How would I go about rounding up decimal numbers to the nearest 2 decimal places? For example $7.0000032 would be $7.01 In theory, VB would make it $7.00 but if it is > $7.00, I want it to reflect that to the nearest penny... so $3.0000001 would be $3.01
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I've been trying get rid of decimals on a number, but I need the whole number, so I can't have it rounded. I've tried .ToString and Format(), but without any luck.
View 3 RepliesWhat is the cleanest, most readable way to String.Format a decimal with the following criteria
start with a sign symbol (+ or -)
a fixed number of fraction digits
no decimal separator
right aligned
pre-padded with "0"'s
I'm very new to VB 2008 and I need to round the result of a calculation to three decimal places after using a button click to complete the calculation. I've tried the Round function to no avail.
View 16 RepliesI have constructed my program. I had my price variable originally set to integer, but I found this was causing me errors as the numbers were just being rounded to the nearest 10 and not the exact decimal place.
I have since changed the variable to a decimal and now see this in the errors box, how do I elminate this error?"A first chance exception of type 'System.ComponentModel.Win32Exception' occurred in System.dll"
Secondly, it is producing the correct price but only to one decimal place. How do I get it so it displays the price to two decimal places?
How to i roundup a double number to 6 decimal places in vb.net?
View 1 RepliesProblem: Using the sub routing below, when adding a value to another value the results eventually change from 2-decimal places to multiple decimal places.Basically, the amount stored should always only be 2 decimal places, because the values passed in are always 2 decimal places. Output from calling the sub routine multiple times.
Running total = 329430.75
New Withheld Amount = 710.79
Running total = 330141.54
[code]....
As a workaround, I have a new routine that uses a custom round function to properly store only 2 decimal places - as the VB round function does not perform the type of rounding desired.I understand that we are removing the value from the dictionary and adding it back..
How can I make it so that decimal numbers round up or down to the nearest integer?
View 3 RepliesI have a series of text boxes with numbers. They are an array called txtBF(0 to 16). I am trying to take the value that is to be displayed in the text box and make it have only one decimal place. I have tried using this code below but I keep getting an error message Run Time Error 13: Type Mismatch.
txtBF(11).text = Round(txtBF(11).text, 1)
and I have also tried this
txtBF(11).text = Math.Round(txtBF(11).text, 1)
I'm trying to compare Office version numbers in vb.NET How can I determine if: 12.0.64 is greater or less than say 12.0.62 or 14.0.4762 It seems the fact that there is 2 decimals, vb doesn't like it.
View 1 RepliesI'm a noob, so please bear with me. I'm working with VB in Visual Studio 2008. I have an application that displays dollar amounts. With the application installed on my desktop all of the dollar values display with 2 decimal places. However, after moving the application to the server and executing from there, trailing zeroes after the decimal point are lost.
For example - 7.00 displays as 7 - 10.60 displays as 10.6 I'm guessing there's an options file somewhere that determines how these numbers are displaying but I have no idea what that file might be.
Can someone tell me how to get both digits following the decimal point to display all of the time?
how to limit number into 2 decimal places sample when i got number of 1000.7585545 is should be 1000.76 i have this code below but based on the given sample it will result to 1001.00
If txtpassPrice.Text <> "" Then
Dim dblTranspo As Double
dblTranspo = txtpassPrice.Text
txtpassPrice.Text = Format(dblTranspo, "#,##0.00")
End If
i tried this one but i will result to 1001 only
If txtpassPrice.Text <> "" Then
Dim dblTranspo As Double
dblTranspo = txtpassPrice.Text
txtpassPrice.Text = Format(dblTranspo, "#,##0.##")
End If
I want to use numbers with a precision of hundreds of decimal places.
I know of the BigInteger datatype for ints, but System.Numerics falls short beyond the decimal.
How can I achieve anything beyond a simple Decimal/Double precision in vb.net?
Is there a way in VB .NET to have a decimal variable with 40 decimal places?
View 3 Repliesformat number to hower many number on left of decimal and 1 decimal without rounding
View 2 RepliesI have read about Round() and MidpointRounding.ToEven but I still could not figure how to use it to achieve what I want. I have numbers (usually from 5 digit decimal) such 125.36 , 125.10, 125.99. I want to make the 2 decimal point rounded to the nearest 20. Means, the 2 decimal point should be either .00 or .20 or 0.40 or .60 or 0.80 only.
125.36 should be 125.40 : 125.10 should be 125.00, 125.99 should be 126.00
125.54 should be 125.60 and so on
Is there math function to make or I should parse the number as text and test the last 2 digit?
