I am currently using visual basic 2005 and i am wondering if it is possilbe to create a line graph using data similar to for example Week 1 = 40, Week 2 = 40, etc....and the Weeks as cross the X axis and the numbers from 1 to 100 on the Y axis....is this possible to implement in visual basic?
I want to picture a line graph based on my array. I can create a graph line with 3 different series, but I don't get my exact chart as in excel. As can be seen from graph in the attachment. It has additional lines. I want just the 3 curved lines, but i don't know why it create other lines. Here is the code I used:
Based on some calculation i will get the (x,y) coordinates of the points to be plotted. I need to draw a line graph based on these points. Which is the best and easiest way to do so?
using vs2008 I am trying to create a line graph using vb in a windows form. I have dragged a chart onto the form, and via the properties window, through the series option have changed the type to the graph that I want, which is line. But all the time the data is displayed as a simple bar chart. How do I remedy this please to get the type of chart that I want.
I have a series of x and y co-ordinates that I would like to plot on a line graph. Can anyone recommend any simple tutorials that would get be started?I have my chart component on the form, I'm guessing that I need to declare a collection of datapoints and loop through the adding each to the graph
I've looked around, I can't find much documentation on Line Graphs using the MS Chart Addon for VB2008.
Whenever I add the "chart" control (which seems to be the only new one in the property browser) a Bar Graph appears. I'd like to create a line graph rather than a bar graph, I don't see an option to change the kind of graph it displays. I'm sure I'm missing something simple, since I've seen people able to create their line graphs almost immediately after installing the control.
How to create a line graph in VB 2005? I will get the data from database and plot a line graph with the information i get from the database and display it out. I know i can use Microsoft chart control but i don't really know how to use that.
This isnt the first time i have posted about a graph, last time i was posting about which way i should do it, now that i have created the graph (by drawing individual lines) i was wondering what the easiest way to actually get data from a SQL database and output it as a line on a graph. here is a picture of what the graph looks like (bottom of the page) [URL]
I am trying to plot a set of data using a function I have defined as an array: Private Sub calculate_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles calculate.Click range(1) = min.Text For i = 2 To 100 [Code] ..... Range(i) I want to be my x values and fee(i) to be the y values. When I try to select range() and fee() as the x and y values for a series, I get an error because they are not of type double.
I would like to know a simple method to create a simple line graph, with a grid and X and Y values... I tried just drawing in a picturebox but that was just annoying and not clear... Is there any simple way to create a little graph with prefixed values on X and Y (graph should just be lines drawns from different Y values, with always the same change of X)
I'd like to do something I thought was simple. All I'd like is to take the data from a connected database, then put those values into a scrolling line graph. Preferabley with 4 lines (taking information from separate tables) on the same graph. I've connected the database and set up a script to populate it with data, but that's as far as I go with graphs.
I've downloaded 'MSChart.exe', 'MSChart_VisalStudioAddOn.exe', ChartFXLiteNet' and others, yet none work. I've also followed a tutorial here on graphs, but it's for visual studio 2005, and I don't have the options required. I'm using Visual Studio 2008 with VB.NET.
I have this code which creates a picturebox during runtime and displays line graph but I always get an error in this line: gr1.DrawImage(pic1.Image, -m_Dx, 0) 'it says Value cannot be null. Parameter name: image
code Public Class Form1 Private Const m_Dx As Single = 1 Dim data As Integer = 1 Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim pic1 As New PictureBox
I have two values those are contiguously One is Time along x-axis and second is the CPU Usage in percentage along Y - Axis. I want to draw a continuous line Chart/graph what ever called.
I have written a simple program which receive data from serial port i.e (temperature) and display on a line graph. but i require accumlate the graph data upto 10 minutes on screen. after that it again accumlate next 10 minutes data.[code]....
I am developing an application with multiple picture boxes, each displaying a line graph. I want to be able to have a label following the mousepointer showing xy coordinates of the point. I also want to allow a user to zoom in on a specific picture box by double clicking on it. The code does what I want as written (changes backcolor so I know double click event fires) except moving the position of the label to follow the mouse pointer.
However if if uncomment the line in the MouseMoved sub: LB.Location = New Point(e.X, e.Y) Then the label moves as desired however the double click event no longer fires.
Public Class Form1 Dim PB As New PictureBox, LB As New Label Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Me.Controls.Add(PB) With PB [Code] .....
i am a newbie to visual basic 2005. i have a excel file contain x value and y value of points.i wan to plot a graph using these few points.after that display the graph in the vb.How can i do that??
If I have an X-Y plot on a graphics and I also create a verticle line on the same graphics. I want to move the line cross the X-Y plot without disturbing this X-Y plot.
Is there a way to move a entire row from one array to another array, without having to move it cell by cell? Assuming that the row length in both arrays is the same.