VS 2005 Have The User Click On The Button The Button Stays Pressed While The ContextMenu Shows?
Mar 15, 2010
I have a button on my form where I'm showing a ContextMenu when the user left clicks on it, I'm actually using MouseUp right now to show it.What I would like to have happen is the user click on the button, the button stays pressed while the ContextMenu shows, it returns to normal when the ContextMenu closes (Either a menu item was selected, the user hits the escape key or they click/tab to somewhere else). Also I'd like to position the ContextMenu in the lower left corner if the menu opens down or the top left corner if it opens up. So the left edge of the ContextMenu is flush with the left edge of the button.Moreso the button staying pressed until the ContextMenu is closed.
Edit: I'm also ok with this being it's own control inheriting the FW's Button that used the assigned ContextMenu as well.
How can I set a button, so that when it is pressed, it stays in the pressed down graphic state. Then when pressed again it returns to the normal not-pressed visual.Make a button stay like this until pressed again: url....
What is code that we can use if user click next button, it will point to other page, for example if use want to register than he click button register and user we point to register page. i am using visual studio 2005 and sql 2005.
I have a coding to let user select 2 files to import:
------------------------------------------------------------------- Private Sub btn_Browse_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdBrowse1.Click On Error Resume Next OpenFileDialog1.Filter = "Lis files|*.lis" OpenFileDialog1.FilterIndex = 1
[code]....
But if user click cancel button at Browse2 button, the system will paste the value from Browse 1 to Browse 2 text box.How to do nothing if user click cancel button at OpenFileDialog?
I have a GUI with a few button on it and each button start an application. I want to prevent the application to start twice if the user double click on the button. How can I do that?
I believe there wont be any diff if user clicks the button on the form and the click event is fired OR if we call the button click event / function in the code. Because in one my project, this does make diff. If I click the button on the form, the App works great but same button if I click it thru the form code, the whole process crashes. This happens in Vista / VB.net.
How to fix the error in code..this code will always display msg box if user select ot nt slect the checkbox .. but i want if user doesn't select any of the checkbox or forgot to select checkbox then msg box will ppear other wise redirect to other page ..
I'm creating a web browser and I was wondering how I could make a button click cause the enter key to be pressed after without having to do it yourself on the keyboard.
Private Sub Button6_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button6.Click End Sub
is there anyway i can randomly call up even numbers like i have a label (label1) and button (button1) i want to click on the button and it shows EVEN NUMBERS on the label at random?
On an form i have few labels, upon clicking on that labels i want to display an another form which contains 3 textboxes(Default,Current,New) and 3 buttons(Default,Current,new). I need to save the values of all the textboxes to the label's tag, but the label's text will contain the value of the textbox based upon the button which is pressed. i.e if 'Default' button is pressed then the 'Default' textbox text should be the label's text. I have created a class with three mem. variables to the save these class objects in the labels tag. But how should i know which button was pressed.
I'm working with ASP.NET and VB.NET. I have a page which contains 5 user controls. the page itself does nothing, it just presents the user controls to the user.
The user controls work fine when I come on the page, or when I refresh, but when I go to another page, and press 'Back' only two of my user controls shows up, and they don't work like they're supposed to!
Short description of the controls:
2 controls which look if the user has to create something and shows an option to do so. (goes to the DB) 2 controls show an overview if needed (goes to the DB)1 control looks if the user is an admin (does not go to the DB, but looks in the securityContext)
I need to create a program that when I click a button it shows a sentence (took it from a list) random. But after it have to delete the sentence from the list 'cause we dont want to read it again I don't know so much about VB so I'd like some help!
I am making a program that calculates various results with variables entered by the user. What I am trying to do is incorporate a function that will allow the user to switch from metric to imperial easily but only when the ok button is pressed. Now I got all the coding done for the metric and everything is working fine. My problem is when I use the radiobuttons to switch the entered variable in the text box to the desired unit it gives me a 0 or a random number in the textbox...
