DateDiff Doesn't Take Into Account The First And FirstDayOfWeek
Nov 17, 2009
I am writing some code that is trying to determine how far through a season we are in a game we play.
[Code]....
The code below, sort of works:
[Code]....
which could be any day of the week. I've tried all sorts of things to programmatically set "FirstDayOfWeek.x", but it seems as though vb.NET wants it hard coded as FirstDayOfWeek.Monday or. Tuesday etc and you can't pass an integer like 1 or 2 so I could set it on the fly.
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May 9, 2011
I have a query to retrieve DateDiff in my SQL:
SELECT Convert(char,DATEDIFF(m, Temp.Opening_Date, '2011-05-01')) As MonthDifference From Temp
It was successfully retrieve the data from SQL Server. But when I bind it to my vb.net datatable, the value is null. It's seems like vb.net datatable doesn't support datatype from DateDiff... What can I do?
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May 30, 2012
I suppose it is impossible to change FirstDayOfWeek in DateTimePicker (as it is in MonthCalendar) but who knows?
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Sep 12, 2010
Does anyone know how to run windows explorer with an admin account while logged in with a non admnistrative account? i want to be able to open up an admin share on a remote host with windows explorer instead of iexplorer. I tried some code I found on the net to impersonate but it didn't work.
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May 17, 2012
I am currently working on a stock market monitoring application. how to create a new portfolio(sort of a personal account) for each user that accesses the system such that 2 different users do not have the same portfolio. I am making use of SQL server for my database.
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Aug 27, 2010
We have a windows service running under a network account that calls and runs an ActiveX exe. The exe is running under the local system account, not the network account of the service.
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Apr 26, 2009
Ok this is what I'm stuck on:I have 2 ListBoxes and 2 Lists, let's call them ListBox1, ListBox2, List1 and List2.List1 needs to be associated with ListBox 1, and List2 with ListBox2 I loop through a bunch of accounts, add them to LixBox1 at run-time.During that loop I add each account number to List1 so now the account number is associated with the ListBox index number which is right.Now when I double click one of the accounts in ListBox1 it is added to ListBox2 (but it still remains in ListBox1), and the same index of List1 added to List 2, now the account in ListBox2 is associated with the account number at the same index in List2 you see where I'm going with this?The issue wtarts here.When I double click an account (let's say the account at the first index) in ListBox2 it should be removed from the list, so now I remove the index from List2 since it's no longer needed, but now you know what's happened right? ListBox2's List indexes have all decremented by 1 because I just removed an item from the beginning of the list, but List2's indexes have stayed the same (at least that's how it appeared when I tested it).
So basically whats the best method for keeping things in reference? I was told about list boxes in another thread of mine, but is it really the best way to go about this, I can't seem to keep everything linked together reliably.
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Jan 3, 2012
I'm trying to do a Datediff in VB.Net thats confusing me. Basically I'm trying to do the following. If DateDiff("D", Today(), rsData("Start")) > 0 Then This is working fine when comparing the value from SQL with todays date. I however need to convert this to check the current month and if it matches then return whatever I'm trying to show below.
[Code]...
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Feb 22, 2011
If DateDiff(DateInterval.Day, moDoBooking.m_CurrentDay, moDoBooking.m_BaseDay) _
> DateDiff(DateInterval.Day, DateAdd(DateInterval.Day, _
Convert.ToDouble(moDoBooking.oBooking.oFacility.ADAYS), moDoBooking.m_BaseDay), _
moDoBooking.m_BaseDay) Then
This condition won't satisfy with these values:
moDobooking.m_CurrentDay = 2/3/2011
moDobooking.m_BaseDay = 22/02/2011
moDoBooking.oBooking.oFacility.ADAYS = 1
You might say this is dead-easy but honestly it's late here and my head is not working at all! Could AnyOne tell me why is that?
