DateAdd Function - Arithmetic Operation Resulted In Overflow
Jun 15, 2010
I am using the following code to add some value to a date:
Dim strdate As Date
Dim numinterval As Double
numinterval = 149548.720386359
strdate = DateAdd(DateInterval.day, numinterval, #1/1/1601#)
MsgBox(strdate)
The value numinterval is the number of days passed since 1/1/1601 (this is how date is counted for things like 'last logon time', 'last bad password' in Active directory). I do some calculation and get that numinterval value in days.. But since I want it to return the time more accurately, I tried first multiplying numinterval by 1400 for number of minutes.. And I changed the interval as dateinterval.minute... That worked fine!
But, when I tried again by multiplying it further by 60, to get the time accurately in seconds and changed the interval to dateinterval.second it throws the following exception:
Arithmetic operation resulted in an overflow
I changed the type of numinterval into long, but the same problem..
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Apr 6, 2011
Ok so in my code i need a ****ing long as equation to draw a certain paint for getting the distance of a particle using the terminal velocity equation. which looks like this...
var.vt = ((2 * var.m * var.g) / ((var.fluiddensityp) * var.apaos * var.dragcoef)) ^ (1 / 2)
then pop that in here to get terminal velocity at a given time...
= var.xvalgraph1 * ((var.g * var.fluiddensityp * var.dragcoef * apaos) / (2 * var.m)) ^ (1 / 2)
terminalvelocityovertime = vt * Tanh(tanhx)
then as I'm drawing a graph i calculate the previous coordinate and join then with a line.so i need a value called previous which is where ever there is a var.xvalgraph1 it minuses what ever time increments have been set so alll var.xvalgraph1 turn to (var.xvalgraph1 - var.timeperpixel)
ok thats all fine this is where the equations get too much and i don't work
[Code]...
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Feb 8, 2010
Why a variable defined as a long will not accept this number (2,148,532,224) with out throwing an exception of "Arithmetic operation resulted in an overflow." Looking at documentation it should be able to handle a value up to 9,223,372,036,854,775,807.
My code does some simple calculations and then tries to store the value in the variable.
Dim mdblTotalFileSize as Long = GetImageSizeBlocks * GetBlockSize
The value for GetImageSizeBlocks is 1049088 and the value of GetBlockSize is 2048 which equals 2148532224
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Apr 21, 2011
I am new to programming with visual basic version 10 (I hope this is the correct forum).
I am using the following line in my program[code]...
I am getting the message that an arithmetic operation resulting in a math overflow.
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Sep 28, 2010
For iLoop As Integer = 0 To length
Dim byte1 As Byte = Fs1.ReadByte()
Dim byte2 As Byte = Fs2.ReadByte()
Dim offset As Byte = Fs1.Position()
If byte1 <> byte2 Then
OffSetFS.WriteByte(offset)
OutPutFS.WriteByte(byte2)
End If
Next
Arithmetic operation resulted in an overflow.
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Sep 28, 2010
Dim f1 As String = "File1Path"
Dim f2 As String = "File2Path"
Dim Fs1 As New FileStream(f1, FileMode.Open)
Dim Fs2 As New FileStream(f2, FileMode.Open)
Dim f1length As Integer = Fs1.Length - 1
Dim f2length As Integer = Fs2.Length - 1
[Code]...
Application.StartupPath & "PatchData.dat": PatchData.dat isn't created yet, but my program makes PatchData.dat, and PatchData.dat is ~8KB when my program gives me this error.
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Jan 21, 2011
In this call to method SetVolume, Volume = 2055786000 and size = 93552000. Volume is an Integer property, and size is also Integer, as you can see.The class is a partial class of a dbml entity class, however this Volume property is NOT a column in the database, it exist only in the partial class, as a "business object property".
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Aug 16, 2010
I am having a problem with a download form I am trying to make. This downloader works fine for small files but once it gets to, 20,969KB it errors, "Arithmetic operation resulted in an overflow". I downloaded this code about a year ago and used it in all my applications for my auto updater I have coded for my applications....
Downlaoder code...
Imports System.Net
Imports System.IO
Imports test_app.dloadinfo
Public Class Dloader
Dim whereToSave As String 'Where the program save the file
[Code] .....
