I am new to VB (and coding in general) and I'm wanting to make a check digit generator. To do this I need to take the a user text input and split it into individual digits so that I can then calculate the check digit.
View 2 RepliesHow do I split a 2-digit number from a textbox and put the first digit in one label and the second digit in another label when a button is clicked?
View 2 RepliesI am trying to split a long string based on an array of words. For Example:Words: trying, long, array Sentence: "I am trying to split a long string based on an array of words."Resulting string array:Multiple instances of the same word is likely, so having two instances of trying cause a split, or of array, will probably happen.
View 5 RepliesI need a regular expression that I can use in VBScript and .NET that will return only the numbers that are found in a string.
For Example any of the following "strings" should return only 1231231234
123 123 1234
(123) 123-1234
123-123-1234
[Code]....
I want to run a check on a String right before I append it to a StringBuilder to make sure only numeric characters are in the string. What's a simple way to do that?
View 7 RepliesDim Timing1, Timing2 As DateTime
Timing1 = DateTime.Now
MyCode
[code].....
For some reason I can't figure this out. Here's my code. colorTextbox.Text =Format(Hex(ColorBox.Color.G), "00")What I want it to do is format the Green Hex number to be "00" instead of just "0" when the color is something like blackhis has proven to be very stressful and this Format command makes no sense to me anymore (worked differently in 2005).For one, whatever I put in the quotes ("00") is what comes out in the text box. Butaccording to the command parameters, "00" should be the format, not the actual text! So then I tried any string format I could think of (## etc.) along with switching the order and I STILL can't figure this out.
View 16 RepliesHow to extract digits from the beginning of a string?
1234A - should output: 1234
123AB - should output 123
12ABC - should output 12
1ABCD - should output 1
my code is :
[Code]...
The error is Value of type '1-dimensional array of string' cannot be converted to 'String'.
This is an example of the text I want to modify:
0110
0001
0001
1000
[Code]....
Here, I want to replace two-line digits in bold(0110 0001) with a different sequence as the program scans the text line by line. But two things complicate the task:
1. the comma lines should be ignored, but
2. they also should stay intact after changing the digits.
I'm trying to match a string to see if it matches exactly this:####-####, it has to be 4 digits followed by a hyphen followed by 4 more digits. Right now I have this pattern: "d{4}-d{4}" but it's allowing 5 digits in either (or both) instead of strictly 4 per group. Here's an example of what it should allow:
1999-2000
2003-2007
2009-2010
and here's what my pattern is allowing but should not be allowing:
20081-2009
2009-20101
12345-12345
12345-1234-1234
I have 10 labels with 10 numbers and i want theses numbers to compare with other 10 labels with different numbers and when they found that second pair of labels are not equal with the first to show me in a new label where is the fault and in another new label the sum of the mistakes
View 3 RepliesI'm trying to split a Yahoo historical stock price csv file, downloaded into a string, by what looks like a space character. I want a new row for each split. The split function works for other characters I see in the string. I suspect the characters may be a non breaking space character but I've been unable to split on them. This is the test csv file that is downloaded into the string: [URL] I'm trying to split the string like this:
[Code]...
These is the content of my txt file which is saved in D drive in my pc abc,1,2,3..I tried the flowing but it didn't work:[code]I am getting error on this line.. data = line.Split(","c)...it says this line isn't in use anymore or something and that I rather use LineInput but thats asks for filenumber and i don't know what that is. I am sorry but I am a complete beginner. what else can I try? [code]ok that error is gone now but now if I want to add these values to a list box..how can i do that?
View 1 RepliesIs there a way to use the string.split command to get a section of a string without using an intermediary array?for example, if my string is "1 2" and I want to get the "2" part using string.split(" "), is there a way to avoid creating a new array, and just get the bit of the string I want in a single line?
View 4 RepliesAfter having some trouble in my own code using String.Split and the Split(String(), Int32, StringSplitOptions) overload, I decided to look to the MSDN.I copied the entire VB.NET code example from this link: url...I placed it in a new class, and received the following errors (same errors as my own code example):[code]Why can my code not recogognize the string() parameter overloads to String.Split? Remember, i took the code from the MSDN link above, copied and pasted and it still did not work.I am counting on using the string() instead of char() overloads shown here: url...
