Anyone know how I can return 3.0790 given the two dates below using VB.NET 4?The code below returns a whole number 3... Dim datTim1 AsDate = #1/31/2005# Dim datTim2 AsDate = #2/29/2008# Dim YEARS AsDouble = DateDiff(DateInterval.Year, datTim1, datTim2) MessageBox.Show("Years: " & YEARS)
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this code always return '0' i don't know why
Dim cur_month = DatePart(DateInterval.Month, Now).ToString()
Dim cur_date As String = "01/" + cur_month + "/" + (DatePart(DateInterval.Year, Now).ToString)
[Code]....
cnb_mnth is ComboBox for Month
txt_year is Text Box For Entering Year
I need to return the exact difference between two dates in the form of a string. If the dates are 01-FEB-2012 and 01-FEB-2014, the function should return "2 years" If the dates are 01-FEB-2012 and 01-MAR-2014, the function should return "25 months". If the difference is not in exact years or months, it should return the difference in days. I do not want to use DateDiff from the Visual Basic namespace so the code is portable to C#.
View 1 RepliesI'm using datediff to establish difference between two dates using datetimepicker.i.m nnot getting the right results. a one day difference returns a 0, a two day difference returns a 1 etc. the code I am using is posted below.
days = DateDiff(DateInterval.Day, dtpStart.Value(), dtpEnd.Value())
I am building an application where a button click runs a sql query and shows a user the next available date that they can process from. The problem was that it needed to be the following Sunday and not the following day.
That code looked like this:
Public Class Form1
Dim ReturnValue As Object = Nothing
Private Sub Button1_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
[Code]....
I am building an application where a button click runs a sql query and shows a user the next available date that they can process from. The problem was that it needed to be the following Sunday and not the following day.That code looked like this:
Public Class Form1
Dim ReturnValue As Object = Nothing
Private Sub Button1_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim connectionString As String
[code]....
I am building an application where a button click runs a sql query and shows a user the next available date that they can process from. The problem was that it needed to be the following Sunday and not the following day. That code looked like this:
Code:
Public Class Form1
Dim ReturnValue As Object = Nothing
[code]....
Code:"select payrolldate from payroll where(payrolldate <= getdate())and payrollran <> 'yes'")but when I add that query it just returns a value of 1/1/000 as the date.
Is there a way to get the fraction parts of a Double without using string manipulations? Specifically in vb.net?
There are numerous examples for a decimal in various languages. One for vb.net is this one
Basically they all seem to use either a mod or Truncate method or they take advantage of casting to integer behavior. But none of those approaches will work for a double/float type due to the inherent inaccuracy of the double/float type. There is also the problem that doubles don't cast to decimals reliably. Below is a test case to show what I mean and expect.
<TestClass> _
Public Class BasicNumberTests
Function DecimalFractionalPart(ByVal number As Decimal) As Decimal
[Code]....
I am creating a math related class and one of the problems I have been having was how to create a function to return the fractional part of a double as an integer. I could easily do that if there was a way I could get the length of the digits.
-3.141 should return 3
-0.125 should return 3
-0.5 should return 1
-0.4545 should return 4
I would like to do this without using string manipulation. So far all I have gotten on the web is unanswered questions. I thought of using log, but it doesn't give the desired result when working with numbers < 0
I have a web app that sets a var setT to DateTime.Now. This var is used to set a "lastUpdate" field in a database and Cache("ltu"). This value is also added to a cookie. the problem I'm having is that comparing the cookie value and the cahed value show that the cookie value is earlier than the cached value, eventhough it is the same value that cam from the setT var.I'm assuming that the fractional seconds are being set to 0000's in the cookie by some means which is the only explaination I can come up with.Now, Is there some way I can set the origianal setT DateTime.now value to not have fractional seconds, or zero fractional seconds?Do you think I'm going about this correctly?
View 1 RepliesSimple requirement to split a double value inputted into a string to decimal and fractional.I enter 12.1 and it splits it into
12 and then 0.0999999999999996
Where is my 0.0000000000000004 gone??? Did the cpu tax it?I have tried a few other tricks to split the number and i get the same result...The fractional results of each attempt
12.0 0 Amazing!!!!
12.1 0.0999999999999996
12.2 0.199999999999999
[code]....
I have an ASP.NET web application (VB.NET) using an Oracle database. On an insert, I need to get the identity of the inserted row back. I am trying to use RETURNING, but I keep getting a value of 1 returned.
Dim strInsert As String = "INSERT INTO L.TRANSACTIONS (LOCATION_KEY, TRANS_CREATOR, TRANS_EMAIL, TRANS_PHONE) VALUES (:location_key, :trans_creator, :trans_email, :trans_phone) RETURNING TRANS_ID INTO :ukey"
[Code].....
I have two dates. [code] How to print all dates between these two dates in one listbox, for example: [code]
View 8 RepliesSay the user specifies these two dates....
Start Date: 2010-12-05
End Date: 2011-01-15
If I select December 2010 I should get the folllowing
startdate = 2010-12-05
enddate = 2010-12-31
Select January 2011 then
startdate = 2011-01-01
enddate = 2011-01-15
Should I subtract dates? How can I get the start and enddate for the current month/year based on the overall start and end date.I'm coding in vb.net.
My brain may just be fried since it's the end of the semester, but my teacher kicked this back to fix and resubmit...she said that I am "returning the name of your function rather than your variable name".
Here is my code for all 3 forms.
code:
These are forms to calculate the cost of getting a cell phone package.
