DateTime Binary Coded Decimal Byte() Equivalent Of String Format?
Sep 30, 2010
I realize the code listed below, whose serial port using string formatting which I inherited is complicated. It formats a Date obtained from a DatePicker control into a "yyyy-MM-dd HH:mm:ss" string format to send to a hardware device to be stored via Serial Port retrieves the date from the device and displays to user What I'm trying to do is port the code for use in a Socket rather than Serial Port which wants a Byte Arrray of the same Date Time string variable. I can't figure out how to encode and convert to Bytes the string value used in the Serial Port version. The evolution of the process is listed from top to bottom.
I'd like to convert a string which contains a decimal number into string that contains the binary value, the octal and the hexadecimal value of that decimal number.Afterwards I also like to convert a string containing a binary, octal and hexd. number into a decimal string.Basically I'm looking for the functions:
dec2bin dec2oct dec2hex bin2dec oct2dec hex2dec
I'd not prefer to rewrite a function, I'm sure the framework must have these functions already.
I have a language that generally contains serialised data messages in a human-readable format, but some productions within the language contain verbatim raw, binary data.My parser uses String for its buffer since that seems to be the easiest thing to work with. However the data is read from a network socket into an array of Byte.
Now, I'm trying to connect the dots between Byte() and String:
[Code]...
But my data is still mangled. I haven't actually been able to deduce yet precisely how the data is being mangled, but I do know that the length of the data is changing, indicating that the bytes are not being left verbatim.
So how can I obtain a String whose contents are just a verbatim copy of the bytes from my Bytes() input?
I'm trying to read the binary data from a binary file with the code below but the it's return the value in the byte array. How can i read the binary data from the binary file and then convert the data into string?This is how i create the binary file.
Dim fs As New FileStream(Application.StartupPath & "Agency.dat", FileMode.OpenOrCreate) Dim bf As New BinaryFormatter() Call bf.Serialize(fs, GAgency)[code]....
So I need a format string to pass to String.Format that would "move" the decimal point.I can't perform any math operations before doing the String.Format, so it has to work right off the bat.Basically I'm emulating a formatting string from a proprietary server. In it if I say:
"MR2"
for the value:
12345
The result is:
123.45
I'm close with this, but it's not spot on:
String.Format("{0:#0.##}", 12345)
an extra, but not necessary... there is also MR2Z, which moves the decimal 2 left, but if the value is 0 "" is returned.
i have a table in sql server with some fields set as Byte() (System.Byte[]) when i import them in my application to be used with linq they are converted in Binary (System.Data.Linq.Binary)why is that?is there a way to prevent this wrong translaton???if i update the database how can i update the classes that has been craeted in visual studio2008?
I have a field that I display via: String.Format({0:c},amount) This produces the string "$28.28" However, when I try to convert back to a decimal amount, I get an incorrect format exception: amount = Decimal.Parse(amount.Text, NumberStyles.Currency) I also tried it with NumberStyles.AllowCurrencySymbol with the same results. I verified that the value in amount.Text is "$28.28". Am I missing something? Shouldn't these two operations use the same currency symbol and formats?
Need to convert a string to normal datetime format so it can be correctly inserted onto a datetime type field. String Format: 4/21/2010 4:43:03 PM Example: 2010-04-21 16:43:03.000 I have clarified question: The need is to change format and not type.
Could someone please guide me on the correct format string to display a time in the following format? [code] Is there one format string I can use to accomplish this?
In my VB project I am returning an SQL datetime field to a date variable mdtCreated = CType(oReader("dtCreated"), Date) In an example it returns mdtCreated as #5/13/2011 2:59:43 PM# which is correct. Later on I want to show this as a string to dd/mm/yyyy format. I have tried mdtCreated.ToString("dd/mm/yyyy hh:mm:ss") But that returns "13/59/2011 02:59:43". I want it to return "13/05/2011 14:59:43" How can I achieve this?
I wish to convert my string in format dd/mm/yyyy hh:mm:ss to a DateTime of the same format. Dim ukCulture As System.Globalization.CultureInfo = New System.Globalization.CultureInfo("en-GB") Dim myDateTime As DateTime myDateTime = DateTime.ParseExact("18/05/2010 23:42:10, "dd/MM/yyyy HH:mm:ss", ukCulture) When I step through this code the variable myDateTime is 05/18/2010 23:42:10 it appears that the dd/mm is the wrong way around and I cant work out how to correct this.
I can't seem to be able to convert a string that contains date value of "100714 0700" (2010-07-14 7am) to a date format in vb.net 2005.
When I attempt to do: Dim provider As Globalization.CultureInfo = Globalization.CultureInfo.InvariantCulture strPickupDateTime = DateTime.ParseExact(txtPickupDate.Text, "yymmdd", provider)
I get back "1/14/2010 12:07:00 AM". How can I get a value of "2010-07-14 7:00"?
I have been struggling with this problem for several hours now and can't find the reason for the error message...I am reading a datetime string from a txt file, it returns this:"01/31/2011 6:13 AM" Now, I want to convert this string to datetime format. I don�t want to change the structure of the date... just want to convert in order to do some minutes and seconds calculations.I have tried all kind of options:
Timespan Datediff Parse ParseExact with format.... culture... globalization
I have asked this question before and used the soln but for some reason it just does not work this time around. Hopefully someone else can see the error/missing element. Iparse a date that is in string format and would like to convert it to a datetime format but cannot figure out how to do this. The date appears as such:
format a decimal value to a string with a single digit after the comma/dot and leading spaces for values less than 100?For example, a decimal value of 12.3456 should be output as " 12.3" with single leading space. 10.011 would be " 10.0". 123.123 is "123.1" I'm looking for a solution, that works with standard/custom string formatting, i.e.
decimal value = 12.345456; Console.Write("{0:magic}", value); // 'magic' would be a fancy pattern.
I'm having a problem converting a string to a datetime format. the string is depicting an hour, for example 08:00, but in the mysql database it stores that as 2008/00/00 00:00 any idea how to solve this? [Code]
I've been trying to figure this out for hours now, and I've given up on trying to solve it myself. Basically what I need to do, is convert a "double octet" binary string, such as "11010011 01011101", into a byte or char type if possible.I use the following code to convert my Unicode text into binary:
Private Function ByteToStr(ByVal bt() As Byte) As String Dim st As New StringBuilder For Each byt As Byte In bt
[code]....
But that gives me weird results. The "Convert.FromBase64String" obviously isn't what I'm after. Any help would be great. If I can convert the "binary string" into a bytes or chars I can get it into a string.
I've been trying to figure this out for hours now, and I've given up on trying to solve it myself. Basically what I need to do, is convert a "double octet" binary string, such as "11010011 01011101", into a byte or char type if possible. I use the following code to convert my Unicode text into binary:
trying to find a decent answer for my question; I do have a utf8 file which I (down)load, manipulate and wanting to save back again.The result always is that the file I produce is not in utf8 format;
Dim fs2 As New FileStream("c: est.dat", FileMode.Create, FileAccess.Write, FileShare.None) Dim w As New BinaryWriter(fs2, Encoding.UTF8)
I need to convert a Short to his binary equivalent. For example:Dim x As Short = 20480 And then I need a method to get the binary thingy, which in this case is: 101000000000000
I searched for a answer using google, but I couldn't find a proper explanaition.