I also have labels indicating each variables unit which I easily managed to change with the text box using this code. : 'Change Labels to Metric lblMDegreeC.Text = "Degree C" lblMDegreeC2.Text = "Degree C" lblMmm.Text = "mm" lblMmm1.Text = "mm" lblMmm2.Text = "mm" lblMm.Text = "m" lblMm2.Text = "m" lblMm3.Text = "m" lblMDegreeC3.Text = "Degree C"
I created all the coding to convert the metric variables to imperial. My problem is changing the textbox text when the user switches the units during run time. The labels change without a problem but the textbox never works. I have attached the coding for the file.
I just want a program compiled in Visual Basic 2008. which can just submit a form of only one field. the form is already uploaded to the server but i don't want to go to that url every time to do so.What I want here, just to open application and fill that field and submit. Is this possible in visual basic 2008?Also let me know how to create a button that can rapidly submit the form repeatly untill the second button named cancel is pressed. field name of that form is "msisdn" and the action on submit button is post method and url in target is url...
I have a vb.net application that uses Flash movies (AxShockwaveFlashObjects.AxShockwaveFlash). I have buttons in the flash movie. When they first start using the application, they can single click on the buttons in the flash movie and button responds accordingly. But after a while (and I haven't been able to pin-point an exact thing that changes it or my issue would be solved), the user has to double-click on the button in the flash movie for them to work.
I am using the media player control in my VB2010 project and hit a problem. I want to detect when a user has pressed the "next " button on the media player console.I can use the following code to detect the pause, play, fast forward, etc but I do not see anything that will detect when the "next" button is pressed.
I am trying to do the following check to see if the user presses the Cancel button or the exit application (X). But for some reason it is not working. Can anyone let me know what am I doing wrong?
CheckCancel If NewStationInfo.CancelButton.DialogResult = Windows.Forms.DialogResult.OK Then do sometheing
I need to ensure that the user can only click the button (to acknowledge the message) and not do anything else (like clicking another button). How can I do that?
I want to show the contextMenu on MenuItem right click....AS IE favorites.... I am able to show the contextMenu when I right click on menu. But the Probs is that when I right click..Context menu is showing & menu is hiding. I want that when we right click on menu. Menu is not hidden.
Private Sub MenuAddToFavorites_MouseDown(ByVal sender As Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles MenuAddToFavorites.MouseDown If e.Button = Windows.Forms.MouseButtons.Right Then ContextMenuFavorites.Show(DirectCast(sender, ToolStripMenuItem).GetCurrentParent.PointToScreen(e.Location)) End If End Sub
I have a simple form that works fine with a button click and the code generated by VB for Button1_Click event.But I want to make the user have to double click the button, So I just modified to: [code]This compiles but nothing happens when you double click.What am I not doing to get this to work?The problem is that if you click the button and the form is the focus, then if you hit the enter key it fires the event (when you didnt want to)
I'm creating a CD that when inserted into a CD-Rom will AutoRun, which brings up the program starting with a splash screen, then the first window form. All this works, no problem. On the first window form I have a button (one of many) all buttons work (so far) except this one button. (I actually haven't test3d the buttonjs to see if they work on / from a CD yet, but they work in Debug).
I would like to have the user click the button, and have that button be tied to a zip file or an exe file that is in a folder on my CD, that will be downloaded to the user's computer. I would like the usual window to come up asking the user where the user would like to save the file, the user will choose the folder, click the save button and the file downloads from the CD to the hard drive of the user's computer, so the user can open it later. It doesn't have to Run from the CD, it is just to download to be accessed later.
Some files will be a Zip and others are Exe files that I would like to have downloaded to the user's PC by way of a button click. Of course the user's computer will need to be able to know which drive the CD is in.
This is what I've tried and doesn't seem to work...Have not tried it from directly from CD (Haven't tried anything directly from the CD as of yet, but after this problem my next step is try and make a AutoRun CD and test the program).
I'll start another post for How to Make my Program ready for a CD. I think it may involve Publishing...but publishing only made a setup.exe, which is Not what I want.
