Forms :: Showing The Show Dialog Window On Front When Clicking With Mouse?

Mar 25, 2009

My Front end is VB.net 2008.I have a form. In this form, I have a menu control, this menu control has four buttons.On clicking the first three buttons, open the window with Show() event. and the fourth button open the screen with ShowDialog().Now, One by one I am clicking the button , so finally i have now four windows of this application.(Three with Show() and one with ShowDialog())Right?

Now I am minimizing all the windows with the help of Window + D Button.After this, If I use the keyboard(Alt+ Tab) keys. This is opening the showDialog window on top because , Show dialog's TopMost = True.Now I come back to my problem. That's why I cannot use the show/Showdialog overloaded menthod to pass the Me/form-id .Again, I use the keyboard(Alt+ Tab) keys, to minimized all windows. In the taskbar and Startmenu properties ,I have selected the Group Similar Taskbar buttons.This resulted in the heap of my application windows, one on the other.Now i click on one of my application window , and If I click the window other then the Show Dialog opened Window, this is not bringing the show dialog window to topMost.

Note:- There is no parent child window requirement. That's why I can't use the Show/Show Dialog overloaded method to pass the Me/Form-id

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[Code]...

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[Code]...

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My declaration:

[Code]....

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[Code].....

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[Code].....

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[URL] I have tried heslacher's method which is Hi clzanas, you problems had been the result of calling a for each loop inside the events. If you only want for the button you hoover / leave to call the ShowDetails.Open/close, then you can take the code below:

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[code]....

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[Code]...

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[code]....

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