I'm using two datetimepicker controls to set the start and end dates for a range of dates I'm searching for.I want to make sure that the start date selected is not greater than the end date. This code works, but it runs the messagebox prompt twice for some reason. I've tried to ignore it from doing this, but it's not working. Can someone tell me what's wrong?
Private Sub dtpStart_ValueChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles dtpStart.ValueChanged
[Code]...
I have one more problem with MonthControl.And when I bold some dates the program doesn't show bold dates on month calendar.When I move on next or previous month and get back to currently month the program normal displays bold dates. What's the problem?
View 22 RepliesI'm trying to do a Datediff in VB.Net thats confusing me. Basically I'm trying to do the following. If DateDiff("D", Today(), rsData("Start")) > 0 Then This is working fine when comparing the value from SQL with todays date. I however need to convert this to check the current month and if it matches then return whatever I'm trying to show below.
[Code]...
If DateDiff(DateInterval.Day, moDoBooking.m_CurrentDay, moDoBooking.m_BaseDay) _
> DateDiff(DateInterval.Day, DateAdd(DateInterval.Day, _
Convert.ToDouble(moDoBooking.oBooking.oFacility.ADAYS), moDoBooking.m_BaseDay), _
moDoBooking.m_BaseDay) Then
This condition won't satisfy with these values:
moDobooking.m_CurrentDay = 2/3/2011
moDobooking.m_BaseDay = 22/02/2011
moDoBooking.oBooking.oFacility.ADAYS = 1
You might say this is dead-easy but honestly it's late here and my head is not working at all! Could AnyOne tell me why is that?
I am trying to put together a booking system. I have managed to program rates, discounts etc., and am now onto calculating the nights for the stay. On my form I have two datetimepickers, and a button. The code I have entered is: (I am using Visual Basic 2008 Express)
CODE:
This works well when getting how many nights between two dates in the same month, but if I enter say 30th August to 2th September, I get a -28. Is there a way to get the number of nights booked between two different months?
I have five text boxes & one button there in my form. I have written this code to get user`s current age. But problem is that I have to get user`s age with months.
My code to get age :
Private Sub Command1_Click()
BDate = Text1.Text & "-" & Text2.Text & "-" & Text3.Text
CurDate = Now
[Code].....
I`m migrating access database to vb.net. I have employee database with a few DateTimePickers, textboxes, and comboboxes
In access I have formulas in textbox's control source like this, and it works:
txtDayCalculation=DateDiff("d",txtDateofHire, txtManualDate)txtYear=Int(txtDayCalculation/365)txtMonth=Int((txtDayCalculation-(txtYear*365))/30) txtDay=((txtDayCalculation-txtYear*365))-(txtMonth*30).
So, I have trying to do also in vb.net, but NOT successfull. Maybe my aproach to write a code is wrong. Anyway, I have write like this:
me.txtDayCalculation.text = DateDiff("d",txtDateOfHireDateTimePicker, txtManualDateDateTimePicker)me.txtDayCalculation.text = DateDiff("d",txtDateOfHireDateTimePicker, txtManualDateDateTimePicker)
In my office we were using VB.net 2003 and MS SQL server 2000. Now we bought a license for vb.net 2008 and MS Sql Server 2005. I migrated our application to vb.net 2008..Now the code compiles without any problem, but when i run a report, it shows error. System. Data. Sql Client.SqlException : 'DateInterval.Day' is not recognized datediff option.It was working fine in 2003. [code]
View 6 RepliesI'm trying to fill a label with a datediff 'minute' value.. but when the minutes value is < 10
View 2 RepliesHow can we handle the case where one date is blank in DateDiff method? Example:
DateDiff(DateInterval.Day, CType(txt61_2.Text, Date), CType(txt21_2.Text, Date))
In above statement fields txt61_2.Textor txt21_2.Text may be empty then take it has 0
I am writing some code that is trying to determine how far through a season we are in a game we play.
[Code]....
The code below, sort of works:
[Code]....
which could be any day of the week. I've tried all sorts of things to programmatically set "FirstDayOfWeek.x", but it seems as though vb.NET wants it hard coded as FirstDayOfWeek.Monday or. Tuesday etc and you can't pass an integer like 1 or 2 so I could set it on the fly.
I am using the following code in my project. I want to find the number of days by given the last date and now.[code] for example, when BorrowDate is "01/Jul/2011" then the result is 7 days which it should be 10 to now.
View 1 Repliesi have a problem on my DateDiff result. For example the result is 3.5, it will only show 3. How can i control that?
View 1 Repliesi am using Visual Studio 2008 and VB.NET 2008 and SQL Server 2005 as the database. I just finished designing & writing codes for a customer information and , however after it has been connected to the database only one of the datetimepicker can be click, and the rest of the function including in the form are not working!it seem that the form stuck and NOT responding. i cant even close the form (X button), so i have to stop the process using compiler (visual studio 2008), however if i press the 'Delete' button before the 'Add' button, it will successfully delete the data.. but if i disconnected the form from the database, (disabled the form_load codes [put 'quote']) the both of datetimepicker will work and able to view the date interval (after pressing the 'Calculate Period' button) in addition how to make it appear automatically in screen without using the button? below are the code, I try to make some other form.. but it is still the same
Code:
Imports System.Data.SqlClient
Imports System
Imports System.Data[code].....
I am using the folowing code to calculate the difference between two dates. intDaysInDev = DateDiff(DateInterval.Day, calManuDt.SelectedDate, calLaunchDt.SelectedDate) I've now been told that the calculation should not include weekends.
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