Im trying to get the location of a picturebox on my form or say if location = (20,20) then this happens. The action performed by the picturebox is determined by its location i need some way of monitoring it
View 3 RepliesI'm trying to copy a picture from one location and paste it into another location however VB throws out the following error
Exception from HRESULT: 0x800A0046 (CTL_E_PERMISSIONDENIED)
both locations are on my local computer. So not sure what is causing the problem.
Here's the code
Module CPASU_SPC
Sub Main()
Console.Title = "MOARW Programs"
[Code]....
i want to get location of all black pixel inside the picturebox like the picture2,3 and 4 belownd here's my code
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles b1.Click
[code]......
I am making a lunar lander game that randomizes the terrain for each new game, so each game is different. For my game, I am creating a graphics object that draws a closed curve for the terrain of the game. I am trying to then detect if a picture object collides with the graphics object.[code]...
View 1 RepliesI researched this and found I had to use something called "ScreenToClient" [URL]...what I want to do is to have a picture box that I can just get the coords from easily (for example 0,0 bottom left hand corner)
So how do I get that to work? (im guessing something like comparing the picturebox size to the form size then working it out but im not quite sure how to do that.)
I was wanting to make a little game. You press a start button, and a picture moves into different spaces. If you can hit stop when the picture is in a certain spot, then you win. How do i make it so when i press the stop button, it will check to see if the picture is in the location (180, 307)?
This is what i have:
CODE:
I have a country map in a picture box with provincial divisions. I can fill each province on mouse over by calling following floodfill function on my pictureBox MouseMove event[code]...
View 1 RepliesFirst of all take a look in here :[URL]...As you can see, in the image there're 3 items.So let's talk about the first one, the first right one. (CRAYON SHORTS)I want the picturebox to move always to the left side,After it knocks the "wall" it'll re-start all the progress.So simply, I want the picturebox to move left.
[Code].
I am writing a program in VB 2010. My computer is an E Machines dual processor Intel Celeron running at 1.8 gb/sec with 2 GB of RAM. I have a 1680 X 1050 display and the graphics driver in the computer is fully capable of utilizing this display. I am running Vista Home Edition.
The purpose of the program is to analyze a large number of infrared and visible light images from the geostationary satellites GOES East and West. Note: These images are TIFF and range in size from 400 KB to 70 MB. The pixels are either 8 bit or 10 bit depending on the image type.
The program allows the user to select a series of images from a file folder. These images are then displayed in a picturebox. A map covering the same area is also available to the user. The user may then move the cursor, via the mouse, to a selected location on either the map or in a picture. With a left click that location in terms of image coordinates is used to compute the geographic coordinates of the selected location. These coordinates are then displayed for verification purposes. So far, all of this works properly.
The next thing I need to do is to determine the brightness value of selected pixels in the displayed image. Because brightness is related to temperature this permits a detailed examination of cloud temperature and density in each image. By making this measurement at several different wavelengths (provided by images taken at different wavelengths) the program will then compute the atmospheric extinction factor at each selected wavelength and from that derive the atmospheric transparency function.
Here is where I have run into problems. I cannot find a way to extract the pixel value from the selected X, Y values input either by cursor position or by direct entry. I have tried the various approaches described in the documentation but I either get errors or a pixel value that is unrelated to the image. The following is a section of code that I am currently trying.
[Code].....
i have a chart of images.. and i want to load individual images into picturebox from that chart..chart = big image, eg alphabet chart. (yes i am creating a game for my small nephew.. pictures and alphabet) now, i want to show different pieces of images into picture box. like the A box, b Box etc one option is to cut the chart into pieces, save each piece with different filename and load individual filename into picturebox.but i saw somewhere that we can use pixel location to load images into picturebox..as i recall it required two pixel location, 1 was upper left and other was lower right.. and passing that pixel locations would load the rectangular image between those pixel locations into picturebox?
View 9 RepliesI'm making a screen capturing program, and I am trying to save the image. I can do it as a 'save as' like this
save as
savefiledialog1.Title = "Save File"
savefiledialog1.FileName = "Capture"
savefiledialog1.Filter = "JPEG (*.jpg;*.jpeg;*.jpe;*.jfif)|*.jpg;*.jpeg;*.jpe;*.jfif|PNG (*.png)|*.png"
[code]....
How could I do a quick save option so that it auto saves to a certain location that the user doesn't have to choose and as a .jpg?
how I loaded my image
Dim test(100) As Image
test(0) = Image.FromFile("C: est.jpg")
now i want to put it in a picture box at location 50-50
I have a picture box and I tell it to appear on a random location on another specified larger picture box.
here's my code:
Code:
Sub P2_AppleMove()
Dim P2ax As Integer = CInt(Int((P2Foodarea.Width * Rnd()))) ' sets the random area of the food
[Code]....
P2foodarea is a large picture box I created. I only want the apple to spawn on P2Foodarea, atm, it spawns on P1Foodarea which is very weird. P1foodarea is a whole other picture box. I even made new variables as you can see P2ax and P2ay, but it still doesn't spawn on P2Foodarea. I have even tried recreating a new picture box for P2foodarea
I have a problem that I can not seem to get. I have a program that moves a picture to what ever location the user puts into the text boxes. It works as I wanted it to but my problem is when a user puts in anything but a number into the text box it gives an error, I want a message to pop up and let them know that a numbers needs to be entered not a text.
