.net - Datediff And Dateadd Function?
Feb 22, 2011
If DateDiff(DateInterval.Day, moDoBooking.m_CurrentDay, moDoBooking.m_BaseDay) _
> DateDiff(DateInterval.Day, DateAdd(DateInterval.Day, _
Convert.ToDouble(moDoBooking.oBooking.oFacility.ADAYS), moDoBooking.m_BaseDay), _
moDoBooking.m_BaseDay) Then
This condition won't satisfy with these values:
moDobooking.m_CurrentDay = 2/3/2011
moDobooking.m_BaseDay = 22/02/2011
moDoBooking.oBooking.oFacility.ADAYS = 1
You might say this is dead-easy but honestly it's late here and my head is not working at all! Could AnyOne tell me why is that?
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May 16, 2010
I know I can import Microsoft.Visualbasic and just use the ones I used in vb6. But I don't want to ;)In vb6 DateDiff("d", dte1, dte2) would just give me the number of days between the 2 dates and it didn't matter which order I put the 2 dates, it would still return x days.In .Net i have Date.Compare(dte1, dte2) but I have to know which date is newer other wise I get a negative result because I subtracted a bigger from the smallerIs there no .NET way to just get the difference without having to subtract then multiply by -1 if its less than 0?ALSO,In vb6 I could use Weekday function to get what day of the week a date is and use it in the DateAdd function to find the first day of the week's date. Like so: dim firstday as date = DateAdd("d", (Weekday(today, vbWednesday) - 1) * -1, today) would like a .Net way to find the date of the first day of the week, giving that our week might not start on sunday or even monday. I need to pass a date and the weekstart day (wednesday) and have it return the date for the wednesday. Like this:dim firstday as date = GetFirstDay(Today, Firstday.Wednesday)so if the date i passed was "9/3/10" which is a friday, the function would return "9/1/10" which is the date my week started on.
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Oct 14, 2009
I would like to calculate a new date simply by using the build-in dateadd function, but take into account that only weekdays should be counted (or 'business days' so to speak).I have come up with this simple algorithm, which does not bother about holidays and such. I have tested this with some simple dates, but would like some input if this can be done in better ways.This sample assumes a week with 5 business days, monday-friday, where first day of the week is monday. Dateformatting used here is d-m-yyyy, the sample calculates with a startdate of october 1, 2009.
Here is the simple form:
Dim d_StartDate As DateTime = "1-10-2009"
Dim i_NumberOfDays As Integer = 12
Dim i_CalculateNumberOfDays As Integer
[code]....
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Jun 15, 2010
I am using the following code to add some value to a date:
Dim strdate As Date
Dim numinterval As Double
numinterval = 149548.720386359
strdate = DateAdd(DateInterval.day, numinterval, #1/1/1601#)
MsgBox(strdate)
The value numinterval is the number of days passed since 1/1/1601 (this is how date is counted for things like 'last logon time', 'last bad password' in Active directory). I do some calculation and get that numinterval value in days.. But since I want it to return the time more accurately, I tried first multiplying numinterval by 1400 for number of minutes.. And I changed the interval as dateinterval.minute... That worked fine!
But, when I tried again by multiplying it further by 60, to get the time accurately in seconds and changed the interval to dateinterval.second it throws the following exception:
Arithmetic operation resulted in an overflow
I changed the type of numinterval into long, but the same problem..
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Sep 16, 2010
I am trying to compute time off, I have a datetimepicker which allow user to select a day he wishes to start leave and a textbox to specify no of days applying for.Now I wand to use dateadd function to calculate resumption date excluding Weekends.
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Jun 22, 2010
I have five text boxes & one button there in my form. I have written this code to get user`s current age. But problem is that I have to get user`s age with months.
My code to get age :
Private Sub Command1_Click()
BDate = Text1.Text & "-" & Text2.Text & "-" & Text3.Text
CurDate = Now
[Code].....
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Jul 11, 2011
I am using the following code in my project. I want to find the number of days by given the last date and now.[code] for example, when BorrowDate is "01/Jul/2011" then the result is 7 days which it should be 10 to now.
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Dec 21, 2011
I had some trouble specifying Monday as the first day of week in the DateDiff function.
The following syntax does not work: Dim myWeekNumber as Int32 = DateDiff("ww",date1,date2,2)
Compiler Error Message: BC30519: Overload resolution failed because no accessible 'DateDiff' can be called without a narrowing conversion
However, using the enumeration value (FirstDayOfWeek.Monday) instead of the value (2) does work. I wonder why.
