How do you split the 2 dimension into 2 variable from a string?
what i have:
RECT (-9895480 4134720, -3298480 9523800)
what i want to appear in the message box:
-9895480 4134720 - x axis
-3298480 9523800 - y axis
how do i split the string into 2 variables with "," as the splitting refernce point? I'm using vb08.
These is the content of my txt file which is saved in D drive in my pc abc,1,2,3..I tried the flowing but it didn't work:[code]I am getting error on this line.. data = line.Split(","c)...it says this line isn't in use anymore or something and that I rather use LineInput but thats asks for filenumber and i don't know what that is. I am sorry but I am a complete beginner. what else can I try? [code]ok that error is gone now but now if I want to add these values to a list box..how can i do that?
View 1 RepliesFor example, I have string variable (MyString) as below.MyString = "First word || second order || third example || fourth item || fifth stuff"
There are separator "||" at MyString variable. I want MyString variable is spited based on separator "||"and stored it into new array variable.
Could you advise me the most efficient code to do this job in VB?
Using VB.NET .NetFramwork 3.5. This fails and strikes me as odd. Is this correct behavior:
Public Sub TestForEach()
For index As Integer = 1 To 10
Dim z As Integer
Assert.AreEqual(0, z)
z = index
Next
End Sub
I would expect z to always equal 0 as I thought the dim-ing of an integer would set the value to 0. If you run this. It fails at the second loop. For some reason z retains it's value of 1. I know I can manually initialize z to = 0, but I wanted to know if this is a bug or expected behavior.
is it possible to dynamically dimension a variable?in my case, i have a chart that has a varying number of series on it depending on the data extracted and in order to use those series, i have to dimension them manually before adding points to them, IE:
Dim series1 as New Series()
Dim series2 as New Series()
etc
etc
my series data is contained in a datatable, so i'll know the count required, but it will change at runtime, so obviously doing something like this won't work, but explains what i'm trying to do:
dim recordcount as integer = datatable.rows.count
for i = 1 to recordcount
dim "series"+recordcount.tostring as new series()
next
I hope get a string key based the content of string[] such as aDIM, I use the following do that, but I think it's not good way, could you give me a better way?
[Code]...
I am trying to split a long string based on an array of words. For Example:Words: trying, long, array Sentence: "I am trying to split a long string based on an array of words."Resulting string array:Multiple instances of the same word is likely, so having two instances of trying cause a split, or of array, will probably happen.
View 5 RepliesI have searched for a simple way to search a string array. MS gives a clean simple solution for a one dimesion string.
Dim StrArray() As String = {"ABCDEFG", "HIJKLMNOP"}
Dim FindThisString As String = "JKL"
For Each Str As String In StrArray
[code]......
my code is :
[Code]...
The error is Value of type '1-dimensional array of string' cannot be converted to 'String'.
I'm looking for a way to search a string variable for two words and copy the text in between them into another variable. This needs to be done as many times as the match occurs.
View 3 RepliesI have an one dimension string array ar1
ar1(0) ="One;is;a;dog;"
ar2(1)="Two;is;a;cat;"
...
I want to convert ar1 into ar2 which is a two dimension array
ar2(0)(0)="One";ar2(0)(1)="is";ar2(0)(2)="a";ar2(0)(3)="dog"
etc
I'm trying to split a Yahoo historical stock price csv file, downloaded into a string, by what looks like a space character. I want a new row for each split. The split function works for other characters I see in the string. I suspect the characters may be a non breaking space character but I've been unable to split on them. This is the test csv file that is downloaded into the string: [URL] I'm trying to split the string like this:
[Code]...
Is there a way to use the string.split command to get a section of a string without using an intermediary array?for example, if my string is "1 2" and I want to get the "2" part using string.split(" "), is there a way to avoid creating a new array, and just get the bit of the string I want in a single line?
View 4 RepliesAfter having some trouble in my own code using String.Split and the Split(String(), Int32, StringSplitOptions) overload, I decided to look to the MSDN.I copied the entire VB.NET code example from this link: url...I placed it in a new class, and received the following errors (same errors as my own code example):[code]Why can my code not recogognize the string() parameter overloads to String.Split? Remember, i took the code from the MSDN link above, copied and pasted and it still did not work.I am counting on using the string() instead of char() overloads shown here: url...
View 15 RepliesBackground: I have a winForm app that registers a user in the database based on the information provided, auto-generates a random password and username, and e-mails the user a link to take an application based on the marketing company selected. Problem: hen the user clicks "Send Invitation" with data inputted iton all fields except the bundles listbox in debug, the NullReferenceException Error is thrown highlighting the line: Dim MCShort As String = Trim(splitMC(0))How do I fix this issue Here's a screenshot of the web app: Here's the code of the Send_Button_Click method off default.asx.vb:
Private Sub Send_Button_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Send_Button.Click
'TODO Add code to validate that all selections that are reaquired are met.
