Unable To Click A Button?
Sep 19, 2010I'm having trouble clicking a button
Here is the html code of the button:
[code]...
How would I go about doing this?
I'm having trouble clicking a button
Here is the html code of the button:
[code]...
How would I go about doing this?
So I'm trying to click a button on a site, but here's the problem, it doesn't have ID or Name, it has this
<input type="submit" value="login">
Just that, nothing else, and I'm trying to click it but it doesn't work.I used
WebBrowser1.document.GetElementById("submit").InvokeMember("click")
but it doesn't work.
I have to click a HTML button programatically which is on the 3rd page of the website . The button is without id. It has just name type and value . The HTML code of the button is given below
<FORM NAME='form1' METHOD='post' action='/dflogin.php'><INPUT TYPE='hidden' NAME='txtId' value='E712050-15'><INPUT TYPE='hidden' NAME='txtassId' value='1'><INPUT TYPE='hidden' NAME='txtPsw' value='HH29'><INPUT TYPE='hidden' NAME='txtLog' value='0'><h6 align='right'>
[code].....
I am simply trying to get to automatically click the submit button on my intranet page. I have been able thus far to input the user name and password fields, however i am unable to click submit. I keep getting some error about object required amongst others. This is the code i have thus far:
[Code]...
I want to be able to click a button on my application and the start menu appears where I've clicked. This (if possible) will replace my shell.exe. I know that with EmergeDesktop, you can show the start menu by right-clicking the desktop. How do you do that?
View 2 RepliesBelow is is an HTML form and below that, is a vb procedure, "LoginExamp" that enters in the username and password. I am unable to locate the button however and click it since it does not seem to show up as a mshtml.HTMLInputElement. "htmlInput.click()" never runs. How can I adjust the loginExamp code so that the button is clicked.
<form id="loginform" name="loginform" method="post" action="">
<input id="username" class="formfield" type="text" value="User Name" maxlength="40" name="Xusername">
<input id="password" class="formfield" type="password" onfocus="clearDefault(this)" maxlength="40" name="Xpassword">
<button class="subButton" onclick="javascript: submitform()">submit!</button>
[code]....
This is a quick mock up of what my application looks like.Trying to incorporate a progress bar. I want to be able to click "start" then the start button disappears then a progress bar shows up in its place.
View 36 RepliesUsing 2 forms how would I click one button, from another form? ie In VB 4,5,6, I would used to do it as:-
Form 1:
private sub Command1_Click()
msgbox "Say Hello"
End Sub[code].....
If I clicked the button in form2, it would automaticlly, click the button in form1. Do I, do it the same way in VB Express or has it changed?
Having problem with mouse click, this code i am testing is through vb.net 2008 express edition, i am just wrote a program my form has one web browser and button when i click the command button it click the upload-video file for uploading the video [Code] also i had no idea how to automate the video inputs(file name)into the dialog box and click save button. what i am trying to do this click upload and then input video file name do the other settings like this and the finalize the process.
View 1 Repliesmy source code in design part is:
<asp:Panel ID="Panel1" runat="server" Style="display: none" CssClass="modalPopup">
<asp:Panel ID="Panel3" runat="server" Style="cursor: move;background-color:#DDDDDD;border:solid 1px Gray;color:Black">[code]......
Ok button click is not accessing click event.
I created a button control ,, by double clicking only the process was going on,,when iam single click the button nothing is to be happenend,,so i want to change into single click insted of double click........here my coding is given below.......
<asp:Button ID="getrec" UseSubmitbehavior ="false" runat="server" Style="left: 30px; position: relative; top: 0px; z-index: 101;"
Text="Get Record" />
[CODE]...
Here the coding is all are correct but the problem is when double clicking the button only it was worked ,,,iwant want to change it into single click
i'm making some login function with some website but this website button is some different before what i know method. to login this website , first should have to some button click then drop down menu go down then can input id and password. how can i emulate click and make drop down this menu? if you go following website you can see right side 'Log in' button if click this button drop down menu go down [Code]
View 2 RepliesI have a vb.net application that uses Flash movies (AxShockwaveFlashObjects.AxShockwaveFlash). I have buttons in the flash movie. When they first start using the application, they can single click on the buttons in the flash movie and button responds accordingly. But after a while (and I haven't been able to pin-point an exact thing that changes it or my issue would be solved), the user has to double-click on the button in the flash movie for them to work.
View 2 RepliesHow can I make a program so you click a button and select a File using a OpenFileDialog and click send on your computer and it will send the file to a different computer and then a SaveFileDialog will show asking where to save the file on the other computer. Oh ya I cant use WinSock or whatever becuase im using Windows Vista 64 Bit. I need it because I for some reason cant use printer sharing. It might be because im on A 64bit Vista Machine and I want to print a file off of a 32bit XP Home Machine.
