.2nd I need to get the "#" from each of those checked options.I think that Split(conControl.Name, "_") should work to get me two different parts one with the OptionID, and the other with the "#".Still stuck on the first part though of actuall locating the controls I need.
View 9 RepliesI'm trying to find some words within a string so I can use them as headers. The string has different characters involved like letters, numbers, colons and so on. I've used the Mid function but it wouldn't work if the amount of characters in the string changed. The string isn't automatically coded in as it's a text file that's uploaded.There are multiple words I need to find within the string also.
View 9 RepliesHow can I find out the length of particular row of array?
Label1.Text = array.Length
This shows the length of whole array.
e.g. 30
0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
I would like to get the length of 0 row.
0 1 2 3 4 5 6 7 8 9
i want to use a text box of format shown below:Attachment 71883means the text box will at its end show what the user will input in it as you can see the above text boxes in the figure
View 39 Replies