[code].....
I have some code that splits a session into strings by a -
My session looks something like this 123-456-789- and I split it like this
Dim MyString As String() = Session("MySession").Split("-"C)
And i've got a some code like this
Dim x as Integer
For x = 0 to MyString - 1
Response.write("Ref: " & MyString(x) & "<br>")
Next
This writes the code like this
Ref: 123
Ref: 456
Ref: 789
Ref:
So it's adding an extra Ref where it shouldn't be because there is no data after the last -
Is there a way to stop this adding in the extra one?
I have a long string like this
dim LongString as String = "123abc456def789ghi"
And I want to split it into a string array. Each element of the array should be in 3 characters length[code]...
I have a string which I've split into an array. I need to change a value in the array and join the string together. However I cannot set the value of the array variable as it's read only.Is there any way to do this without creating another array?
Dim LineOfText As StringDim aryTextFile As String[code...]
I want to take a string from a text box and split each letter of the string into an array. Then, I want to take the first item in the array(the first letter of the string)and capitalize it. Once I've done all that, I want to combine the array and convert it back to the original string it was, except I want the first letter to be capitalized(I've already placed this into a variable.)
Here's what I've come up with so far:
[Code].....
how to combine the array back to a string except I replace the first letter of the original string with the "firstLetter" variable I created.
I have a listbox that contains 10 records as the follow:
1 + 1 = 2
1 - 1 = 0
2 / 1 = 1
[code].....
I want split a gridview row on an html tag. How can i do this preferably in C#??.row.cells[1].Text.Split("htmltag")
View 7 Repliesi was unable to implement a multiline label or a transparent multiline textbox. So ive come up with the long way.I have paragraph of words (approx 100) that changes on a click. i want to split the paragraph into blocks of 20 and create 5 strings.
' Split string based on spaces
Dim split As String() = movieDetails(0).movieInformation.ToString.Split(" ")
i dont know how to put them into array. I keep getting this error " variable has been used before it has been assigned a value"
How would I split the following string?
test, 7535, '1,830,000', '5,000,000'
The result should be
test
7535
'1,830,000'
'5,000,000'
I try:
Dim S() as string = mystring.split(",")
But I get,
test
7535
'1
[code]....
have this stringmain
String="/MyApp/ViewPage.aspx?userId=admin&password=1&id=975"and i have two sting variables1)strTempUsername2)strTempPasswordin these variables i want to store userId and password values from mainStringso for this requirement how i wirte logic in codeHere
[code].....
I'm using vb.net 2.0. Here is my input string "When the string needs to be splited to fit on the lines, it is tried to split the string at a gab between words." I want to split string for the given word "to fit on the lines" and i gave like this code:
Dim string1 As
String() = strBody.Split("to fit on the lines")
But the output came like this :
string1 {Length=16} String()
(0) "When " String
(1) "he s" String
(2) "ring needs " String
[code]....
I want is to split the string as :
string1(0)="When the string needs to be splited " string1(1)=", it is tried to split the string at a gab between words."
i have one long field, a string. it looks like it was once xml. i am wondering if there is some way to split this field into the correct parts.
<Record><DocumentRequestID>7360095</DocumentRequestID><FirstName>ETHEL</FirstName><LastName>DANIELS</LastName><DateOfBirth>1927-04-21T00:00:00</DateOfBirth>
Say I have something like this
Dim Level1 as Integer = 83
Dim Goal as String
Goal = InputBox(" What level is your goal?")
[code].....
I have a filename in a string. I want to split the given string into 2 (1 is filename without extension, 2 is only extension) strings. Then add _dev to the end of first string and concatenate with 2nd one.
ex: Dim name as string="abc.txt"
Dim finalName as string
The finalName should be like this "abc_dev.txt"
Need to take a string in vb and split it. Also need to look through the two returned values and return the value which contains [URL]. Pipelines are the delimiter.
txtEmailFrom.Text = "john@huno.com|james@domain1.com"
Dim brokened() As String
brokened = Split(txtEmailFrom.Text, "|")
I'm having some issues using the String.Split method, Example here:
Dim tstString As String = "something here -:- urlhere"
Dim newtstString = tstString.Split(" -:- ")
MessageBox.Show(newtstString(0))
MessageBox.Show(newtstString(1))
The above, in PHP (My native language!) would return something here AND urlhere in the message boxes.
In VB.NET I get:
AND
: (colon)
Does the String.Split only work with standard characters?