I am testing for a string if it contains at least n chars in consecutive order: I have this regex but it doesn't seems to work (w1){3,}
View 2 RepliesHow can I count the amount of times a character appears in a string?
The assignment is to create a program with 2 text boxes, label, and a button. We then need to type a phrase into the first text box, and a character in the second. Then click the button and then the label will display the output of how many times the character in the second text box appears in the first.
I have all the above setup except for how to display the amount of times the character appears in the first text box, here's a picture:
How do I count the number of times that a string appears in another string. I know this code:
If odocument.ToString.Contains("window.alert") Then
pops = pops + 1
End If
But that will just see if the desired string contains "window.Alert" once, rather than how many times it does contain it.
this is my first post in this forum! I guess my question is very simple. I just started with VB.net yesterday I want to search through a text string, and then count how many times a word appears. How do i do this? Is there some sort of function that i can use together with a loop of a kind?Something like the inStr(), just something i can use with mulitble appearences!
View 4 Repliescodes like(x is variable)
dim k as string="5b5" & x & "85"
I want to know how many times "5" appears in k,
I am writing a little utility to generate some SQL files. I have a file which is generated from a string array of 400+ elements. It stops writing (without throwing an error) at arround 1000 characters or 380 lines. I am clearly missing something here. Question is what? I've tried (the remed lines of) flush but that seems to have no effect.[[code]...
View 4 RepliesI know it sounds strange but let me it explain. It has a purpose, but really all I'm looking for is the item with the most duplicates.I know it's possible and I've had a few ideas already, though none were successful or practical.What I'm doing here that requires this is creating an intuitive search for clients in a database. You type in a single field and click search. Behind scenes each keyword broken down from the single input field is searched through the table of clients, hitting each column and returning matches. the results are large in numbers, but truly it's the client that appears the same number of times as there are keywords.
View 1 RepliesIn my DataGridView, there is a column for names of machines in the database and I want to count how many machines of each time I have. I have set aside 1 text box with 1 label for each time of machine and in the text box, I want to display how many machines of that type are in the DataGridView?For example, I have 50 records and 30 of those records use machine "80ER" while 12 use "90E" and 8 of them are "PM100". I'd like the 80ER text box to show 30, 90E text box to show 12, and PM100 text box to show 8.
View 7 RepliesIn VB.net I've got the following line that removes all non-alphanumeric chars from a string:
return Regex.Replace(build, "[W]", "")
I now need to extend this to remove non-alphanumeric chars that aren't [] or _. I've changed the line to:
return Regex.Replace(build, "[W[]_]", "")
However I'm pretty sure that this says
replace non-word or [ or ] or _
how do I negate the tests for the [] and _ chars so that it says
replace non-word and not [ and not ] and not _
Some examples:
"[Foo Bar_123456]" => "[FooBar_123456]"
"[Foo Bar_123-456*]" => "[FooBar_123456]"
How to convert or make a cast of a List object typized as a container of chars like
Dim mylist As List(Of Char) = New List(Of Char)(New Char() {"1"c, "2"c})
in a simple array of chars as
Dim mychars() As Char
without make a loop for...
I am making an antivirus program and i am having a problem with my database. how can i only get the hash in this string:
693248:ff807bd383d377f7f8f91ed4aa7677ae:Trojan.Agent-178374
i only want between the two ":"s in this string. how is this possible? and also how do i get the last part on the right of the last ":"?
I'm data binding to a label in a grid and need to knock off the last two chars, not so easy as I thought.I know this is wrong it just shows how I'm coding:
Code:Private Sub TemplateControl_DataBinding_Label(ByVal sender As Object, ByVal e As System.EventArgs)
[code].....
if the last 4 chars in my string(result) are " AND" or the last three chars are " OR" I would like to remove these from the string. So far I have am trying result.trimend and a few other methods but am unsure how to get it working.
View 3 Repliesthis is driving me crazy , I have a string like this dim s as string = "<a href="url.aspx? target=_BLANK>mik, H</a>" I want to remove "mik, h" from the string, how can i do that?
View 4 RepliesI am using TrimEnd to remove certain chars from the end of a string. Initially I thought this would work:
[Code]...
still pretty new to programming in general, but I have most of the basics figured out.I stumbled across this problem today, though. I wanted to try making a simple encoder/decoder. However, I am having trouble getting characters from a string.