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Apr 10, 2011
I tested every example I found but it doens't work in vb 2010 express... Do I need to install anything moor to make it work?
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Apr 15, 2012
One of the problems with datediff function is that even if the two dates are 31-12-2011 and 01-01-2012,it will show the difference as 1 year.How to overcome this problem?
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Jun 9, 2009
DateDiff for the interval Day gives expected results for days past until present, but if the first date is further in time than the second date, it gives the difference +1. Is there something I'm doing wrong? For example, if I put in today for both, the difference is 0. If I put in yesterday and today, I get 1. This is all expected, but if I put in tomorrow and today, I get 0, and two days from now and today give -1. Why is the function giving altered results if the date is negative?
Here is the specific code.
Private Sub DateTimePicker1_ValueChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles DateTimePicker1.ValueChanged
TextBox1.Text = DateDiff(DateInterval.Day, DateTimePicker1.Value, Date.Now)
End Sub
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Jan 18, 2011
I have a project, a database with employee information (name, town, birthday, HireDate, etc). I have add custom TextBox (on fly), and on that TextBox a
TexBox1.text = DateDiff("d", HireDateDateTimePicker.value, Now)
.
Which is calculating how many days worker is working in company from HireDate,and Now.I have put code on event TextBox1_TextChanged. But, this means that I need to move cursor in TextBox1 to apply changes. I have also try with MouseMove. It works, but if I would have a huge database, then application will all the time reading script on MouseMove, and by that will slow down entire program.
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Jan 4, 2011
I am currently writing a scalar valued function and I'm having a few issue with the returned result. I have narrowed the problem down to a calculation that convert the difference between two dates as a percentage/decimal. No matter what I try the return value is always a whole number
set @earnedpremium = (@premium * @pretripearnings) + ((@premium - (@premium * @pretripearnings)) * cast((datediff(day, @outdate, @experiencedate) / datediff(day, @outdate, @returndate))as decimal(5,2)))
The cast section needs to return the percentage, I know the rest is working fine through some elimination and testing.
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Nov 10, 2010
The result will be '2010' for this query select year(getdate())
How do I get same result as Linq?select year(dateadd(yy,-1,getdate())), year(getdate()),
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Feb 25, 2011
Is there a way to add milliseconds in dateadd? It is not in the DateInterval enum. I created a class so my program knows what the real time is, based off the sql server. This way, we don't have to worry about people's computer clock being off, or different time zones, etc. When the program starts, it grabs the current time on the SQL server, and starts a Stopwatch. Then each time I need the time, I find the elapsed time on the stopwatch and add to the SQL time. The problem is that I use these times sometimes to do timestamps as a unique ID for certain records, and sometimes multiple records get created in the same procedure, so it is being called more than once per second, so the same ID is returned. I need the time to go down to milliseconds, so it is more precise. Therefore, I can't just multiply the seconds by 1000.
Here's my class
vb.net
Public Class RealTime
'Added 11/03/2010 v0.4.4 To determine the real time, not the time on the local machine.
'The time will be stored in GMT +/-0 World Time
Private stopW As New System.Diagnostics.Stopwatch
Private StartTime As DateTime
[Code] .....
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Jan 3, 2012
I'm trying to do a Datediff in VB.Net thats confusing me. Basically I'm trying to do the following. If DateDiff("D", Today(), rsData("Start")) > 0 Then This is working fine when comparing the value from SQL with todays date. I however need to convert this to check the current month and if it matches then return whatever I'm trying to show below.
[Code]...
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Jun 21, 2012
this code always return '0' i don't know why
Dim cur_month = DatePart(DateInterval.Month, Now).ToString()
Dim cur_date As String = "01/" + cur_month + "/" + (DatePart(DateInterval.Year, Now).ToString)
[Code]....
cnb_mnth is ComboBox for Month
txt_year is Text Box For Entering Year
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Aug 22, 2010
I am trying to put together a booking system. I have managed to program rates, discounts etc., and am now onto calculating the nights for the stay. On my form I have two datetimepickers, and a button. The code I have entered is: (I am using Visual Basic 2008 Express)
CODE:
This works well when getting how many nights between two dates in the same month, but if I enter say 30th August to 2th September, I get a -28. Is there a way to get the number of nights booked between two different months?
