VS 2008 Remove Last Character From A String?
Aug 14, 2010i have a string like this sravani/i want to remove last character '/' in the above string...which function can i use?
View 3 Repliesi have a string like this sravani/i want to remove last character '/' in the above string...which function can i use?
View 3 Replies[Code]...
For each character of this string I want a new character out of the string and then remove the character from the list of characters that still maybe used for other characters. It may not get the same character, you could basically just call this encryption, but it's not what I am making. I don't want to waste my time doing this one hour while VB can do this for me in <1 second.
I have a string like this sravani/, asdfff/, lsdsf/. I want to remove last character '/' in the above string...which function can I use?
View 4 RepliesI am trying to remove a last character of a string. This last char. is a newline (system.environment.newline)
I have tried some things but I can not remove it.
Example:
myString.Remove(sFP.Length - 1)
Example 2:
myString= Replace(myString, Environment.NewLine, "", myString.Length - 1)
How I can do it?
I am trying to remove everything AFTER a specified character in a string. The string is just the Environ("username") and the local machine's IP address separated by a colon. IE username:127.0.0.1.. I have tried everything I could possibly think of in the last hour to do this with one or two lines of code and can't wrap my head around it.
View 3 RepliesHow do I get the last charactor of a string, and remove it from the string? I know all the rules about 'We won't do your homework'.
View 2 Repliesthis would be my string Panipat,Patna,Result should be Panipat,Patna,Panipat,Patna,Result should be Panipat,Patna Panipat,Result should be Panipat,Panipat,,Result should be Panipat How can i do it
View 3 RepliesDim str as string = xxxxxxxxxxxxxxxxxxxx£xxx£xxxx**£**xxxxxxxxxxI want to remove £ in the bold which is always at certain position (11th for instance) from the end. The whole string is a long one, always change in size and can't be counted from the start. Can't use Replace as well, there may be same characters at other positions that I don't wish to remove.
View 4 RepliesMy project is scanner for example.
[code]...
if listbox in same url then don't add listbox only one url stay
I'm trying to build a list that will be used as the in clause of a select statement. The requirement is to have the user enter a comma separated list of descriptions. Each description can contain spaces so I can't remove the spaces before splitting by comma to add the single quotes around each description. I want to remove all white space after a single quote since no description will start with a space. What's the best way to do this in VB.NET? Regular expression or a string function? Here's what I have so far.
[Code]...
How can I remove the first character from a text string?
View 7 RepliesI want to know if there is an easy and short way to remove all characters except for numbers and decimals from a string. Either that or have a textbox that will only except numbers and decimals, but not a masked textbox.
View 2 RepliesI have MIDNAME column in my table. I want to remove all the character starting from the second character going to the right and after removing it, a period "." will be added right after the letter which left. How do I it?
View 6 RepliesI am writing a hangman type game and I am displaying the word to the user in a label as all *'s, but I cannot figure out how to have just one of the *'s changed in the label to the correct letter when the user inputs the correct letter into the text box and clicks the check letter button.Everything else in the program works perfectly, except for this part.[code]When I use the .Replace it changes all of the *'s to the correct selected letter.
View 2 RepliesIn a rich text box I have a lot of lines of text, all of them have the same pattern:
12345 - Something here - something else here
65474534 - stuff here - random crap here
The number of words/numbers varies from line to line. What I'm trying to do is remove the third part, so the result would be:
12345 - Something here
65474534 - stuff here
I've tried using many variations of Split(), but since the number of words varies it doesn't always split it correctly. Also It doesn't seem to go down the lines of my rich text box, and it just sticks with the first like?
how to trim the first character of a string? I found some examples on how to trim the end or how to trim spaces but nothing on trimming a character off the front.
View 3 Repliesthe coding is to 'Get input string and put its character into List, and replace the character with other.'but having problem putting each character into List and also replacing it,[code]
View 2 RepliesI have problems sending sms using API. I need to sens sms encoded ISO-8859 The problem is encoding to ISO. Not runs
[Code]...
I've been working with the substring command and after coding up all the things I needed it to do, I saw a post on here where the "For Each" statement was used basically to do the same thing.Lets say we just want to take a string apart one character at a time and add each character to a label. Which would be more efficient?I made a cheap example to show ...
Code:
ABinary = "0110 1100 0001 1011"
For x = 0 To Len(ABinary) - 1
[code].....
when saving the "conversion failed when converting datetime from character string" is displayed.
Private Sub BtnSave_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles BtnSave.Click
Try
Dim cn As New SqlConnection(ConnectionString)
cn.Open()
[code]....
Currently I have this code in my app:
Dim parts As New List(Of String)(ListBox2.SelectedItem.ToString.Split(""c))
Dim myArr(1) As String
myArr(0) = parts(0)
parts.RemoveAt(0)
myArr(1) = String.Join("", parts.ToArray)
MsgBox(myArr(1))
MsgBox(myArr(0))
As you can see it splits from left to right.Can anyone help me update the code to read the string RIGHT to LEFT and remove everything read till it finds the FIRST "" and display in msgbox?
when saving am getting this error"undiscclosed quotation mark after the character string')'.incorrect syntax near ')'.I used the command in other codes which working perfectly. [code]...
View 10 RepliesI was wondering if anyone could help me with the following problem:
I am working with a csv file (it contains two columns of numbers), which as a last character has a comma and I would like to remove that comma from the file.
I have a text file and i want to remove all the last character in each line how could i do that?
View 3 Repliesif i have a textbox called textbox1 and there is some text in it, is there a way to remove the last character in the textbox?
View 10 RepliesI need to remove some content from string.
dim id as string ="TabContainerContent1_Basic_MyFirstName"
I need to remove TabContainerContent1_Basic_ . The fix is TabContainerContent1, it is under loop so always _Basic_MyFirstName will be changing. I need to get the text after the last _ char.
How would I remove before a string e.g. If I wanted to removed before "the" in "this is the test" it would leave me with test.
View 5 RepliesI want get the most specific from the current url in visual basic .net.I've tried several code but it just was the same.I have this code:
Dim CurrentURL1 As String = Request.Url.PathAndQuery
The code will result like: /FolderName/CurrentUrl.aspx
What I want is, just get the 'CurrentUrl.aspx'.How to get that?
input : how to remove 1 white-space character
output : howto remove 1 white-space character
how to remove single white-space character....i try to use regular expression but cant work...
Private Sub txtInput_KeyPress(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyPressEventArgs) Handles txtInput.KeyPress
Dim len As Integer
[Code].....
i want to delete "b" from first textbox and i should delete "King" from second textbox the length of each word is same "Acer" "King" it is always 4 in length
but i am getting following error
"Index and count must refer to a location within the string. Parameter name: count"
i also tried by replacing "len-4" by another variable dim c as integer=len-4