How to convert the textbox.text to a number with decimal points. Once the subroutine have been process, the numbers will be dispalyed on the textbox or label in a format with two decimal numbers.
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What is the cleanest, most readable way to String.Format a decimal with the following criteria
start with a sign symbol (+ or -)
a fixed number of fraction digits
no decimal separator
right aligned
pre-padded with "0"'s
format number to hower many number on left of decimal and 1 decimal without rounding
View 2 RepliesI want to convert numbers from 0 to 15 like that
[Code]...
Problem is that when we convert 2 to binary number it gives only 10 in binary, but i want to convert 2 to 4 bit binary number 0010.
I am calling the function below from an Excel spreadsheet and the conversion from hex to decimal using the VAL function in the "manufacturer" variable below is coming back with a negative value. The VBA edition is 6.5.
Public Function decMEID(ByVal sKey As String) As String
Dim manufacturer As String
Dim serial As String
[code].....
1) One Decimal Varibale stores a decimal value
2) The value must be converted in string ( some time the comma is used as decimalplaceholder some time the dot)
3) the user modifies the value
4) i need to riconvert the string back in decimal
how can i do this
so:
Variable 123.34D ----> textBox 123,34 or 123.34 -----> variable 123.34D
im having trouble understanding this question for a homework assignment. I need to write the PSEUDOCODE for the following scenario, but i got no idea about how to convert a hexadecimal number to a decimal number..You are required to input a two digit hexadecimal number eg. 3f (digits can be entered separately) and calculate the equivalent decimal number. (note the decimal number will be between 0 and 255) . output the decimal number
View 1 RepliesTo allow a textbox to contain "15" or 15.5" as numbers nothing else...I figured that ^\d+$ works for numbers but can't get decimals to work also?
View 1 RepliesI have a TextBox in a Windows Forms application in VB 2008 (.NET 3.5) where a user can key an estimate amount. I am allowing them to key dollars and cents, and I want to round to the nearest dollar. The original code had the rounding down when the data was written back to a table, and that worked fine - I have this code in a "Save" routine that fires when the user moves to a different screen or record:
Dim est As Decimal : Decimal.TryParse(txtEstimateAmount.Text.Trim, est)
Dim estimatedAmount As Integer = Math.Round(est)
I decided that it might be nice to actually do the rounding as soon as they leave the field instead, so they're not surprised when they reload the screen and find that 1822.60 is now 1823. So I took the exact same code and added it to the TextBox.Leave event handler. And the weirdest thing happened: instead of the variable est being populated with 1822.60 after the parse, it gets set to -1! What the...?
Debugging the handler shows that the value goes into the parser correctly, and if I do the parsing manually via the Immediate window, it parses correctly, but when I let the code do it, it invariably gets set to -1. What's even weirder is that any number gets parsed as -1, not just decimals, and any non-number gets parsed as 0 (which is correct).
Has anybody else ever run into this before? I tried moving the code to the TextBox.LostFocus event instead, but with the same results. I have no idea what in the heck is going on, and obviously there are workarounds galore for this, but it just makes no sense whatsoever.
EDIT: Here's the full event handler (current behavior for which is to put -1 in the TextBox):
Private Sub txtEstimateAmount_Leave(ByVal sender As Object, ByVal e As System.EventArgs) Handles txtEstimateAmount.Leave
' Take any dollars-and-cents amount and round to the nearest dollar
Dim est As Decimal
[code]....
How can I only add the decimal part of a number to another one?
example: if a number is A = 10.25
Then X = 30
Y = X + 0.25 (Here it added 0.25 which the decimal only NOT 10.25)
Another example, If X = 16.35, A = 102.001
Y = 16.351
I am attempting to take the decimal places of a given input, round it so there are only two decimal places, then change it to a whole number. So far I have been able to remove the integer part of the number, leaving only the decimal, but the other procedures are eluding me. Here's what I have so far: (VB 2008)
Private Function DecimalNumber(ByVal number As Double) As Double
Dim Input As Double
Dim SubtractNumber As Decimal
[Code]....
That code returns the decimal part of the input just fine, and I thought maybe multiplying it by 10 would work....but obviously you run into problems when there is more than one decimal place.