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Nov 2, 2010
I have upgraded vb6 to vb.net and getting the Arithmetic operation resulted in an overflow Error below:
[Code]...
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Dec 16, 2009
When I Run my app, I get a pop up box saying this 'Arithmetic operation resulted in an overflow'. Here is the code;
[Code]...
how to fix this issue?
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Jun 8, 2009
I am having issues with a dictionary object I'm trying to use.
I have this code:
CODE:
Every time I run it, I get this error: Arithmetic operation resulted in an overflow
I am adding to the dictionary like this:
CODE:
Is there anything I am doing wrong?
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May 1, 2012
If dgCell = "Delete" Then
'make sure user wants to delete the selected record.
If MsgBox("Are you sure you want to delete this image?", MsgBoxStyle.OkCancel,
[Code]....
Error is thrown at "cmdDelete.ExecuteNonQuery()". Sql query still deletes the record. I have run query against the database itself and I get no error. I am using an as400 db and vb.net 2008. I'm not sure if this is problem with the database or vb. I get this error when I run the delete above, also when I run an insert or an update.
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Feb 24, 2011
I'm making a downloader program in Visual Basic 2010, and it calculates the current download speed, the approximate time left and all that good stuff.But when I download certain files, the program decides to f*** up.The program stays still for a bit, and nothing happens when i click download button, but then all out the sudden the download starts like normal but an error message pops up and it says:
"Arithmetic operation resulted in an overflow"As I previously said, this error message only pops up on certain files.Then I started to do some "error-investigating" xD, and i found out that this line caused the error msg:
dlspeed = e.BytesReceived / SW.ElapsedMilliseconds
remainingtime = ((e.TotalBytesToReceive - e.BytesReceived) / dlspeed) / 1000
lbl_dlspeed.Text = Math.Round(dlspeed) & " kB/s"
That code is written in the web_downloadprogresschanged class.And SW is a stopwatch.I mean, it still downloads fully and such, but it looks ugly when an error message pops up even though it works.
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Mar 19, 2010
I have this script:[code...]
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Feb 17, 2012
I am getting the following error: Quote: Arithmetic operation resulted in an overflow. Here is my Public Shared Function AESFileEncrypt(inputFilename As String, outputFilename As String) As Boolean
[Code]...
Dim InputFileData(CType(InputFileStream.Length, Integer)) As Byte ' - error line This happens on a file that is 2.4 gigs. I presume this is because the byte array cannot be declared that big. How can I get this to work?
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Dec 4, 2011
I have been working on a Amortization Schedule after getting it almost completely done I saw that my Monthly interest Rate was incorrect so I re-wrote the equation I was using to get it then I got the error "Arithmetic operation resulted in an overflow."[code]...
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May 12, 2012
I attempt to prepare printing document by using WinAPI instead of (System.Drawing.Printing.PrintDocument) because Graphic.DrawString does not render Khmer Unicode properly. Only TextRendering.DrawText renders it properly. I believe Graphic is GDI+ wrapper and TextRendering.DrawText is using GDI. Furthermore, PrintDocument does not work with TextRendering.DrawText.
[Code]...
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Apr 19, 2012
I've never seen this error before; and apparently (According to DIC) the number would have be bigger than -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807, to this this exception (I'm using an Integer, but I've tried Int64, and the same thing happens).
This is where the exception is being thrown:
Dim localPort As Integer = (tcpRow__1.localPort1 << 8) + (tcpRow__1.localPort2) + (tcpRow__1.localPort3 << 24) + (tcpRow__1.localPort4 << 16)
Full Code (Method)
[CODE]...
I highly doubt that that the integer that is being parsed back is greater than, either of those numbers listed above. I've tried using Int64, and even removing the << operator, but it's still throwing this exception.
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Jan 7, 2010
I get a "Runtime Error 6: Overflow" when I multiply some variables in VB6
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Jun 10, 2009
why this code would produce an Arithmetic overflow statement? I don't see any reasons why, and the error produces no line number
Try
Me.CampaignsTableAdapter.Fill(Me.EmailPromoTimeSaverDataSet.Campaigns)
mainFormURLTextBox.Text = "http://google.com"
[Code].....