View 6 RepliesI want to create a server control that inherits System.Web.UI.WebControls.Button but gives it special capability, now what do i mean? i want my button to be a confiorm button that will work like so:
Renders to the page as a button of lets say cancel after the user clicks it i want to catch the click event (within the server control) and now after the click makeing the button not visible and makeing some kind of content placeholder (that will render from the server control) visible. that content place holder will have 2 buttons inside of it: yes and cancel. I want the programmer that adds this control to be able to register a function to the click event of the yes button. and the second cancel confirmation button should make the first button appear agian. (i know how to do this all in the client side but this time i need it all as server events)
My question is this: how do i catch the click event? i want it all to be handled inside the server control itself. so a programmer that adds this control wont have to worry about anything but just needs to register to the click event of the "yes" button.
I am writing an Automation program to control an MS Acces applcation. Here is the sequence of events:
- Load MS Access Database (Done)
- Load an MS Access form (Done)
- Take dates from Main.VB and populate 2 fields in MS Access form (done)
- Load another MS Access form called Stage_2 (Done)
- Load a file name into a filed in the Stage_2 form (Done)
- Do a click event in MS Access linked to a button called Pre_Stage_copy on Stage_2 form (How do I do these?)
- Do a click event in MS Access linked to a button called Pre_Stage_import on Stage_2 form (How do I do these?)
1. Retrieving data from an .mdb
2. Displaying the table(s) in a datagridview
3. Populating an array of structures with the table data
4. Searching the array of structures for a member value equal to a string
5. Displaying the matching array elements in a listbox.
[code] Any suggestions? Am I missing something simple? Should I be using a Multidimensional array instead of a structure?
I have a basic window that has 20 buttons (One, Two,.....,Twenty).Currently if you click on a button its background color changes, and changes back on next click.I'm looking for a way to make it so when the mouse button is held down I can drag across the screen and it will change every button I hit.Disregard the "Shut Down", "Restart", "LogOff", "Clear", and "Invert" buttons. This idea doesn't apply to them.
View 5 RepliesOne the click of a button the stopwatch starts, then on the click of a second button the stopwatch stops then states either in a msgbox the time taken between the two button clicks.
View 2 RepliesI'm having a problem with my richtextbox. I'm unable to click links in it, and if I create a new project,
Same problem. I use visual basic 2010, so maybe there's a bug in it..
i have 3 forms one stays at back alll the time and the other 2 can be launched fromt he first but when i lauch both of them it frezzes them both unable to resize or click anything on the form why is this?
View 1 RepliesWe are having problems with the speed in parts of our application, Standard .NET 4 Windows forms application. We have a ListView containing some commerce items and the user can click on items to put them in a shopping cart. The problem is that when clicking 10 times fast on one item, only 4-6 items is added to the shopping cart.I get the same result when building a simple test application with only one ListView, with one item and a debug.print in the click handler.I have tried to add a Button in the same testapplication and this is fast..[code]
View 2 Repliesi just started playing with the menu toolbars in the toolbox. neat stuff. this thread is mostly for a contextmenustrip, since i'm trying to do a virtual right click on a regular click so the context menu shows..
i would like to know how to do a virtual right mouse click, so that's primary and reason for this thread, but if there is another way to have the context menu act on any other commands, then do post..
I have a button on my form where I'm showing a ContextMenu when the user left clicks on it, I'm actually using MouseUp right now to show it.What I would like to have happen is the user click on the button, the button stays pressed while the ContextMenu shows, it returns to normal when the ContextMenu closes (Either a menu item was selected, the user hits the escape key or they click/tab to somewhere else). Also I'd like to position the ContextMenu in the lower left corner if the menu opens down or the top left corner if it opens up. So the left edge of the ContextMenu is flush with the left edge of the button.Moreso the button staying pressed until the ContextMenu is closed.
Edit: I'm also ok with this being it's own control inheriting the FW's Button that used the assigned ContextMenu as well.
the menu in the button is opened with click in the small down arrow, but NOT if click in the button image.
View 6 RepliesHow can you chnge the location of a ovalshape using button and 2 textboxes in a button click event
View 1 RepliesI am Sorry but I Can not get my head around Saving data in a Form to my records (DataBase) When I Click Button1. I know how to clear the controlls when i click Button1. How Do i start The code "Do I use a SaveFileDialog1" or "Do I Look in the property settings" how the code starts. is what i have at the moment is below. also Button1 should be able to clear the controls ready for the next user input.
[Code]...
I believe there wont be any diff if user clicks the button on the form and the click event is fired OR if we call the button click event / function in the code. Because in one my project, this does make diff. If I click the button on the form, the App works great but same button if I click it thru the form code, the whole process crashes. This happens in Vista / VB.net.
View 12 RepliesI have created a custom control that has a few labels and a button on it. In my main program i dyanmically add this control to a stackpanel. When i add the control i add a few events for it by doing th e following:
Dim newqueue As New UserControl1
AddHandler newqueue.MouseDoubleClick, AddressOf PrintMessage
How would i go about adding an event for the button.click for the button in the custom control?
I have numerous buttons on a form, one each to select a playing card (52 buttons). When the Card(button) is selected I want to highlight it by changing the border from black to Red, then if reclicked from change back from red to black, easy enough (if then else). So that I do not have to copy this code 52 times I wanted to create a module as follows:
Sub ChangeButtonBorderColor(ByRef ButtonName)
If (Equals(ButtonName.BorderBrush, Brushes.Red)) Then
ButtonName.BorderBrush = Brushes.Black
[code]....