Dialog Box Pop Up A Second Time After Clicking The OK Button?

Mar 22, 2009

[Code]...

Why does my dialog box pop up a second time after clicking the OK Button? The program continues after clicking the OK Button on the second dialog box.Cliff

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Friend Sub CloseAllForms()
CloseHelpForm(True)
CloseDiagForm()[code].....

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If saved_prac = "" Then
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I am making program that will login to a site, then rate something (Bot), so on login there is no button, but picture and i used this:

For Each logn As HtmlElement In WebBrowser1.Document.GetElementsByTagName("input")
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[Code]....

Its picture like the first button, but i can't click it with same function... Site is [URL]

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I'm brand spanking new and trying to learn VB.net on my own but am doing a horrible job. It seems I can follow basic tutorial instructions and do them correctly but not learn how to do things on my own.

Anyway, I'm trying to do simple stuff first like have a textbox and a button that I click that adds 1 to the value in the textbox and makes the textbox output that value but I can't get it to work for the life of me. I know it's probably something really easy but yeah, I just can't figure it out after scouring the net now for about 45 minutes.[code]...

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[Code]...

I'm trying to make the program click on the "Join" button on that website, and with the code above it does click on the join button, but it seems to ignore any type of javascript involved with the button, therefore giving some type of website error. Is there a better way to click that button so it won't produce any website errors?

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[code].....

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<div align="left" style="padding:2px;">
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If I have the following code: With this code:

<p style="margin:10px 0px" align="center">
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<input class"login-button" type="submit" value="login" name="commit">

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Partial Public Class _Default
Inherits System.Web.UI.Page

[code].....

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I have reiseved this function on an previos thread but I dont know how to use functions. how do I get it to do its thing by for insance clicking a button?

Function GetImageNames(ByVal num As Integer) As String()
Dim folder As String = My.Computer.FileSystem.SpecialDirectories.MyDocuments

[CODE]...

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Private Sub Backgroundworker_ProgressChanged() Handles BackgroundWorker1.ProgressChanged
If Me.BackgroundWorker1.WorkerReportsProgress >= 100 Then

[Code].....

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