This my working method to send a email
Sub emailConfirm()
Dim email As String = txtMail.Text
Dim name As String = txtPrenom.Text + txtNom.Text[code]....
note:I want to send Link contains a unique identifier and verify the unique identifier in the login.aspx.I don't know when to do this...I found nothing interesting on the net ...
I want to send a Link that contains a unique identifier and verify the Guid in an another page named login.aspx So how do I add the link and how do I retrieve the Guid from the login.aspx to compare it to the one I saved in the SQL database...
[code]...
Question: When you have a .NET GUID for inserting in a database, it's structure is like this:
60 bits of timestamp,
48 bits of computer identifier,
14 bits of uniquifier, and
6 bits are fixed,
128 bits total Now I have problem with a GUID, because it's a 128 bit number, and some of the DBs I'm using only support 64 bit numbers. Now I don't want to solve the dilemma by using an autoincrement bigint value, since I want to be able to do offline replication.
[Code]...
how to determine this? I know how to get the "processor ID" etc. but this is apparently not a unique identifier.This is for an intel i7 975. My boss has asked us to make sure that no-one tampers with several parts of a process control computer.
View 6 RepliesAnyone know of a unique identifier I can grab from a Windows PC?I am working on licensing of my app and I want to assign the user a license key and have the key and some unique piece of data from the PC hit a database server of mine and then check credentials before the program runs.I thought about using host name but that can be cloned. I also thought of MAC address but if a computer has a wired and wireless NIC then there are multiple MAC addresses.
View 2 RepliesI have a table in an SQL database bound to a datagridview and am having an issue with understanding what happens when I add a new data row.
My datatable is built in code with the first column created using this sql command...
vb
cmdString = String.Format("CREATE TABLE {0} ({1} INT IDENTITY(1,1) NOT NULL, ", tableName, columnNames(0))
after that there a a number of other columns added to the command to build the table. After the table is created, I fill the datatable and bind the datagridview using this code....
vb
Dim cmdString As String = String.Format("SELECT * FROM {0}", DB_DATALOG_TABLE_NAME)
DataLogAdapter = New SqlDataAdapter(cmdString, dBConnection)
DataLogTable = New DataTable
[Code].....
This is where my understanding is falling. Because I have created the datatable's first column with the NOT NULL key word, an exception throws when I try to update the data adapter because the first column of the data row is empty By creating the table with the first column the IDENTITY key word, doesn't that imply that the database will generate the value for that column? If so, when I add a new datarow, how does the identity column get filled?
I am looking to return a machine specific unique identifier from an EXE. I've tried MAC, hard drive serial and CPU ID, but all contain alpha characters. This makes returning them as an integer difficult - integer seems to be the only type you can return from an EXE.
[Code]....
I have a read-only mssql-view, and I want to map it to nhibernate (using hbm.xml files). The view is a select that joins two tables. For give an abstract-insight, the select is something like this:
SELECT A.Id As A_ID, B.Id As B_ID,
A.AttributeA, B.AttributeB,
FROM A INNER JOIN B ON
A.Id = B.RootID
It's a one-to-many relationship between A and B (B entries are dependant/leafs of A entries).
I'm using nhibernate's hbm.xml files, and I can't make it to work. I'd gladly appreciate if someone can enlight me of the kind of XML that I have to use, I guess that as my view has no ID, I have to create a composite-nhibernate id (wich will be the ids os A and B together) but I couldn't make it to work. Also the view is READ ONLY so I think that should make the solution easier.
In my [2005] application, I use the MacAddr / CpuId / DiskId of the computer to validate my licence using the WMI calls. The problem is we just can't thrust this feature because on a good percentage of the computers this feature is not installed properly or completely disabled.The users are not experienced, they are located in a remote location and I just don't feel like debugging their Windows installation every time they want to try my application.Is there a working alternative that I can use that will always return me a unique identifier for every computer which will always be available on 2000 / XP / Vista systems?
View 8 RepliesASPX:
<a
href="ShowImageVB.aspx?id=<%# Eval("ProdID") %>">
<asp:Image
runat="server"
ID="ImageThumbnail"
AlternateText="Click here to open the real size image"
ImageUrl='<%# "ShowImageVB.aspx?thumbnail=true&ID="& Eval("ProdID").toString%>'
Style="border-width:
0px;"
/>
</a>
Code Behind:
Dim data As DataView = SqlDataSource1.[Select](New DataSourceSelectArguments())
The above code does not seems to work when I change my ProductID to UniqueIdentifier Datatype. This is the error I have ""Input string was not in a correct format."
But when change the ProductID to Int datatype is working fine.
I am using VB .Net to access the eBay API and store all completed orders in a database. This database is then fed into a proprietary shipping system, which can not handle an order number larger than 20 characters. eBay returns an order number like so 230407279314-680141236013 which is too long. The order number is always 12 numbers a hyphen and 12 more numbers. What I need to do, is turn this (the result can be alpha numerical) into a shorter, unique order key to store in my database alongside the true orderId (so that this can be referenced by the shipping software instead of the actual order number). The reason for the 20 character limit is the barcode algorithm used. Is there any way to achieve this in VB .Net 2010? This number can be anything unique, so long as it does not exist already (even a good uniqueid function would work, but I would have to query the database to make sure it isn't taken)
View 2 RepliesI'm using the datagridview. This is the sample data:
[Code]....
How do I parse through the grid to rename the duplicate values in a particular column (in this example it's the l_name field) into such a format?
