I want only 2 digit after decimal point WITHOUT rounding..but format function return value after rounding u can try
Format(0.016,"0.00")
this return "0.02"
but i want "0.01"
OR any function which can use instead of 'format'..?
validation for , allow only 2 digit after decimal point in TextBox in vb.net eg 150.25
View 3 RepliesHow to set run time Masktextbox mask to allow only 1 or 2 digit(number) After decimal point , run time in vb.net
View 1 RepliesI have constructed my program. I had my price variable originally set to integer, but I found this was causing me errors as the numbers were just being rounded to the nearest 10 and not the exact decimal place.
I have since changed the variable to a decimal and now see this in the errors box, how do I elminate this error?"A first chance exception of type 'System.ComponentModel.Win32Exception' occurred in System.dll"
Secondly, it is producing the correct price but only to one decimal place. How do I get it so it displays the price to two decimal places?
How would I go about rounding up decimal numbers to the nearest 2 decimal places? For example $7.0000032 would be $7.01 In theory, VB would make it $7.00 but if it is > $7.00, I want it to reflect that to the nearest penny... so $3.0000001 would be $3.01
View 5 RepliesI was wondering how i can get as far as the second point in a Double. I have a double that will contain a number such as 12.98 but when i try to show it in a textbox it shows as 12.98000000000000000 I know this is because its double but im unsure about to to retrive only as far as the .98 and get rid of all the 00000000000000
View 2 Repliesformat number to hower many number on left of decimal and 1 decimal without rounding
View 2 RepliesintLoginTime = txtLoginTime.Text
intLogoutTime = txtLogoutTime.Text
[CODE]..........
The problem is that the numbers seem to round after the decimal point, so if I entered a login-time of 8.15 and log-out 9.30, instead of showing 1.15 as the difference, it shows '1'. is there a way around this?
I'm having some trouble converting a double to a string.I have a double value, like 43.64 and I need a string like this: "43.64"If I try to convert the double to a string I always get "43,64" what doesn't work for me..
View 5 RepliesI've been trying get rid of decimals on a number, but I need the whole number, so I can't have it rounded. I've tried .ToString and Format(), but without any luck.
View 3 RepliesIm working on a program that is about to drive me nuts figuring out how to round and show only 3 or 4 numbers past the decimal placement and also show the scientific notation.
Here is an example of the code.[code...]
The problem here is that most of these calulations turn up so long that my text boxes just show a small portion of the answer. I have really investigated rounding and decimal placement but nothing seems to work...does anyone have a solution?
I have a bit of code that returns some stupidly long number, and i need it to round up or down to 2 decimal places. I've looked online but I dont really understand much of it (I'm still learning!).
Code:
shill = txtshill.Text * 5
pen = txtpen.Text / 2.5
[code].....
I would like to covert a 4 digit hexadecimal code point to UTF8.
For example:
4e00 to δΈ€
Dim s1 As String = Char.ConvertFromUtf32(&H28E02)
I don't think they are built for my 4 digit code though.
I'm very new to VB 2008 and I need to round the result of a calculation to three decimal places after using a button click to complete the calculation. I've tried the Round function to no avail.
View 16 RepliesHow to i roundup a double number to 6 decimal places in vb.net?
View 1 RepliesI have a series of text boxes with numbers. They are an array called txtBF(0 to 16). I am trying to take the value that is to be displayed in the text box and make it have only one decimal place. I have tried using this code below but I keep getting an error message Run Time Error 13: Type Mismatch.
txtBF(11).text = Round(txtBF(11).text, 1)
and I have also tried this
txtBF(11).text = Math.Round(txtBF(11).text, 1)
I just finished this application where you enter a five-digit credit card number, with the fifth digit being the check digit. everything seems to work except, I can't seem to get it to determine that any number is "valid". Every 5-digit combination that I enter returns "The credit card number is not valid". Im using visual basic 2008 express
[Code]....
How to get the second decimal point?
View 7 RepliesI have a value that shows a integer value between 0-100. For a little math, I need to be able to add a decimal in front of the value. So if the value was 50%, I need it really to be .50%.
View 4 RepliesHere is the code in C# to allow only one decimal point in a textbox:
if textbox5.text.contains(".") && e.keychar="."
{
e.handled=true
}
I have to use it in VB.NET 2003 version, but I can't use the contains property. How can I do this?
what is the code for decimal point in vb calculator?
View 2 RepliesI am trying to move some data from an Excell sheet to an AS/400 file.
I have my app working, in that, the data is getting to the correct table, but the problem I'm having is that one of the columns in the spreadsheet contains numbers ie; 1234.55
I need to get that to the AS/400 as 123455 in a text field.
Currently I am moving the data from one dataset to another as follows.
Dest_DS.Tables(0).Rows(i).Item(0) = Data_DS.Tables(0).Rows(i).Item(0)
I think what I need to do is seperate the whole number from the decimal and then concatenate the values. ?Not sure how to.
Also, some of the values in the spreadsheet may end in a zero such as 1234.50 but only show the 1234.5 so even fnding the decimal and then taking the next two characters won't always be correct.
How to add decimal point (with two decimal places) to string, without converting string to decimal? For example (Dim str1 as String), regardless str1 has value: 100 , 100.0 , 100.00, or 100.5 , 100.50..I'd like to get the output: 100.00 or 100.50, with two decimal places.
View 3 RepliesBasically in my in my aspx page I have a gridview which displays the value from my database as an image. So if a value in my database table is 5, it will be displayed as 5 images in the gridview. ie.(star.jpg star.jpg star.jpg star.jpg star.jpg)The code:
Protected Function getrating(ByVal rate As Integer)
Dim getrating As String
getrating = ""
[code].....
Way to find out the numbers after the decimal point of the double?All i need to do is to find out if the number ends in 0 like 1.0 or 10.0 or 323.0 ?
View 6 RepliesFor some time I try to get the comma instead of the decimal point, but the labels I use won't display a comma. For some reason I don't understand, the msgbox() does the trick, but is useless in my application. This is my last desperate piece of code I tried but it also failed.
Expresserprijs = EuropluscolNL(ArrayCol, 2) - EuropluscolNL(ArrayCol, 1)
' All above are "Doubles" and are fed with data like 21,45 (with comma's that is)
Decimaalteken = Expresserprijs
' Decimaalteken is a string
MsgBox(Decimaalteken)
[Code] .....
I'm making a sciene program so I want to draw the graphic with decimal size and location. But the parameters are always integer, not decimal or double. Can I do that?What is big but light?
View 3 RepliesI am trying to think of a possible way to insert a colon and decimal point to a part of a number. I am making a Rubik's Cube timer, and I converted the times to milliseconds so I can calculate the average of 5 with that. I averaged the milliseconds, but now I need to convert that into minutes, seconds, and milliseconds. Does anyone have any idea on how I would go about this?
View 2 RepliesI have a problem which is that Class Big integer Doing a miscalculation
For example: -
5 / 2 = 2.5
With Class
5 / 2 = 2
I want to do to show the numbers after the decimal point (.5)
I have read about Round() and MidpointRounding.ToEven but I still could not figure how to use it to achieve what I want. I have numbers (usually from 5 digit decimal) such 125.36 , 125.10, 125.99. I want to make the 2 decimal point rounded to the nearest 20. Means, the 2 decimal point should be either .00 or .20 or 0.40 or .60 or 0.80 only.
125.36 should be 125.40 : 125.10 should be 125.00, 125.99 should be 126.00
125.54 should be 125.60 and so on
Is there math function to make or I should parse the number as text and test the last 2 digit?