I have a form with a textbox on it. Validation occurs on the leave event. If validation fails, the focus is set into the textbox, making it impossible to click outside it unless there is a valid value entered. A valid value is anything from 15.00 to 99.99 inclusive, always with two decimal places.What code will return a boolean answer that checks if the input is valid?
View 3 Replies
Problem: Using the sub routing below, when adding a value to another value the results eventually change from 2-decimal places to multiple decimal places.Basically, the amount stored should always only be 2 decimal places, because the values passed in are always 2 decimal places. Output from calling the sub routine multiple times.
Running total = 329430.75
New Withheld Amount = 710.79
Running total = 330141.54
[code]....
As a workaround, I have a new routine that uses a custom round function to properly store only 2 decimal places - as the VB round function does not perform the type of rounding desired.I understand that we are removing the value from the dictionary and adding it back..
What is the cleanest, most readable way to String.Format a decimal with the following criteria
start with a sign symbol (+ or -)
a fixed number of fraction digits
no decimal separator
right aligned
pre-padded with "0"'s
I have constructed my program. I had my price variable originally set to integer, but I found this was causing me errors as the numbers were just being rounded to the nearest 10 and not the exact decimal place.
I have since changed the variable to a decimal and now see this in the errors box, how do I elminate this error?"A first chance exception of type 'System.ComponentModel.Win32Exception' occurred in System.dll"
Secondly, it is producing the correct price but only to one decimal place. How do I get it so it displays the price to two decimal places?
How do I round my values to 2 decimal places in a datagridview.
I have a value column that is picked up from a SQL Server datafield type Money. In the database this sits as I want it to appear in the datagrid with 2 decimal places. In the datagridview it shows with 4 decimal places.
how do I limit a numeric value (Integer type Array) to only show 2 places after the decimal ? ie: 25.00 and not 25.00175?
View 7 RepliesHow would I go about rounding up decimal numbers to the nearest 2 decimal places? For example $7.0000032 would be $7.01 In theory, VB would make it $7.00 but if it is > $7.00, I want it to reflect that to the nearest penny... so $3.0000001 would be $3.01
View 5 Repliesthe first is validating numeric input in a textbox to make sure it's got two decimal places. I think this should be really simple, but I'm totally missing it.The second is adding an extra summary line to a listview. I have it working with all the data required, but I need to add an extra line at the end showing some totals. How do I do this?
View 10 RepliesIs there a way in VB .NET to have a decimal variable with 40 decimal places?
View 3 RepliesI am trying to write a code for a curency convertor.The result from multiplying the amount by the exchange has to be to 2 decimal places in order to convert it into Pounds and Pence.
Dim Currency As String
Dim Exchange As Decimal
Dim Amount As Integer
Dim Result As Decimal
Currency = txtCurrency.Text
Exchange = txtExchange.Text
Amount = txtAmount.Text
Result = Amount * Exchange
lblOutputMessage.Text = Result
Mod Edit: When you are posting code please use code tags like this.
Using Visual Studio I'm using TextRange processing a word at a time, parsing for figures and minus values etc. All of which works. However I have to honour the original number of decimal places in the figures, even though they may be 0's.ie -1219.0 and 1219.00 are both valid inputs the valid outputs would be(1,219.0) and 1,219.00, I can't just use tostring and stamp all of them as "N2" etc).I have to format including retaining the trailing 0 if necessary.I can use "#,##0.######" but that removes trailing 0's... ie both above example would be changed to 1,219 pos or neg.
View 2 RepliesHow can I convert the Tax in the following code which is Double to a two decimal place figure[code]...
View 8 RepliesHow do I check how many decimal places does a number have in VB.net?
For example: Inside a cicle I have an if statement and on that statement I want to check if a number has 4 decimal places (8.9659)
I used math.round(decimal, 2) in the hope that it would give me two decimal places.
But when the last digit is 0 VB 2008 doesn't display it. I get "1.3" instead of "1.30"
How do I force it to give me 2 decimal places in the rounding from the decimal?
My computing teacher challenged me to write a console program in Visual Basic.NET which would calculate π, AKA Pi, to 14 decimal places. I contemplated various algorithms, then settled for a variant of Leibniz's series which would converge rapidly whilst being simple to implement.After about 30 minutes or so of programming I had finished my program which could generate the first 14 decimal places of π in a mere 27 iterations, below is the source code:
[Code]...