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Aug 26, 2011
I have a DateTime Picker that I have set Format to "Custom" and CustomFormat to "dd/MM/yyyy HH:mm"
When the user changes the date time it all works fine and update the table no problem.
If the user does not change the date time I get the error[code]...
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Jan 28, 2009
I am using a DataReader to get data from a database. For some reason, I keep getting this error "Arithmetic operation resulted in an overflow." The error occurs on the line: courseID = (dr.Item("courseId"))
[Code]...
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Feb 22, 2011
If DateDiff(DateInterval.Day, moDoBooking.m_CurrentDay, moDoBooking.m_BaseDay) _
> DateDiff(DateInterval.Day, DateAdd(DateInterval.Day, _
Convert.ToDouble(moDoBooking.oBooking.oFacility.ADAYS), moDoBooking.m_BaseDay), _
moDoBooking.m_BaseDay) Then
This condition won't satisfy with these values:
moDobooking.m_CurrentDay = 2/3/2011
moDobooking.m_BaseDay = 22/02/2011
moDoBooking.oBooking.oFacility.ADAYS = 1
You might say this is dead-easy but honestly it's late here and my head is not working at all! Could AnyOne tell me why is that?
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Oct 14, 2009
I would like to calculate a new date simply by using the build-in dateadd function, but take into account that only weekdays should be counted (or 'business days' so to speak).I have come up with this simple algorithm, which does not bother about holidays and such. I have tested this with some simple dates, but would like some input if this can be done in better ways.This sample assumes a week with 5 business days, monday-friday, where first day of the week is monday. Dateformatting used here is d-m-yyyy, the sample calculates with a startdate of october 1, 2009.
Here is the simple form:
Dim d_StartDate As DateTime = "1-10-2009"
Dim i_NumberOfDays As Integer = 12
Dim i_CalculateNumberOfDays As Integer
[code]....
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Sep 16, 2010
I am trying to compute time off, I have a datetimepicker which allow user to select a day he wishes to start leave and a textbox to specify no of days applying for.Now I wand to use dateadd function to calculate resumption date excluding Weekends.
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Feb 5, 2010
I must convert string data from a CNC that is arithmetic expression to a number that I can use in a VB application that I wrote. The following is what I get out of the cnc. [18722*65536+19377]/67108864. I need to evaluate this expression in my VB ap. The format of the string is not always the same as what I have illustrated.
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Apr 26, 2009
This is probably a stupid question, but how do you make a function which takes a number then does an operation to it again and again until it gets a vlue which it already has seen, when it returns all of its values? I have this function:
Private Function fractal(d as string) As double
Fractal = Val(D) * (Val(D) - 1)
Fractal = FormatNumber (Fractal, 2)
[code].....
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Mar 27, 2010
i create a thread that load a function, in this function i need to read from txtbox into the same form and during the function write into another textbox the call to function is done in this way Dim t As Thread t = New Thread(AddressOf Me.myFunction) t.Start() from myFunction i read info in this way myInfo = textbox1.text and i write into textbox during the execution of myFunction in this way textInfo.text = myInfo but in debug time i have an error of crossthread.. how can i solve this problem??
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Nov 10, 2010
The result will be '2010' for this query select year(getdate())
How do I get same result as Linq?select year(dateadd(yy,-1,getdate())), year(getdate()),
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Feb 25, 2011
Is there a way to add milliseconds in dateadd? It is not in the DateInterval enum. I created a class so my program knows what the real time is, based off the sql server. This way, we don't have to worry about people's computer clock being off, or different time zones, etc. When the program starts, it grabs the current time on the SQL server, and starts a Stopwatch. Then each time I need the time, I find the elapsed time on the stopwatch and add to the SQL time. The problem is that I use these times sometimes to do timestamps as a unique ID for certain records, and sometimes multiple records get created in the same procedure, so it is being called more than once per second, so the same ID is returned. I need the time to go down to milliseconds, so it is more precise. Therefore, I can't just multiply the seconds by 1000.
Here's my class
vb.net
Public Class RealTime
'Added 11/03/2010 v0.4.4 To determine the real time, not the time on the local machine.
'The time will be stored in GMT +/-0 World Time
Private stopW As New System.Diagnostics.Stopwatch
Private StartTime As DateTime
[Code] .....
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