[Code]....
How generate the unique no. 1,2,3 and so on .... on button click of each new user ..
the code mentioned below is a readwrite coding in vb.net ...
but the problem is it generate the same id for different users on button click event... but i want the no. of times button clicked the new ids will be generated
Protected Sub Button1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim FILE_NAME As String = Server.MapPath("counts.vbi")
[Code].....
Unique constraint - these columns currently doesn't have unique values..?? I have created Unique Constraint with 3 columns. My code works perfectly but once - two users @ same time entered same data and somehow it saved in DB; after that incident. This UniqueConstraint gives me error - These columns currently doesn't have unique values. How can I check if user enters this kind of entry or how can I restrict the Entry?
View 2 RepliesWhat identifier should I use for TAB (e.g. for output to text files)?There are many choices:
vbTab
ControlChars.Tab
A constant (or public member) in my application set to Chr(9)
I am working on a periodic table of elements with buttons for each element-done
next step. textbox + chemistry formulas = grams to mole conversions/ moles to L/ moles to molecules.
The problem I'm having is dimming the chemicals Arsenic(As) and Indium(In). I need to dim these as integers = to their atomic mass G/Moles. But I am not able to Dim them because they are highlighted in blue and the help tip comes up as "keyword is not a valid identifier" is there anyway I can tell VB to not use "In" and "As" how it normally does and use it for integer values?
I instaled vb.net 2005 and when i want to see my old project that has been created by vb.net 2003 (when i click on one of the forms that i created) vb.net 2005 show me this error "
One or more errors encountered while loading the designer. The errors are listed below. Some errors can be fixed by rebuilding your project, while others may require code changes.
Identifier 'Of' is not valid. Hide
In visual studio 2008 when open the design for a VB.Net windows form, i am getting the error " '.ctor' is not a valid identifier". I can see the form designer if I press the "Ignore and Continue" link. All other forms are loading fine.
The callstack with the error message:
at Microsoft.VisualStudio.Shell.Design.Serialization.CodeDom.CodeDomEventBindingService.ValidateMethodName(String methodName)
at
[Code].....
In visual studio 2008 when open the design for a VB.Net windows form, i am getting the error " '.ctor' is not a valid identifier". I can see the form designer if I press the "Ignore and Continue" link.All other forms are loading fine.The callstack with the error message:
at Microsoft.VisualStudio.Shell.Design.Serialization.CodeDom.CodeDomEventBindingService.ValidateMethodName(String methodName)
[code].....
If you try and do the same in a control that inherits Control, you get an error,Keyword is not valid as an identifier. Since Step is a keyword via the For Next statement.
So, how do you achieve the same as the ProgressBar has done in a custom control?
i am new to visual basic and have a question with text boxes and sounds the goal is so that you put a word in a text box and then it plays that sound if it has it as a resource
[Code]...
I have a sp which returns me:
Select 10 as Visits,5 as [Test_Drives],3 as Orders,'£5000' as [Profit_£],4 as Deliveries,'£6000' as [Delivered_Profit_£]
FOR XML PATH('CONTENT'),ROOT('SOMEROOT')
But when I use output as
Dim dr As New SqlDataAdapter(SqlCmd)
Dim tbl As New DataTable
dr.Fill(tbl)
I get an error
Column name 'Profit_£' contains an invalid XML identifier as required by FOR XML; '£'(0x00A3) is the first character at fault.
The problem is that I need have a raw name of column.
when you log in a username and a password a msgbox will show that you are log in, and then when you enter the same username and password, the program will identify that the username and password is log out. no button will be use in here.
View 5 RepliesI have a vb.net dll which I imported in an unmanaged c++ project.I successfully created an object of the class object using:
CComPtr< IWSconnection > pIWSconnection;
pIWSconnection.CoCreateInstance( __uuidof(IWSconnection ) );
Then, when I tried to call a method from the dll:
pIWSconnection.connect(...);
I am getting an error: pIWSconnection undeclared identifier.Why would the object work with 'CoCreateInstance', and not with 'connect'?
When the SQL Server 2005 Wizard is used to create a database project, the following error is issued[code]...
View 3 RepliesI get Keyword is not valid as an identifier error on this line
Private Sub Event _service_GetReleasesForProductCompleted(ByVal Sender As Object, ByVal e As EventArgs)
Where as I want to Raise an event [set up events].
I was wondering if you could assist me with this line of code when am entering the under scroll it says identifier expected.Private Sub btnSearch_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnSearch.Click
Dim record = (From line In IO.File.ReadAllLines("test.txt") _ Let fields = line.Split(","c) _ Select New With { _
.drawer = fields(0), _ .number = fields(1), _ .title = fields(2) _ }).Where(Function(r) r.title = TextBox3.Text).FirstOrDefault
how can i reset my autonumber to 0 again...?
View 6 RepliesPublic Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
End Sub
End Class
[Code] .....
<ClassInterfaceAttribute(ClassInterfaceTypr.AutoDispatch)> _
<DefaultBindingPropertyAttribute("Text")> _
<AssemblyComVisibleAttribute()> _
Public Class
I keep getting told there should be an identifier after Class, but when I apply one I get a host of new errors.
Inherits ListControl
Private Sub ColorComboBox_click()
Select Case Combo1.Text
Case "Blue"
Preview_Box.BackColor = &HC00000
Case "Red"
[Code] .....
Dim method1 = Function(x As Integer, ByRef y As Integer) As Boolean
If x = y Then
Return True
Else
[code]....