However, to my dismay, I soon discovered that this was all my program was capable of because of the IEEE specifications for numbers, although I've heard of people generating π to thousands of decimal places using unmodified Personal Computers so if you could tell me how I should modify my code to work around this to generate say 500 more decimal places.
I want to format a number ex: 279388242 output 2,793,882.42
View 1 RepliesAt the end of a calculation Pweight stores a number, I need to format this number so that it only shows to 2 decimal places.. I have tried this:
[Code]...
This actually seems to make it miss calculate, so I've put it back to Pweight.ToString() and left it at that but I get around 12 decimal places.
I have designed a unit converter that converts between different units. The value and unit to be converted from are entered in the first text box, for example "1 km" and the unit to be converted to is entered in the second text box. Then after pressing the calculate button, the new value will be displayed in the second text box as the output. By default the output will be specified to two decimal places. However, if the input has any number of decimal places, for example "1.045 km" the output should be displayed to the same decimal place, in this case 3.Displaying the output to two decimal places was easy enough to figure out, I just used:
FormatNumber(finalValue, 2)
But I'm completely stuck on the other part however and I'm wondering if anyone here has any suggestions. I thought about doing something like this:
[code].....
I've been trying get rid of decimals on a number, but I need the whole number, so I can't have it rounded. I've tried .ToString and Format(), but without any luck.
View 3 RepliesI am making a conversion program. When I try to convert 6 mm to km for example, the output number says 6E-06. Here is the line of [code]...
View 8 RepliesI have a field in datatable .If 1000 is the value in it, i want to display it as 1000.00.Then if user changes to 1000.50 it should display as it is.Is there anyway to do this?
View 4 Repliesin my application there's Textbox1.text, Textbox2.text, Textbox3.text and Button1.
my code is:
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
TextBox3.Text = Val(TextBox1.Text) / Val(TextBox2.Text)
End Sub
End Class
correct syntax to format decimals. I want 2 decimal places even if the result is an even number i.e. I want 40 to show as 40.00 and 40.6666667 to show as 40.67.
View 8 RepliesI am making a simple unit converter, and wanted the user to specify the number of decimal places to be displayed for the results.
The user selects which conversion they want to perform from another combo box, and I have a select case to decide the calculation needed. Eg.
Select Case cboUnitType.SelectedIndex
Case 0 'grams to ounces
lcUnit2 = lcUnit1 * CSng(0.00220462262)
[Code].....
I'm trying to compare Office version numbers in vb.NET How can I determine if: 12.0.64 is greater or less than say 12.0.62 or 14.0.4762 It seems the fact that there is 2 decimals, vb doesn't like it.
View 1 Repliesi am very sorry for the inconvnience. this is my first post... i have downloded this souces code version of (VB6) . i want to convert to vb.net 2005 or vb.net 2008[u]..... i think this function usefull for others also. i am try to develop Payment system. i will post it after complete. there are so meny controls. i need this one also add to my Payment System.... Text Box Keypress event is not compatibal with Vb.net..
[Code]...
OK, I've got my program that works perfectly, however it is displaying the total from the calculations to multiple amounts of decimal places. If there a way to limit the value that is being displayed down to say 2 decimal places??
View 5 RepliesI'm a noob, so please bear with me. I'm working with VB in Visual Studio 2008. I have an application that displays dollar amounts. With the application installed on my desktop all of the dollar values display with 2 decimal places. However, after moving the application to the server and executing from there, trailing zeroes after the decimal point are lost.
For example - 7.00 displays as 7 - 10.60 displays as 10.6 I'm guessing there's an options file somewhere that determines how these numbers are displaying but I have no idea what that file might be.
Can someone tell me how to get both digits following the decimal point to display all of the time?
I am writing a basic math program where some textboxes are input and some are result data. I would like the result data to be limited to 2 decimal places.
[code]...
how to limit number into 2 decimal places sample when i got number of 1000.7585545 is should be 1000.76 i have this code below but based on the given sample it will result to 1001.00
If txtpassPrice.Text <> "" Then
Dim dblTranspo As Double
dblTranspo = txtpassPrice.Text
txtpassPrice.Text = Format(dblTranspo, "#,##0.00")
End If
i tried this one but i will result to 1001 only
If txtpassPrice.Text <> "" Then
Dim dblTranspo As Double
dblTranspo = txtpassPrice.Text
txtpassPrice.Text = Format(dblTranspo, "#,##0.##")
End If