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Jun 21, 2012
this code always return '0' i don't know why
Dim cur_month = DatePart(DateInterval.Month, Now).ToString()
Dim cur_date As String = "01/" + cur_month + "/" + (DatePart(DateInterval.Year, Now).ToString)
[Code]....
cnb_mnth is ComboBox for Month
txt_year is Text Box For Entering Year
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Aug 22, 2010
I am trying to put together a booking system. I have managed to program rates, discounts etc., and am now onto calculating the nights for the stay. On my form I have two datetimepickers, and a button. The code I have entered is: (I am using Visual Basic 2008 Express)
CODE:
This works well when getting how many nights between two dates in the same month, but if I enter say 30th August to 2th September, I get a -28. Is there a way to get the number of nights booked between two different months?
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Jun 22, 2010
I have five text boxes & one button there in my form. I have written this code to get user`s current age. But problem is that I have to get user`s age with months.
My code to get age :
Private Sub Command1_Click()
BDate = Text1.Text & "-" & Text2.Text & "-" & Text3.Text
CurDate = Now
[Code].....
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Jan 15, 2011
I`m migrating access database to vb.net. I have employee database with a few DateTimePickers, textboxes, and comboboxes
In access I have formulas in textbox's control source like this, and it works:
txtDayCalculation=DateDiff("d",txtDateofHire, txtManualDate)txtYear=Int(txtDayCalculation/365)txtMonth=Int((txtDayCalculation-(txtYear*365))/30) txtDay=((txtDayCalculation-txtYear*365))-(txtMonth*30).
So, I have trying to do also in vb.net, but NOT successfull. Maybe my aproach to write a code is wrong. Anyway, I have write like this:
me.txtDayCalculation.text = DateDiff("d",txtDateOfHireDateTimePicker, txtManualDateDateTimePicker)me.txtDayCalculation.text = DateDiff("d",txtDateOfHireDateTimePicker, txtManualDateDateTimePicker)
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Feb 7, 2010
In my office we were using VB.net 2003 and MS SQL server 2000. Now we bought a license for vb.net 2008 and MS Sql Server 2005. I migrated our application to vb.net 2008..Now the code compiles without any problem, but when i run a report, it shows error. System. Data. Sql Client.SqlException : 'DateInterval.Day' is not recognized datediff option.It was working fine in 2003. [code]
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Oct 6, 2011
I'm trying to fill a label with a datediff 'minute' value.. but when the minutes value is < 10
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Oct 5, 2010
How can we handle the case where one date is blank in DateDiff method? Example:
DateDiff(DateInterval.Day, CType(txt61_2.Text, Date), CType(txt21_2.Text, Date))
In above statement fields txt61_2.Textor txt21_2.Text may be empty then take it has 0
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Jul 11, 2011
I am using the following code in my project. I want to find the number of days by given the last date and now.[code] for example, when BorrowDate is "01/Jul/2011" then the result is 7 days which it should be 10 to now.
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Jun 21, 2010
i have a problem on my DateDiff result. For example the result is 3.5, it will only show 3. How can i control that?
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Apr 15, 2010
i am using Visual Studio 2008 and VB.NET 2008 and SQL Server 2005 as the database. I just finished designing & writing codes for a customer information and , however after it has been connected to the database only one of the datetimepicker can be click, and the rest of the function including in the form are not working!it seem that the form stuck and NOT responding. i cant even close the form (X button), so i have to stop the process using compiler (visual studio 2008), however if i press the 'Delete' button before the 'Add' button, it will successfully delete the data.. but if i disconnected the form from the database, (disabled the form_load codes [put 'quote']) the both of datetimepicker will work and able to view the date interval (after pressing the 'Calculate Period' button) in addition how to make it appear automatically in screen without using the button? below are the code, I try to make some other form.. but it is still the same
Code:
Imports System.Data.SqlClient
Imports System
Imports System.Data[code].....
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Jan 29, 2004
I am using the folowing code to calculate the difference between two dates. intDaysInDev = DateDiff(DateInterval.Day, calManuDt.SelectedDate, calLaunchDt.SelectedDate) I've now been told that the calculation should not include weekends.
