This is an example of the text I want to modify:
0110
0001
0001
1000
[Code]....
Here, I want to replace two-line digits in bold(0110 0001) with a different sequence as the program scans the text line by line. But two things complicate the task:
1. the comma lines should be ignored, but
2. they also should stay intact after changing the digits.
How to extract digits from the beginning of a string?
1234A - should output: 1234
123AB - should output 123
12ABC - should output 12
1ABCD - should output 1
[code].....
View 2 RepliesSorry if this seems like I haven't searched, however I have. Maybe I'm not understanding something or maybe I just haven't found what I need. Anyway my question is this. How would I find multiple strings in a text file and replace them? So far I've been able to find out how to replace a single string with:
[Code]...
Here's the content of text file:
0022005138450000425081959 091
003200513845161223180000001Doppel-Pack, WET "Warming" & "Original" 0000001499
003200513845161048400000001Handschellen-Set, "Fetish Fantasy" 0000000999
003200513845161214340000001Strap-on, "His Vibrating S(extension)" 0000003999
[code]....
I want to draw string in multiple lines and and I want to know how many lines given string will take. I am using following method.
[Code]...
I need a regular expression that I can use in VBScript and .NET that will return only the numbers that are found in a string.
For Example any of the following "strings" should return only 1231231234
123 123 1234
(123) 123-1234
123-123-1234
[Code]....
I want to run a check on a String right before I append it to a StringBuilder to make sure only numeric characters are in the string. What's a simple way to do that?
View 7 RepliesI am new to VB (and coding in general) and I'm wanting to make a check digit generator. To do this I need to take the a user text input and split it into individual digits so that I can then calculate the check digit.
View 2 RepliesDim Timing1, Timing2 As DateTime
Timing1 = DateTime.Now
MyCode
[code].....
I've got an issue with a program I am writing. The specific issue is replacing characters in a parent string by finding, and matching, specific characters within it that are parsed from an external xml file. It's for a chat-like client.Here's the 2 classes I am using to pull the emote strings, titles, and id from external XML:
Imports System.Text.RegularExpressions
Imports System.Xml.Serialization
Public Class emote
[code].....
For some reason I can't figure this out. Here's my code. colorTextbox.Text =Format(Hex(ColorBox.Color.G), "00")What I want it to do is format the Green Hex number to be "00" instead of just "0" when the color is something like blackhis has proven to be very stressful and this Format command makes no sense to me anymore (worked differently in 2005).For one, whatever I put in the quotes ("00") is what comes out in the text box. Butaccording to the command parameters, "00" should be the format, not the actual text! So then I tried any string format I could think of (## etc.) along with switching the order and I STILL can't figure this out.
View 16 RepliesI'm building a program in which it asks for your name and age and determines a ticket price based upon these details. I want it to show the person's name, then their age, (jump down a line) then their ticket price, and then it jumps down a line to show the next person's name, age and ticket price. Issue is, when it's meant to jump down to show the next person, it just completely deletes the last person's details.I'm using this line of code:
TxtFareShow.Text = (Name & Age & vbCrLf & Price) & vbCrLf
How do I fix this?
I am creating a VB application in Visual Studio 2010 that installs some SQL stored procedures. These stored procedures are encrypted otherwise I would just supply my clients with .sql files to create the stored procedures.
The install script that creates the stored procedure is 1500 lines in length and has been formatted in the way VS 2010 requires multi-line literals to be in:
"First Line" & _
"Second Line" & _
"etc..."
[Code]....
I'm trying to match a string to see if it matches exactly this:####-####, it has to be 4 digits followed by a hyphen followed by 4 more digits. Right now I have this pattern: "d{4}-d{4}" but it's allowing 5 digits in either (or both) instead of strictly 4 per group. Here's an example of what it should allow:
1999-2000
2003-2007
2009-2010
and here's what my pattern is allowing but should not be allowing:
20081-2009
2009-20101
12345-12345
12345-1234-1234
I have 10 labels with 10 numbers and i want theses numbers to compare with other 10 labels with different numbers and when they found that second pair of labels are not equal with the first to show me in a new label where is the fault and in another new label the sum of the mistakes
View 3 RepliesI am using the .Replace function of a string. My string is a module I have added for a resource which looks like this: My.Computer.Network.DownloadFile("This String Will Go Away/details.txt", "details.txt") And then in my application I have:
[Code]...
This should be fairly simple but i'm having one of those days, can any1 advise me as to how to replace the first and third occurance of a character within a string, i have looked at replace but that cannot work as the string could be of different lengths, all i want to do is replace the first and third occurance?
View 2 RepliesOkay, so I know now how to replace vowels in a string. Is there any way I can use the Select Case similar to the code below to replace all numbers into letter Z.
[Code]...
I am trimming some strings but I am unable to do anything about the strings containing plus signs. For example if I have this string with a telephone number
Dim str As String = "+46765124246"
And try
str.replace("+46", "0")
Nothing changes in the string.
im having problems using the replace method.newpassword = oldpassword.Replace("[aeiou]", "X")
View 10 RepliesI am trying to replace a ' with " but this does not work:
Dim strFilter As String = " 'TESt'"
Dim x As String = strFilter.Replace(Chr(145), Chr(147))
Dim u As String = strFilter.Replace(Chr(146), Chr(148))
I have an issue, i have a program im working on, that i have been working on and im trying to replace a whole block of text. I do it in one spot in my code and it works great, but in a different part of my code, even though im using the same exact logic and pretty much the same code (other than slight variable changes) it will not work, and i have no idea why, it just like ignores it. I took some screenshots:If you look hard the only difference is the "S12000" (top pic) is changed to "S6000" (bottom pic). The pic shows this part about 3/4 of the way thru it.
View 1 RepliesIm wanting to use a textbox for the entry of Decimal figures (currency). Is there any way I can have it so if a user does not put a decimal figure (ie 15 instead of 15.00) it will put it on.
I tried a masked textbox, but that means i have to set the maximum number of digits before the decimal too which is no good.
How do I turn
1
2
3
1
[code]....
into
1
2
3
?
I basically want to remove multiple strings within a string.
How to comment multiple lines of code/block of code in VB?
View 5 Repliesfor example i have two strings 0000 and 0001 then
0000
0001
----
result= 000- here difference is indicated by - sign
I am working on a program and for one of my features, I need to replace all spaces in a program with - (dashes.) Is there a way in which I can do this?
Example:
Start String = "The rain in Spain falls mainly in the plain."
End String = "The-rain-in-Spain-falls-mainly-in-the-plain."
[code].....
i have an array that contains a-z.When i enter text like "ab" into a textbox and click the button, it will search the array and replace the text accordingly to the index number of the array and rewrite into the textbox with the index number.
But what i got from the code below is "ab0 1".May i know how to do so that the textbox will only display the index number and not with the letters. Also, how do i search the array from index 12 onwards to the end of the array.
For Each b As String In TextBox2.Text
If abc.Contains(b) Then
Dim ab As Integer = Array.IndexOf(abc, b)
[code]....
Below is the section I'm having trouble with at the moment:
Friend Sub glbHooks_KeyPress(ByVal sender As Object, ByVal e As KeyPressEventArgs) Handles glbHooks.KeyPress
newStr = newStr & LCase(e.KeyChar)
[Code]....
Neither of these worked, though the 2nd one would clean up my code a bit. Unfortunately I'm getting an "Expression expected" error on that "newStr = If..." line. I know there's supposed to be a "Then" somewhere along it but I don't know where it's supposed to be and the poster hasn't gotten back to me on that yet.