View 15 RepliesBackground: I have a winForm app that registers a user in the database based on the information provided, auto-generates a random password and username, and e-mails the user a link to take an application based on the marketing company selected. Problem: hen the user clicks "Send Invitation" with data inputted iton all fields except the bundles listbox in debug, the NullReferenceException Error is thrown highlighting the line: Dim MCShort As String = Trim(splitMC(0))How do I fix this issue Here's a screenshot of the web app: Here's the code of the Send_Button_Click method off default.asx.vb:
Private Sub Send_Button_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Send_Button.Click
'TODO Add code to validate that all selections that are reaquired are met.
[code].....
I have some code that splits a session into strings by a -
My session looks something like this 123-456-789- and I split it like this
Dim MyString As String() = Session("MySession").Split("-"C)
And i've got a some code like this
Dim x as Integer
For x = 0 to MyString - 1
Response.write("Ref: " & MyString(x) & "<br>")
Next
This writes the code like this
Ref: 123
Ref: 456
Ref: 789
Ref:
So it's adding an extra Ref where it shouldn't be because there is no data after the last -
Is there a way to stop this adding in the extra one?
I have a long string like this
dim LongString as String = "123abc456def789ghi"
And I want to split it into a string array. Each element of the array should be in 3 characters length[code]...
I have a string which I've split into an array. I need to change a value in the array and join the string together. However I cannot set the value of the array variable as it's read only.Is there any way to do this without creating another array?
Dim LineOfText As StringDim aryTextFile As String[code...]
I want to take a string from a text box and split each letter of the string into an array. Then, I want to take the first item in the array(the first letter of the string)and capitalize it. Once I've done all that, I want to combine the array and convert it back to the original string it was, except I want the first letter to be capitalized(I've already placed this into a variable.)
Here's what I've come up with so far:
[Code].....
how to combine the array back to a string except I replace the first letter of the original string with the "firstLetter" variable I created.
I want split a gridview row on an html tag. How can i do this preferably in C#??.row.cells[1].Text.Split("htmltag")
View 7 Repliesi was unable to implement a multiline label or a transparent multiline textbox. So ive come up with the long way.I have paragraph of words (approx 100) that changes on a click. i want to split the paragraph into blocks of 20 and create 5 strings.
' Split string based on spaces
Dim split As String() = movieDetails(0).movieInformation.ToString.Split(" ")
i dont know how to put them into array. I keep getting this error " variable has been used before it has been assigned a value"
How would I split the following string?
test, 7535, '1,830,000', '5,000,000'
The result should be
test
7535
'1,830,000'
'5,000,000'
I try:
Dim S() as string = mystring.split(",")
But I get,
test
7535
'1
[code]....
have this stringmain
String="/MyApp/ViewPage.aspx?userId=admin&password=1&id=975"and i have two sting variables1)strTempUsername2)strTempPasswordin these variables i want to store userId and password values from mainStringso for this requirement how i wirte logic in codeHere
[code].....
I'm using vb.net 2.0. Here is my input string "When the string needs to be splited to fit on the lines, it is tried to split the string at a gab between words." I want to split string for the given word "to fit on the lines" and i gave like this code:
Dim string1 As
String() = strBody.Split("to fit on the lines")
But the output came like this :
string1 {Length=16} String()
(0) "When " String
(1) "he s" String
(2) "ring needs " String
[code]....
I want is to split the string as :
string1(0)="When the string needs to be splited " string1(1)=", it is tried to split the string at a gab between words."
i have one long field, a string. it looks like it was once xml. i am wondering if there is some way to split this field into the correct parts.
<Record><DocumentRequestID>7360095</DocumentRequestID><FirstName>ETHEL</FirstName><LastName>DANIELS</LastName><DateOfBirth>1927-04-21T00:00:00</DateOfBirth>
I have a filename in a string. I want to split the given string into 2 (1 is filename without extension, 2 is only extension) strings. Then add _dev to the end of first string and concatenate with 2nd one.
ex: Dim name as string="abc.txt"
Dim finalName as string
The finalName should be like this "abc_dev.txt"
Need to take a string in vb and split it. Also need to look through the two returned values and return the value which contains [URL]. Pipelines are the delimiter.
txtEmailFrom.Text = "john@huno.com|james@domain1.com"
Dim brokened() As String
brokened = Split(txtEmailFrom.Text, "|")
I'm having some issues using the String.Split method, Example here:
Dim tstString As String = "something here -:- urlhere"
Dim newtstString = tstString.Split(" -:- ")
MessageBox.Show(newtstString(0))
MessageBox.Show(newtstString(1))
The above, in PHP (My native language!) would return something here AND urlhere in the message boxes.
In VB.NET I get:
AND
: (colon)
Does the String.Split only work with standard characters?