I have class representing a unit of measure with a Decimal as the numeric. Just to simplify things for this example, let's say I'm representing centimeters. I'd like to implement a ToString() method for this class. The thing is, if the numeric value is a whole number I'd like to just display the decimal as an integer. Otherwise, I'd like to keep it as a decimal. So, for example, 10.5D centimeters would display as "10.5cm", but 7.0D centimeters should display as "7cm". I'd like this to be fast and simple to read. I have a working solution, but it seems like there should be a better way.Here's a contrived example showing my first crack at it:
Public Property Units As String = "cm"
Public Property NumericValue As Decimal = 10.5D
Public Overrides Function ToString()
[code].....
How to convert a whole number into decimal..For example 70 to .70 because there are some price in my system that needed to be calculated by grams for example $5 per grams... I am saving the price in my database as an integer..
View 2 Repliesi am using that code i have one datagridview and datagridview cell 3 value is 7
Dim n As Integer
For a = 0 To DataGridView1.Rows.Count - 1
If DataGridView1.Rows(a).Cells(0).Value = True Then
n = DataGridView1.Rows(a).Cells(3).Value
[code]....
the above code answer is 4 but i want the answer like that 3.5
How do I check how many decimal places does a number have in VB.net?
For example: Inside a cicle I have an if statement and on that statement I want to check if a number has 4 decimal places (8.9659)
How can I get the number of the decimal place, example 1.30 then it should give 2, for 5.0101 should give 4. I'm now doing that:
[Code]...
I have a problem regarding the number and want the number become from this: RM 2 to be like this: RM 2.00 [code]...
View 3 RepliesI have a field in datatable .If 1000 is the value in it, i want to display it as 1000.00.Then if user changes to 1000.50 it should display as it is.Is there anyway to do this?
View 4 Repliescorrect syntax to format decimals. I want 2 decimal places even if the result is an even number i.e. I want 40 to show as 40.00 and 40.6666667 to show as 40.67.
View 8 RepliesI want to know how to convert a percentage rate such as 4.5% into a decimal number in your code editor in V 2008.For example, the user input is 4.5%. Is there any function available to convert is to 0.045?
View 4 RepliesI'm using access as my database and vb .net 2008.My problem is i change a field into 2 ecimal places and when i debug my program why my data in the datagridview not a 2 decimalExample : in access TotalCost = 200.00in vb form datagridview TotalCost = 200
View 1 Replieshow do you detect how many decimals a decimal number has
View 10 RepliesI have two forms. the first form saves a decimal number and could also retrieve it. the second form just retrieves the number from the database. on the first form, i successfully retrieved the number with the decimals included. but on the second form, the number retrieved is displayed as a rounded up whole number. i tried to copy the codes of the first form but it still displays the rounded up number.
View 11 RepliesI have an internal process that requires data in a very specific format. Nothing I can do about that. So in my VB.NET program I am trying to output a number with a terminating decimal and nothing after it. I tried
swOut.WriteLine("{0,10:###0.}", var)
But the output is a whole number
886
913
941
[Code].....
Way to find out the numbers after the decimal point of the double?All i need to do is to find out if the number ends in 0 like 1.0 or 10.0 or 323.0 ?
View 6 RepliesI am trying to think of a possible way to insert a colon and decimal point to a part of a number. I am making a Rubik's Cube timer, and I converted the times to milliseconds so I can calculate the average of 5 with that. I averaged the milliseconds, but now I need to convert that into minutes, seconds, and milliseconds. Does anyone have any idea on how I would go about this?
View 2 Repliesive done a bmi calculator bbut the end result has 4 or 5 decimal places when i only need one. how do i limit the number of decimal places
View 3 Replieswant to return decimal number but because of "UBound" its keep displaying as integer how can i display decimal numbers?Public Class frmPrintbooks
Private Sub frmPrintbooks_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
For x = 0.0 To UBound(Form1.printBookName)
lstPrintbooks.Items.Add(Form1.printBookName(x) & " " & String.Format("{0:C}", Form1.printBookPrice(x)))
Next x
End Sub
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How do I enable a user to set the number of decimal places in my code?essentially I have multiple variables in my code ,different kinds of pressure for example and with each instance I declare the following;
txt_Alt_Press.Text = Strat_Press.ToString(Press_DP)
I then set Press_DP in a module, declared as a public variable,
Public Press_DP As String = ("F1")
So what I want to do is make the "F1" bit a variable in itself, so then the user can set the number of decimal places with a numeric up-down control.
how i can format a number to only show decimal places if needed?For instance...
string.format("{0:SomeFormat}", 26.9) = "26.9"
and...
string.format("{0:SomeFormat}", 26.0) = "26" 'Drop decimal for whole numbers