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Jun 19, 2010
Is it possible to use DateDiff to find the difference between time?I have two time periods i.e. 05:00 and 05:10pm so i would like to run some code if the time is between the two specified periods. Ive searched around and i think DateDiff could do this but unsure?
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Dec 21, 2011
I had some trouble specifying Monday as the first day of week in the DateDiff function.
The following syntax does not work: Dim myWeekNumber as Int32 = DateDiff("ww",date1,date2,2)
Compiler Error Message: BC30519: Overload resolution failed because no accessible 'DateDiff' can be called without a narrowing conversion
However, using the enumeration value (FirstDayOfWeek.Monday) instead of the value (2) does work. I wonder why.
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Apr 10, 2011
I tested every example I found but it doens't work in vb 2010 express... Do I need to install anything moor to make it work?
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Jul 7, 2010
I need to calculate the number of weeks between 2 dates. This will be used in a billing system.
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May 16, 2010
I know I can import Microsoft.Visualbasic and just use the ones I used in vb6. But I don't want to ;)In vb6 DateDiff("d", dte1, dte2) would just give me the number of days between the 2 dates and it didn't matter which order I put the 2 dates, it would still return x days.In .Net i have Date.Compare(dte1, dte2) but I have to know which date is newer other wise I get a negative result because I subtracted a bigger from the smallerIs there no .NET way to just get the difference without having to subtract then multiply by -1 if its less than 0?ALSO,In vb6 I could use Weekday function to get what day of the week a date is and use it in the DateAdd function to find the first day of the week's date. Like so: dim firstday as date = DateAdd("d", (Weekday(today, vbWednesday) - 1) * -1, today) would like a .Net way to find the date of the first day of the week, giving that our week might not start on sunday or even monday. I need to pass a date and the weekstart day (wednesday) and have it return the date for the wednesday. Like this:dim firstday as date = GetFirstDay(Today, Firstday.Wednesday)so if the date i passed was "9/3/10" which is a friday, the function would return "9/1/10" which is the date my week started on.
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Feb 11, 2012
I'm trying to get an If statement to check is the date picked from a datetimepicker is at least 3 days prior to the current date, I can get it to calculate the difference however if I chose a date that 4 days prior to the current date (i.e the result being -4), the else statement doesnt fire.is this something to do with the result being a negative value? I did try to assign the DateDiff result to a variable defined as a short and then used this variable in the If statement, but still get the same issue. Option Strict isn't showing any issues.
[Code]...
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Apr 15, 2012
One of the problems with datediff function is that even if the two dates are 31-12-2011 and 01-01-2012,it will show the difference as 1 year.How to overcome this problem?
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Jun 9, 2009
DateDiff for the interval Day gives expected results for days past until present, but if the first date is further in time than the second date, it gives the difference +1. Is there something I'm doing wrong? For example, if I put in today for both, the difference is 0. If I put in yesterday and today, I get 1. This is all expected, but if I put in tomorrow and today, I get 0, and two days from now and today give -1. Why is the function giving altered results if the date is negative?
Here is the specific code.
Private Sub DateTimePicker1_ValueChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles DateTimePicker1.ValueChanged
TextBox1.Text = DateDiff(DateInterval.Day, DateTimePicker1.Value, Date.Now)
End Sub
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Jul 22, 2009
I found very wiered behaviour for DateDiff. or any other kind to date difference methods avalibale when Date has AM/PM specified in it.
Cl.LunchStartTime =
"2009/7/13 12:10:00 AM"
Cl.LunchEndTime =
[code].....
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Aug 29, 2011
Anyone know how I can return 3.0790 given the two dates below using VB.NET 4?The code below returns a whole number 3... Dim datTim1 AsDate = #1/31/2005# Dim datTim2 AsDate = #2/29/2008# Dim YEARS AsDouble = DateDiff(DateInterval.Year, datTim1, datTim2) MessageBox.Show("Years: " & YEARS)
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