Open Or Start A New Application (notepad) When Press A Control (button)?
Jun 17, 2011i want to open or start a new application ( example : notepad ) when i press a control ( example : button )how would i do this?
View 2 Repliesi want to open or start a new application ( example : notepad ) when i press a control ( example : button )how would i do this?
View 2 RepliesI want to create one help file for my whole application. and once user press help button next to any input control then appropriate help topic from file should get display. how can i create this functionality in vb.net?
View 1 RepliesHow should i call notepad using vs2005.
View 5 RepliesI'm still making a PC Cleaner, and I'm trying to make a cancel button for it, but when the I press the "Clean!" button in my application, you can't control the Form, I made a video of it.[url]...
View 2 Repliesprogram a little begginner project. So I want to create a program that displays an image when you press the start button. When you press the "Next button" it will display a new image.My problem is, I want the image to change EVERY time you hit the next button.
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Im hoping to create an auto clicker which had variable speed control, one button to start and pressing space to stop the application. When start is pressed i want it to click 2 or 3 different locations on my screen if this is posible with about a 1 second delay between each pointer move.i could really use some help with getting started or even better a link to an already created application for this.
View 6 Repliesi've created a hangman game (Fully working) but since you can only "play" with one phrase (10 letters) it gets boring fast. Basic the current game works by on form load i define the slots (10 string which each hold a letter) and give them there letter. then the user type in a text box and if the textbox = any of the slots then the lbl repasenting that slots changes its text from "_" to the letter.
Anyway what I would like the button to do is when the user presses the start button a random number is generated. The program then looks into a textfile and based on which number is generated it takes a certain line (10 characters per line in a phrase) , moves them into the slots and the game starts. Is that possible to code or it too complicated. The textfile will be in the applications folder (words.txt).
I'm new to programming and to Windows Forms development. I'm using VB.NET and Visual Studio 2008.
My question is: How do I open Notepad from a Windows Forms application, and then place some text string in the Notepad window?
How was the code when press one button to open website page?
View 2 RepliesI have a few questions:
1. how do I make a button press a certain button in another application? (i.e - for example it goes to application "iexplorer" and press insert, home, a, b, or other button in the keyboard)
2. How do I make a virtual keyboard (for example a button opens form 2 or 3 and when you click on a button in the keyboard it goes to a certain text box in form 1)?
My mouse has 7 buttons. How to make program that will open notepad when I click mouse button #5?
View 1 RepliesIs it possible to restart your application with a button press?
View 1 RepliesI need my application to go to a website, press a button on the website to get data, and then get the data that it shows all without the user seeing the webbrowser control. I'm doing this for a little project. The user could normally just go to the site and press the button themselves, but that would take to long. So how do you programmatically do this?
View 8 RepliesI get mixed results in Google, so I'm wondering how can I simply launch a ReadMe.txt file in Notepad thats in the same directory as my application?
View 1 RepliesI am trying to open an Access file but so far I am not succeeding. [Code] I receive following error: Cannot start your application. The workgroup information file is missing or opened exclusively by another user. I am sure the file is not open and I tried already to add in the connection string: ;User ID=User and / or Jet OLEDB:System database=C:SYSTEM.MDW; at the and but without result.
View 8 RepliesI am trying to make an application with a start button and a stop button on a stop watch program. These are the codes I am using but my seconds on the stop watch don't start.
Public Form Dim intSecond As Integer = 0
Form 1
Private
Dim intSecond As Integer = 0
intSecond +=1
[Code]...
After I write my code and try to run the program, the seconds will not start,
I have made my application to start automaticly when windows start (registry ../currentversion/run/appname + path). In this mode the application start minimized and an little icon appear in the notification icon area. With this icon you can maximize the app or exit it.If you exit the app and start it again using the Menu (Start/programs etc) than the application start in minimized mode (and in this case I would like to have it in normal mode) because the setting autostart is still true.Is there a way you can detect when the application start when windows startup using the above registry or when people click on an icon in the programs menu (or desktop)?
View 2 RepliesI want to be able to click a button on my application and the start menu appears where I've clicked. This (if possible) will replace my shell.exe. I know that with EmergeDesktop, you can show the start menu by right-clicking the desktop. How do you do that?
View 2 RepliesUsing 2 forms how would I click one button, from another form? ie In VB 4,5,6, I would used to do it as:-
Form 1:
private sub Command1_Click()
msgbox "Say Hello"
End Sub[code].....
If I clicked the button in form2, it would automaticlly, click the button in form1. Do I, do it the same way in VB Express or has it changed?
I have a GUI with a few button on it and each button start an application. I want to prevent the application to start twice if the user double click on the button. How can I do that?
View 7 RepliesMy intentions are to add command line switching. I am trying to see if i could run my application in varoius ways i.e.
App.exe -S - Start the application in XX Mode
app.exe -T30 - Start application with 30 second delay
and that kinda switching.
How to open an application from 1 button (not to open the application, only to select it)
Example: 1 button> when it press to display only .exe file for choose
How do I make it so that I can have the buttons on top of the picture?
Also is it possible for me to get a button to open VBs webbrowser control?
Using VB 2008 When I press the F5 or Start Debugging it does a rebuild even when I have made no changes since the last time. Where is the setting to tell it to only do a rebuild if there are changes?
View 3 RepliesI am creating an application that will be used to open a PDF by the end user. I have been able to create a the application thus far, and it's worked as I want except for one.
I used the code below to get the buttons to open up their respective files:
Process.Start("filename.pdf")
how to open a Jpeg in a PictureBox by using a control button which takes you to an "Open" dialog which allows you to select the picture?
View 8 RepliesWhen i debug the program and open it(inapp.exe) in notepad there a line
C:UsersendroitDocumentsVisual Studio 2008ProjectsDataTypeDataTypeobjDebugDataType.pdb
Well, is there any solution or way not to include that line when debug. I know that .pdb is important in debugging, but when the app published still there's that line. Can we disable it or there's no other way.
I have a notepad I am making. I need to resolve to more then 1 Save and Open Filter. I have the code:
Try
Dim dlg As SaveFileDialog = New SaveFileDialog
dlg.Title = "Save"
dlg.Filter = "Text Document (*.txt)|*.txt"
If dlg.ShowDialog = System.Windows.Forms.DialogResult.OK Then
RichTextBox1.SaveFile(dlg.FileName, RichTextBoxStreamType.RichText)
[Code] .....
It does work on some machine's but wold not start on other computers. from the code line's I see the problem is related to devex components.
View 2 RepliesI am trying to open a password protected access data base. I want to provide the password with in process.start to avoid the first password and security dialog box. so far i have done this
dim path as string="c:\temp\db1.mdb"
dim password as string="temp"
process.start(Path, password)
[code].....