I have a code which generates next number after clicking the button NEW like if there is 1 in table while clicking NEW it displays 2. what i want is default im inserting 001 in table then after clicking NEW button it must show 002 instead it is showing 2 only.[code]...
View 1 RepliesI was working on a pretty basic program to generate a random name and number and then put them together and submit into a form through webbrowser.The random number part is fine, but I'm having troubles trying to create a random word. Any directions on what to try?
View 1 RepliesI am working on a Bingo game and I am stuck. I got the program to generate random number but they are not unique. I dont know how to fix this. I have researched online and nothing this is my last resource. I am using Visual Basics 2005 Express Edition. [code]
View 9 Repliesis there a way to generate a random number and then display that number?
like for example i want to say "i got # - # pencils" or something like that
I want to generate a serial number in this format: INDDMMYY000001, INDDMMYY000002, INDDMMYY000003, ... I can generate INDDMMYY using following code: lblNoSiri.Text = "IN" + Date.Now.ToString("ddMMyy") However, I don't know how to generate the last six digit number. I only can generate number without zero in front of it. How to create the number with fix number of digit?
View 4 RepliesAnyway, I'm primarily a web developer so I'm only really fluent in PHP and everything else it entails.For my assignments the examination board suggests Visual Basic, so I'm just needing a little help as I'm not too great at it yet. [code] How could I ensure it generates a number 1-13 BUT doesn't ever generate a certain number, e.g. generate a number 1-13 but NOT 7.
View 4 RepliesOn Stack Overflow, I found the question Generate a receipt number in this range.In answers (from Adam Maras) I find this code (very interesting for me):
Private Const FirstReceiptNumber As String = "GA00000"
Public Function GenerateReceiptNumber(ByVal lastNumber As String) As String
If lastNumber.Length <> 7 Then
[code]....
But show me error in GenerateReceiptNumber().ow do I use that code to give me a receipt number in TextBox1 when I open this form?The receipt number must be +1 next time with Form_Load.
How can i auto generate number in vb.net
View 4 RepliesI have a form with Textbox CustId. And a Label CurrentDate(22/08/09). I want that when a new customer comes the system must generate the next number automatically. the pattern of CustId is: CurrentDate + Number For example system should generate CustId like : 22080901,22080902. 22080903 where 220809 is the Current date
View 11 Repliesi have to generate a sequence code for my project it should be 8 bytes acii value.[code]
View 3 RepliesHow i would generate sequential number in vb.net.[code]...
View 18 RepliesWhile versioning a .NET 1.1 assembly using Visual Studio 2003, is it possible to generate one without build number and revision. I would want just the major and minor version.
View 1 RepliesHow to display the auto generate next number from sql server 2005 to vb.net 2005 textbox. This code below is not displaying any data in the textbox after retrieving the data from the database.
Code:
Imports System.Data.SqlClient
Public Class NewConnection
[code].....
I once posted a question on generating a policy number by table ID and user selctions from comboboxes. [URL]FYI . I am doing my project in vb, that why i posted it here. I managed to do that when i choose a region and product from two different comboboxes i generate a number but now my problem is that whenever i click on the comboboxes a policy number is generated before i save the record, so if my previous nummber was 72100002 whenever i click on the product combobox i generate a number e.g if i click on it five times by the time i save the number would be 72100007. I am using a stored procedure for this. Is there another way of doing this or i might end up with my first record as 72100001 and my second record 72100006.
[Code]...
im working with my thesis, to generate auto increment number. for example,when the form load for the first time it will appear transaction 1, and then next time i'll load the form it will be transaction 2, so on and so forth. i am using a VB.net and SQL server.
View 1 RepliesI am trying to generate autonumber the sequence is like this. From left to right, last two digit from Year, Month in numeric and the last three digit number be from 001 to 999. I tried with the below coding but the sequence is not coming correctly.
<code>
Imports System.IO
Imports System.Data.OleDb
[Code].....
Assuming that I am going to add new record. I use this function to generate the ID for the new record.
Public Function GetMax(ByVal strTable As String, ByVal strField As String) As Integer
Dim cmd1 As New SqlCommand
Dim conn As New SqlConnection(gStrConnection)
Dim no As Integer
Dim str1 As String
[Code] .....
It returns 1. How can I modify this to make it 20120001 wherein the first 4 number (2012) will depends on the year today.
i'm beginer in this forum and new in vb6.how to generate random number in vb6?
is it posible to represent variable in binary?