View 6 RepliesI have a form that allows me to drag and drop pictures but I want it to check if the object is in the correct location
*curpic = the current picture that has been selected
If curpic.location.X > bx1.Location.X And curpic.location.Y > bx1.Location.Y Then
If curpic.location.X < bx1.Location.X + bx1.Width And curpic.location.Y < bx1.Location.Y +
[code].....
I have developed an application where i am drawing line using the mouse like a pen (it can be of any shape) i want to save the location of the object and redraw it later using the drawn location saved on any xml or text file. Instead of saving the edited image i want to save the location only to save the space in the sql server.
View 2 RepliesI would like to know if its possible to bind the property LOCATION of an object like button.[code]So that, every time I move either the hscrollbar1 or vscrollbar1 the button1.location will change or moves the object to the location of hscrollbar1.value and vscrollbar1.value. It should happen without setting its value using the SCROLL EVENT.
View 3 RepliesI am making a program to organize grainbins in seperate yards.In this program, the grainbins need to be moved around and thier position to be saved when the program is closed. I also need to save information such as backcolour and text.I am specifically referring to GroupBoxes, OvalShapes, Textboxes, Labels, and ComboBoxes.
View 2 RepliesHow can I raise an event from another class which implements an interface that contains an event?
Public Interface IMyEvent
Event MyEvent()
End Interface
[Code].....
Note the comment - that code doesn't work. How can I raise an event like this, if it's contained within another class through an interface?
Is it possible to develop a program in vb.net which can find the location of vehicle in a cctv camera range?if possible ,what are the APIs and technologies used for it?can any one suggest any link or the steps involved in this process...?
View 5 RepliesI was wondering if there is a way of making a picture have the properties of a checkbox. I want to have clickable stars that change color (from white to yellow) everytime the user clicks on them to represent the rating they put on certain foods.
View 5 RepliesI have created a form with pictures of plants on it (note these pictures are moved to the left when the left button is pressed). When a mouse is placed over or hovers over one of these pictures i want a mini form to pop up beside the plant with the plants name on it.
[Code]...
i am using an unbound datagridview so i can dynamiclly add rows. all that is working fine. but the grid is not is the location i have coded.. i am using the defualt form as a base then coding the unbound stuff in.. should i just create a blank class file and do everything? the only problem i am having is the grid must bees in the correct location according to the pixel point that i have given it. Right now it is placing the grid at point (0,0) no matter what point is entered on the line for location. so what am i missing??????
View 3 RepliesI got a error when I run this code:
Dim btch As String
Dim LeftPart As String
[CODE]...
It says index and location must refert to a location withing string
dim cn as oledbconnection
cn = New OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=C:valid.mdb")
[code]......
I have 2 group box components and both are same size,font,location and visible is false. When i click button2, the groupbox1 won't appear(the group box2 is on bottom n group box1 is on top).
Example:
button1
groupbox1.visible=false
groupbox2.visible=true
button2
groupbox1.visible=true
groupbox2.visible=false
Because i want to show the different,so the location have a little different(actually both are same location). I think my code is no problem. The problem i guess is both component cannot locate at same location?
we have a user that my program works fine for.. and another that it just crashes for.. they get this error
"You cannot start application <App_Name> from this location because it is already installed from a different location."
then they run it up again and it comes up.. and then just closes..in reading some stuff online it says its a framework 2.0 sp 1 issue ?these pc's have 3.5, but my program uses all 2.0 stuff..so is this a 2.0 sp level issue ? or should I make my programs start to use framework 3.0 instead ?
I was using this old method of creating a bunch of rectangles when I need to get the location of a certain point within a grid so I could draw images on the grid. The thing is, I don't want to use rectangles, I want to be able to just round the location as if I were using rectangles. I need it to be able to round the point (66,70) to (50,50) so if you can imagine a grid and the mouse position being within that square in the grid, I need to get the location of the upper left corner of that square.
View 5 RepliesI have encounterd a problem when trying to re-enstall a program i have writen in vb 2008.I get the following message:"You cannot start application Shell from this location because it is already installed from a different location."This program is to be used on many workstation computers and i need to be able to update any changes by just reinstalling the program, no uninstalling needed first. If the program was installed from a cd first and needs to be updated from a flash disk this error will be a problem, if the update is from a cd as well then there is no problem.Is there a way to change the installation package to ignore where the program installs from and just update itself?
View 2 RepliesI'm currently working on a project that has a simple game . I want to change the location of a label ( middle ) to another location when a key is pressed down. But there is something wrong with the first of the If statement .I've underlined "point " because it has the error.
Private Sub Space_Navigator_KeyDown(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyEventArgs) Handles Me.KeyDown If e.KeyCode = Keys.Up Then If middle.Location = [u]Point[/u](156, 655) Then middle.Location = New Point(156, 547)
End Sub