I'm creating a maths program and when it comes to division it's giving me .34216 as answeres which isn't what I want.I was thinking declaring the textbox the answer appears in as a single.It's not working out though and it's still using decimal points.I was told by my teacher to declare it as an integer so I tried that too, it's not working out also. I figured based on the code, I would be declaring array3() as the single or integer since that's the textbox the answer will be output into. [code]
View 2 RepliesIm working on a program that is about to drive me nuts figuring out how to round and show only 3 or 4 numbers past the decimal placement and also show the scientific notation.
Here is an example of the code.[code...]
The problem here is that most of these calulations turn up so long that my text boxes just show a small portion of the answer. I have really investigated rounding and decimal placement but nothing seems to work...does anyone have a solution?
I have a bit of code that returns some stupidly long number, and i need it to round up or down to 2 decimal places. I've looked online but I dont really understand much of it (I'm still learning!).
Code:
shill = txtshill.Text * 5
pen = txtpen.Text / 2.5
[code].....
I am trying to write a code for a curency convertor.The result from multiplying the amount by the exchange has to be to 2 decimal places in order to convert it into Pounds and Pence.
Dim Currency As String
Dim Exchange As Decimal
Dim Amount As Integer
Dim Result As Decimal
Currency = txtCurrency.Text
Exchange = txtExchange.Text
Amount = txtAmount.Text
Result = Amount * Exchange
lblOutputMessage.Text = Result
Mod Edit: When you are posting code please use code tags like this.
Using Visual Studio I'm using TextRange processing a word at a time, parsing for figures and minus values etc. All of which works. However I have to honour the original number of decimal places in the figures, even though they may be 0's.ie -1219.0 and 1219.00 are both valid inputs the valid outputs would be(1,219.0) and 1,219.00, I can't just use tostring and stamp all of them as "N2" etc).I have to format including retaining the trailing 0 if necessary.I can use "#,##0.######" but that removes trailing 0's... ie both above example would be changed to 1,219 pos or neg.
View 2 RepliesI want only 2 digit after decimal point WITHOUT rounding..but format function return value after rounding u can try
Format(0.016,"0.00")
this return "0.02"
but i want "0.01"
OR any function which can use instead of 'format'..?
How can I convert the Tax in the following code which is Double to a two decimal place figure[code]...
View 8 RepliesHow do I check how many decimal places does a number have in VB.net?
For example: Inside a cicle I have an if statement and on that statement I want to check if a number has 4 decimal places (8.9659)
I used math.round(decimal, 2) in the hope that it would give me two decimal places.
But when the last digit is 0 VB 2008 doesn't display it. I get "1.3" instead of "1.30"
How do I force it to give me 2 decimal places in the rounding from the decimal?
My computing teacher challenged me to write a console program in Visual Basic.NET which would calculate π, AKA Pi, to 14 decimal places. I contemplated various algorithms, then settled for a variant of Leibniz's series which would converge rapidly whilst being simple to implement.After about 30 minutes or so of programming I had finished my program which could generate the first 14 decimal places of π in a mere 27 iterations, below is the source code:
[Code]...
However, to my dismay, I soon discovered that this was all my program was capable of because of the IEEE specifications for numbers, although I've heard of people generating π to thousands of decimal places using unmodified Personal Computers so if you could tell me how I should modify my code to work around this to generate say 500 more decimal places.
I want to format a number ex: 279388242 output 2,793,882.42
View 1 RepliesAt the end of a calculation Pweight stores a number, I need to format this number so that it only shows to 2 decimal places.. I have tried this:
[Code]...
This actually seems to make it miss calculate, so I've put it back to Pweight.ToString() and left it at that but I get around 12 decimal places.
I have designed a unit converter that converts between different units. The value and unit to be converted from are entered in the first text box, for example "1 km" and the unit to be converted to is entered in the second text box. Then after pressing the calculate button, the new value will be displayed in the second text box as the output. By default the output will be specified to two decimal places. However, if the input has any number of decimal places, for example "1.045 km" the output should be displayed to the same decimal place, in this case 3.Displaying the output to two decimal places was easy enough to figure out, I just used:
FormatNumber(finalValue, 2)
But I'm completely stuck on the other part however and I'm wondering if anyone here has any suggestions. I thought about doing something like this:
[code].....
I am making a conversion program. When I try to convert 6 mm to km for example, the output number says 6E-06. Here is the line of [code]...
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