I have built a Dialog which contains a TreeView. Now, when I invoke this Dialog, I need passing a value based on which a node of the TreeView will be selected. I need help in knowing how do I pass a value to the Dialog?
im learning vb.net and i am trying to build a program for practice.in this program you can open word files with an open file dialog, after the word files were opened the document is added to a listbox. then you can open it again, but from the list box by clicking a Button. everithing is fine, exept one thing, even if i add 5 documents to the list,when i try to open them from the list it only open the last one thant was open by the open file dialog.
I have a project that will add the conents of a .txt file to a listbox but how would I make the program to open a browse for file dialog when a user click a button and then add the file to something to be read from like: Dim accpath As String = My.Computer.FileSystem.ReadAllText(System.IO.Directory.GetCurrentDirectory() + "\somefile.txt")
I am having a funny problem with OpenFileDialog that I just cannot solve. Using VB.NET 2008 Pro.
Problem: I run my program and click the menu item associated with this OFD and the OFD opens fine. When I select a file and click OPEN the dialog disappears then reappears. I click OPEN again and it disposes itself then loads the proper file into a form. The same thing happens with the CANCEL button as well.
Question: How do I go about coding the OFD to open a file that has been double clicked on thus bypassing dialogresult.OK . I can't seem to find an answer to this.
I am using this, to read 1+ files from the openFileDialog, but I am having a problem getting just the file name, I can get the location "C:My Documentsfilename.jpg" but how do I get just the name "filename.jpg"?
I want to replace it with this line: can.Text = Regex.Replace(file, ".+\$", "")
vb.net Private Sub OpenToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OpenToolStripMenuItem.Click
After deploying and installing my application I use the app to create and save a file with my own file extension. After the file is created I right-click on the file and select Open With.. so that I can associate this file extension with my application. In the Open With dialog I use the Browse button to find my application and select it. In the Open With dialog the application icon is shown, but the name of the app is blank (looks like an empty string). Can anyone tell me why this might be happening? I've looked at the Registry, which shows the correct app, but every time I open the Open With dialog only the application icon is displayed, no name.
I'm developing a WinForms app in VB.NET, that handles sets of style data, and when the user clicks on another set's label, it prompts through a dialog "You are leaving this style preset to edit another one. keep changes on this one? [Yes] [No]".But, I'm facing the problem that, when the user clicks either option, and the dialog closes, everything has to be refreshed, and loading the form again seems a good option.[code]But as soon as that sub is called from the prompt, it crashes the application. (doesn't show an error in debug, simply crashes) How should I, from a given dialog, close the dialog, it's parent, and re-open it's parent? (which triggers all the Dialog_Load() code of the parent)
I'm having the reverse problem as this thread.We save off data in several formats, one of which is .XLS, however, some users may not have MS Office installed already, so I want to allow them to use the OS's "open with" dialog to associate with notepad or something so they can open the file.[code]...
I have a form that I am calling by using showdialog(). In that form, there is a button that will call another form by using showdialog(). When I close the second dialog box, it also closes the first dialog box. Is there some way to keep the first dialog open?
I am trying to use the open file dialog box in VB 2005 to open up an existing txt, or rtf file from a directory into a rich text box. I am able to get the Open file dialog to appear and the directories, but when I try to open the file it doesnt import it into the text box. Here is the code I am using
<script type="text/javascript"> function ShowAlert(id) { alert('I am here' + id);[code].....
In my gridviews item template for my edit button I have the following to call the function. Which works to show an alert but can't get it to show the dialog? Is it because possibly the postback happening on the grid causing it to close?
I am retrieving some pictures from the images in my Picture Box on the form I added my "images" folder to the bin/debug folder , and used the code for retrieving images from this directory.
Dim myDir As String = Application.StartupPath & "images" '-- my folder for images
I have some code that loops in the background of a form and triggers action if the form is active (this is in a mdi forms application). I use the following to check this:
vb.net
Dim frmActive As Form frmActive = Me.MdiParent.ActiveMdiChild If frmActive.Name = Me.Name Then 'Do work End if
The problem comes when that form starts another form running in dialog mode i.e. form.showdialog. I need the above code not to run while this is the case, but it still returns true when the dialog form is active and the other form is in the background.
Is there any way to detect whether a dialog is open in an mdi environment?
At one point I have a dialog form open, but in order to process it, the user might want to access information on other (open) forms. This would necessitate the ability to move/resize/scroll the other forms, but obviously everything is frozen during the dialog. I don't suppose it's possible to achieve this "semi-modal" state, where other forms can be browsed, but no other actions taken?
I am trying to open a Dialog box to select a file. I then need to drop that value into a FileStream StreamReader to read it so the combo box will show a list of values in the selected .ini file. I've got pieces of it but I am not sure of the glue that will connect the two. I am posted what code I have below.
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim FileParser() As String
Is there one out there? I try to include this and it says something about the Oracle connection not being compatible with the target framework. Any ideas? Or how can I change the target framework of the project without breaking the visual studio power packs?
what the open/save dialog property, AutoUpgradeEnabled means? I have tried it on VS2005, 2008 and 2010. WHen enabled it delays returning the filename you choose for up to 5 seconds.
and have successfully got a file name from the open file dialog when coded as part of the "Public Class Form1" -> Private Function btnOpenXML_Click function that was generated automatically by vb. The openFD was generated by adding the OpenFileDialog to the pane underneath the form.
Private Function btnOpenXML_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnOpenXML.Click Dim strFileName As String
[Code]....
I'd like to move this code to a module so that it does not clutter my main form1 layout.
However when copy the code to a new module, the openFD is not recognised.
how to I re-declare this openFD or pass it into the function so that it can be used?
I managed to create an application that is listed in the 'open with' list only in debug version. Means, when I right click on a file extension and select "open with..." I get the 'choose program' dialog and can browse for my app, nothing impressive. The weird part is, that when I enter the path to the debug version of my program is works, and when doing the same to the release version my app is not even listed, it is simply not shown...
Does anybody know what it needs to make a simple VB.net app be listed here, any fancy debug/release setting?