I have a list(of char) to separate the individual letters in the message (letterList), and textToConvert is the text that the user types in to be encoded. Here's the section of code my problem exists in:
For i = 0 To textToConvert.Length - 1
letterList(i) = textToConvert.Chars(i)
Next i
Upon running my program, I get an out of range exception for the middle line above. Am I doing something wrong?
i have a VB.NET program that handles the content of documents. The programm handles high volumes of documents as "batch"(>2Million documents;total 1TB volume) Some of this documents may contain control chars or chars like f0e8 [URL]). Is there a easy and especially fast way to remove that chars?(except space,newline,tab,...) If the answer is regex: Has anyone a complete regex for me?
View 2 Repliestell me how to Count Special Characters from input STRING.
View 2 RepliesUsing VB.NET 2003 Asp.Net 1.1. I'm data binding to a label in a grid and need to knock off the last two chars, not so easy as I thought.
I know this is wrong it just shows how I'm coding:
Code:
<div id=CODE>Private Sub TemplateControl_DataBinding_Label(ByVal sender
As Object, ByVal e
As System.EventArgs)
Dim lc As Label
Dim sColumnName As
String = ""
[Code] .....
One problem is what I want to achieve:
I want to have:
$123.00
$15.00
$1,000.00
$123.50
$45.78
My data comes back with 4 places on the end
123.0000
15.0000
45.7800
35.9000
The $ sign I have in my code does work
so I have"
$123.0000
$15.5000
and so on.
I don't believe there will ever be a point where the last two are anything other than zeros.
I want to automatically request the RFID card without having to click the REQUEST button everytime the card touches the RFID reader.
Option Strict Off
Option Explicit On
Imports VB = Microsoft.VisualBasic
[Code].....
I'm trying to make a hash calculator (For testing now)
I know that MD5 is a 1 way(Meaning that there is no decryption for it, yet)
now I was wondering if SHA-1 is a two way. Also, is there any other hashing method that are 2way?
reason is that I want to convert a long string (Lets say 550 chars) into something lower (From 550chars to something lower then 550chars)
I can use a Key, but every possibility will give me bigger length then the actual string.
I'm using the following to strip special characters out of a URL:
Dim urlReg As New Regex("[^dw ]")
inurl = urlReg.Replace(inurl, "")
[code]......
I have text file with a row like this:
[Code]...
have another problem trying to solve again I am trying to add a line into a listbox in this format time item (10), so, e.g. 4:00 Item1(10) So when the next item is added into the listbox and so on, it will look something like this
4:00 Item1 (10)
4:10 Item2 (15)
4:25 Item3 (20)
The time is a Date, and the minutes to add on is extracted with regex. I was able to add the items like above with hardcoding but ain't successful when i try to do it in a shorter way.
[Code]...
i am having a bit of trouble getting a string to print a specific number of times. I am writing a do...loop or a For...next statement where it prints a string ("*") times the counter on the do...loop/for...next but can't quite get it to work.
View 4 Repliesinput = "my mother is a great lady" output = A -3, B - 0, C - 0, D - 1, E - 2
I wanted to count the number of times letter A - E is in the input string.
I am trying to count the number of times a specific character is in a string. The problem is when I run the program the letter doesn't advance from "d" in the string "debugging" and doesn't display the number of time the character "g" is found.
Private Sub Button2_Click(sender As System.Object, e As System.EventArgs) Handles Button2.Click
Dim letterCount As Integer
[code].....
I want to enlarge an image, possibly up to 32 times or 64 times bigger than original dimensions (so that the user can see each pixel) if possible. The following is a simple function that I have to enlarge an image.
Private Function xEnlarge(ByVal Source As Image, ByVal Rate As Double, Optional ByVal Quality As Drawing2D.InterpolationMode = Drawing2D.InterpolationMode.HighQualityBicubic) As Image
[Code].....
I got an app, which receives data via a R232 port, convert it to a string and on the other side I got a database, where the strings are saved. How can I find a way to compare the string with all strings in one database column and get back the another stringform the same row in this database. I never programmed a database
View 1 RepliesWe know that VB string start and end with double quotes " "
So we have to use "" if we want " in VB string.
I wonder if there is a regular expression pattern which will match VB string?.