I am working on student application form in vb.net. I designed a form with fields like firstname, Middlename, Lastname, age ,____,DOB,Education.Height and Weight. Back end as SQL Server 2005. I just want to generate sequence numbers in textbox using vb.net. While loading the form,i should generate number as '1' and second time,if the form gets loading it shows '2' and goes on...
View 1 RepliesI know there has to be a simple way to do this but I'm not sure how the syntax would go. I need to generate a random number from 1 to 99. How do I do this? I have my attempt that failed below:
Private Sub LoadBoard()
Dim mynum As Integer = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99)
Storage.Slot1 = mynum(Int(Rnd() * 10 Mod 99))
End Sub
how to generate student number in visual basic 2008 in this format. the year+date+in what number that the student is enrolled. example: 111201. where the year will change depend on the year that the student enrolled for the first time.
View 5 RepliesI have an application that is made for a game that you have to draw cards for. So what I have done is created a random number generator that generates a random number and then using case statements that number is associated with a picture of the card, which is displayed in a picture box. This part works fine. Each time I draw a card it is not reshuffled so I need to store the random number generated and then if that number is generated again ignore it an generate a new number.
Now to complicate matters even further when a certain card is drawn the entire deck is reshuffled and everything starts over again. Here is what I tried... I tried using arrays to store the numbers but I cannot seem to get it to search the array for the number or store the number properly within the array. The array has to be dynamic since the game is expandable and I will be adding more cards to the game in the future.
How to autogenerate number in a texbox. in Visual Basic .NET 2005 and Using OLEDB I hv created 1 application in which there is one field in the database called "treatment ID"... and now i want to Autogenerate an ID in Incrementing Manner.
View 1 Repliesi would like to generate some random number with some alphabert inside.
View 2 RepliesThe object of this project is to write a computer program that will allow the computer to guess a number that you have selected. The computer will make a guess and you, the player, will tell the computer if it guessed too high, too low, or that it guessed the number.The program will also allow the player to start a new game or to exit the program. PROJECT INSTRUCTIONS:
1. Create a form with a labeled box to display the computers guess.
2. Create a new game and an exit button.
3. Create objects to indicate if the guess was too high, too low, or right on target.
4. Create program code to respond to the player�s indication by selecting and displaying a new computer guess.
5. When the computer guesses the player�s number, reset the so that a new game may begin.
I have done all as above and so far my code looks like so
Public Class Form1
Dim Guess As New Random()
Dim HGuess As Integer, LGuess As Integer, current As Integer
[code]....
The problem i ran into is that if for example a user has a number 24, when the program makes an initial guess of 50,i want to be able to click low, and the program should generate a lower number say example 22. If i then click higher as my actual number uis 24, the program should not shoot higher than a number it has previously guess incorrect (in this case 50) it should guess anywhere from 22 - 49 and in turn limit the range of the next consecutive guesses it till hits the right number. My code right is guessing as it shuold but not within the limited ranges.
I have a form with Textbox CustId. And a Label CurrentDate, I want that when a new customer comes the system must generate the next number automatically. The pattern of CustId is:
CurrentDate + Number
For example system should generate CustId like :
22080901, 22080902. 22080903
Where 220809 is the Current date. How I can code for generation of these numbers.
I want to generate such array number
001
002
003
004
005
i want to genrete a auto number in my project....i used vb .net 2008 and SQl server 2005 as backend ??i want to create a serial no that is like abc/2010/01..In this..
the abc is same in all the serial no.the 2010 is used from the running Year.(using date for year)the 01 is a actual serial no that can be auto genrete...But how can i do this ....?? and How can i find max number from my serial no.....??how can i maintain it if i delete it then all after delete serial no will place it's place..(there is no break in serial no on delete)
My code: it is used to generate number in date format my problem is that it doesn't show any output in the textbox nor in the database. The last num in my database is 2012010001.
Dim i As Integer
Dim strSQL As String
Dim strMonth As String
Dim strYear As String
Dim strTheID As String
Dim today As Date
[Code] .....
I would like to generate a tracking number as primary key for my database.
There will be total 12 letters for each tracking id. Example: 2012010001-1
The "2012010001-1" is actually from combination YYYYMMxxxx-v where YYYY is the current year, MM is the current month, xxxx is the auto generate number(increment) and -v is the version where it can be -2 -3 but using the same YYYYMMxxxx.
For both YYYYMM is not a prob as i can get the value from Date.Today.Month/Date.Today.Year. But how am I going to ensure the xxxx is an auto increment but will be reset back to 0000 every new month.
For example:
2012010000-1 (Month January, so start from 0000)
2012010001-1
2012010002-1
[Code].....