DateFormat In Year Only Appear Two Digits Instead Of Four In ListView?
May 18, 2012
With Binding the Listview with dataset, the dateformat in datefield only appear the year as '12' instead of '2012',
strSQL = "select * from tableA where PNo = '" & cbPortNo.SelectedItem.ToString() & "' and convert(date, fDateReceived) = '" & dDateSelected & "'"
Dim da1 As New SqlDataAdapter(strSQL, sqlconn)
I'm trying to match a string to see if it matches exactly this:####-####, it has to be 4 digits followed by a hyphen followed by 4 more digits. Right now I have this pattern: "d{4}-d{4}" but it's allowing 5 digits in either (or both) instead of strictly 4 per group. Here's an example of what it should allow:
1999-2000 2003-2007 2009-2010
and here's what my pattern is allowing but should not be allowing:
I have 10 labels with 10 numbers and i want theses numbers to compare with other 10 labels with different numbers and when they found that second pair of labels are not equal with the first to show me in a new label where is the fault and in another new label the sum of the mistakes
i want to insert booking_no as combination of year and sno(year/sno) into database here iam giving the code as follows,,,,,,,,, here sno stated from 1.........
Dim conn As New SqlConnection(ConfigurationManager.ConnectionStrings("guest1").ConnectionString()) Dim booking_no, sno As String If Len(sno) = 1 Then
[code]....
but here booking_no was not inserted properly,it was inserted as "0/ ",,iwant to insert booking_no as "2010/sno" ,
I am using a DateTimePicker control in my form. By selecting a date, it should be inserted in an MS SQL database. But, the date format in VB is (DMY) and is different from the format in MS SQL (YMD) !!
I have the following function which is used by a class. It sets dates. Now the problem I have is one date comes back as dd/mm/yyyy and the other as mm/dd/yyyy
I am trying gto get my date formated in the 01/01/2011 format which I beleive is "M/dd/yyyy"current line of code Me.List1_slddatetxt.DataBindings.Add("Text", Subject_Values.BindingSource4, Form10.DateSold_txt.Text, True).FormatString = "M/dd/yyyy"
I am having a problem with my program that is desinged to read a 3rd party text file database. I posted previosuly about a problem inserting an item in a new row and the column was expectig a different data type. It appears that sometimes the column is being determined to be of decimal value, I dont understand why. the fields contain information such as
Col1 F123456 CLW-12321 etc....
So my column fills with 123456 12321 the letters just get chopped off
So I added MaxScanRows = 0 to my schema file and that took care of the problem
Except now several of my columns that contain Date Values are coming back
9/24/2010 00:00:00
without the setting MaxScanRows = 0 The date returned 9/24/2010
Here is the code for my schema ini file I am creating:
HTML
Dim fs As New FileStream("Schema.ini", FileMode.Create, FileAccess.Write) Dim writer As New StreamWriter(fs) [CODE]............
I have been trying different settings hence the dimmed out lines
Here is the code to fill the datatable:
HTML
[CODE].............
I am thinking that without the MaxScanRows = 0 setting the datatype for Col1 is being incorrectly determined
I am not sure what is happening with other columns that contain date values. Apparently If i use MaxScan Rows=0 all columns are being pulled over as string value which creates numerous problems. If I dont use maxscanrows then all columns appear to be correct except Col21 MLSNUM which is being pulled in as a decimal. Can I change that in the schema file?
I want to only show the last four digits of a Social security number after they leave the textbox. Does AJax have a tool for this that I am not aware of? How can i do this? I want to replace the digits with '*'. I'm working in .NET. Ajax is also accessible.
I have a textbox called TxtProNo - this should be ONLY 10 digits maximum. After 10 digits have been typed, the user can't enter any more digits, how can I achieve this...
actually we have given an assignment that find the LCM of two digits in VB.netbut i m not getting the logic how to code this...e-g... we have two digits... 10 and 20
Excuse me if this question already have been answered somewhere else but I really need to know.I need the code to take certain digits out of an intiger, for example:I have the integer 3002010 I want to put the 2 last digits in another integer.Then I want to put the 20 in another integer.After that I take the first digits which comes before those.
Another example:
I have 2993064 In integer one it should be 64 In integer two it should be 30 In integer three it should be 299
I want to run a check on a String right before I append it to a StringBuilder to make sure only numeric characters are in the string. What's a simple way to do that?
I need to count the number of digits in an integer input by the user. In other words if the user enters 101010, I need to obtain the value of 6, because there are 6 digits in this number
I need a function that takes a decimal, with a certain number of digits behiond the comma and convert it to a string with a different number of n digits behind the comma. (to display it)My problem is the rounding ip/down.
like 123,789 with n = 2 --> 123,79 or 123,4 with n = 0 --> 123 or 123,5 with n = 0 --> 124
I did not find an existing function that does that, so I wrote one myself.However the code has become soo complex and it still does not work well, and I get frustrated to spend soo much time with something so trivial.Does anyone know a function that can do this? There must be something out there.
The client can enter only four digits in the textbox wich represent the PIN (the text box is not allowed to enter more or less than four digits) . After the client entered four digits the textbox will be read only
My problem :When I put one digite then the text box becomes read-only, i want to enterd only 4 digite ..
Private Sub TextBox1_KeyPress(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyPressEventArgs) Handles TextBox1.KeyPress If e.KeyChar Like "[0_9]" Or Asc(e.KeyChar) Like 8 Then
Now i am doing a vb.net desktop application, In which i have to construct GUID. Eventhough having a built-in function in our VB.NET like "System.Guid.NewGuid.ToString()" to get GUID, I need to create the GUID in 30 digits in the below mentioned criteria through vb.net.
Application constructs the GUID (30 digits) using the information from the 5 different sources. The different sources are Current system time, millisecond of the system time, Process ID for the application, system physical memory status and finally the group object identifier number.
8 digits 4 digits 8 digits 8 digits 2 digits
[Code]....
I am not sure how to get the above values to construct the GUID?
I found this code for making my textbox only accept numbers.
Private Sub TextBox1_KeyPress(ByVal sender As System.Object, ByVal e As System.Windows.Forms.KeyPressEventArgs) Handles TextBox1.KeyPress Dim allowedChars As String = "0123456789"
[Code]....
But... the user can't delete the numbers using the backspace button. How do I do then?
Given a texbox, how can I completely ignore non-digit characters? So if I press "A" or "Z", those characters would never appear in the textbox. I'd like to run a bit of code if the user tries to input digits and if he tries to input non-digits too..
Given a texbox, how can I completely ignore non-digit characters? So if I press "A" or "Z", those characters would never appear in the textbox. I'd like to run a bit of code if the user tries to input digits and if he tries to input non-digits too
WRITE A PROGRAM THAT TAKES AN INTEGER VALUE AND RETURNS WITH ITS DIGITS REVERSED.. ex. input 7631 output: 1367POSITIVE NUMBER ONLY...Could you guys give me a hint on what i'm supposed to do here?
I am new to VB (and coding in general) and I'm wanting to make a check digit generator. To do this I need to take the a user text input and split it into individual digits so that I can then calculate the check digit.