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Jan 15, 2011
I`m migrating access database to vb.net. I have employee database with a few DateTimePickers, textboxes, and comboboxes
In access I have formulas in textbox's control source like this, and it works:
txtDayCalculation=DateDiff("d",txtDateofHire, txtManualDate)txtYear=Int(txtDayCalculation/365)txtMonth=Int((txtDayCalculation-(txtYear*365))/30) txtDay=((txtDayCalculation-txtYear*365))-(txtMonth*30).
So, I have trying to do also in vb.net, but NOT successfull. Maybe my aproach to write a code is wrong. Anyway, I have write like this:
me.txtDayCalculation.text = DateDiff("d",txtDateOfHireDateTimePicker, txtManualDateDateTimePicker)me.txtDayCalculation.text = DateDiff("d",txtDateOfHireDateTimePicker, txtManualDateDateTimePicker)
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Feb 7, 2010
In my office we were using VB.net 2003 and MS SQL server 2000. Now we bought a license for vb.net 2008 and MS Sql Server 2005. I migrated our application to vb.net 2008..Now the code compiles without any problem, but when i run a report, it shows error. System. Data. Sql Client.SqlException : 'DateInterval.Day' is not recognized datediff option.It was working fine in 2003. [code]
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Oct 6, 2011
I'm trying to fill a label with a datediff 'minute' value.. but when the minutes value is < 10
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Oct 5, 2010
How can we handle the case where one date is blank in DateDiff method? Example:
DateDiff(DateInterval.Day, CType(txt61_2.Text, Date), CType(txt21_2.Text, Date))
In above statement fields txt61_2.Textor txt21_2.Text may be empty then take it has 0
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Nov 17, 2009
I am writing some code that is trying to determine how far through a season we are in a game we play.
[Code]....
The code below, sort of works:
[Code]....
which could be any day of the week. I've tried all sorts of things to programmatically set "FirstDayOfWeek.x", but it seems as though vb.NET wants it hard coded as FirstDayOfWeek.Monday or. Tuesday etc and you can't pass an integer like 1 or 2 so I could set it on the fly.
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Jun 21, 2010
i have a problem on my DateDiff result. For example the result is 3.5, it will only show 3. How can i control that?
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Apr 15, 2010
i am using Visual Studio 2008 and VB.NET 2008 and SQL Server 2005 as the database. I just finished designing & writing codes for a customer information and , however after it has been connected to the database only one of the datetimepicker can be click, and the rest of the function including in the form are not working!it seem that the form stuck and NOT responding. i cant even close the form (X button), so i have to stop the process using compiler (visual studio 2008), however if i press the 'Delete' button before the 'Add' button, it will successfully delete the data.. but if i disconnected the form from the database, (disabled the form_load codes [put 'quote']) the both of datetimepicker will work and able to view the date interval (after pressing the 'Calculate Period' button) in addition how to make it appear automatically in screen without using the button? below are the code, I try to make some other form.. but it is still the same
Code:
Imports System.Data.SqlClient
Imports System
Imports System.Data[code].....
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Jan 29, 2004
I am using the folowing code to calculate the difference between two dates. intDaysInDev = DateDiff(DateInterval.Day, calManuDt.SelectedDate, calLaunchDt.SelectedDate) I've now been told that the calculation should not include weekends.
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Jun 19, 2010
Is it possible to use DateDiff to find the difference between time?I have two time periods i.e. 05:00 and 05:10pm so i would like to run some code if the time is between the two specified periods. Ive searched around and i think DateDiff could do this but unsure?
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Jul 7, 2010
I need to calculate the number of weeks between 2 dates. This will be used in a billing system.
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May 9, 2011
I have a query to retrieve DateDiff in my SQL:
SELECT Convert(char,DATEDIFF(m, Temp.Opening_Date, '2011-05-01')) As MonthDifference From Temp
It was successfully retrieve the data from SQL Server. But when I bind it to my vb.net datatable, the value is null. It's seems like vb.net datatable doesn't support datatype from DateDiff... What can I do?
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Feb 11, 2012
I'm trying to get an If statement to check is the date picked from a datetimepicker is at least 3 days prior to the current date, I can get it to calculate the difference however if I chose a date that 4 days prior to the current date (i.e the result being -4), the else statement doesnt fire.is this something to do with the result being a negative value? I did try to assign the DateDiff result to a variable defined as a short and then used this variable in the If statement, but still get the same issue. Option Strict isn't showing any issues.
[Code]...
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