Mouse Hover And Mouse Leave To Open And Close The Window Form

Nov 5, 2009

how to raise the mouse leave and mouse hover events for VB when i place my mouse cursor over the button. 

When my mouse cursor is over the buttons, it will raise the mouse hover event and open the form, then when the mouse leaves the button, it will close the form upon raising the mouse leave event.

but currently, When i excute this two events, the for will open and close very,very fast. so fast that it is like spamming the VB.

So i am wondering how to change the code that i have to excecute the event one time every time the mouse is over the button which is created at run time.

the codes to execute these two events are:

Private Sub Button_MouseLeave(ByVal sender As System.Object, ByVal e As System.EventArgs)
For Each ctl As Control In PictureBox1.Controls

[Code].....

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Mouse Hover And Mouse Leave To Open And Close The Window Form?

Nov 12, 2009

[URL] I have tried heslacher's method which is Hi clzanas, you problems had been the result of calling a for each loop inside the events. If you only want for the button you hoover / leave to call the ShowDetails.Open/close, then you can take the code below:

Private Sub Button_MouseLeave(ByVal sender As System.Object, ByVal e As System.EventArgs)
If TypeOf sender Is Button Then
ShowDetails.Close()

[code]....

But i got the same results as my previous code, resulting in the form opening and closing so fast that it is like spamming the window.

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[Code].....

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In essence when the app starts up I see the client. I can then click the "Hand" button and the Hand Window is shown as well.

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Error:A first chance exception of type 'System.NullReferenceException' occurred in CCG 2.0.exe

The code in the mouse hover event:

Code:
F1.PictureBox2.Image = F2.PictureBox1.Image

Im Almost certain im going about this the wrong way but I cant seem to figure out any other way...

PS.I have attached an image to demonstrate what Im trying to do...

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[code].....

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