I am trying to use the open file dialog box in VB 2005 to open up an existing txt, or rtf file from a directory into a rich text box. I am able to get the Open file dialog to appear and the directories, but when I try to open the file it doesnt import it into the text box. Here is the code I am using
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In my scheduling app I am exporting information to an excel file. When the first export runs it opens a new instance of an excel workbook. I have decided to save each schedule (AMRN, PMRN, AMTech, PMTech etc) to separate works sheets instead of appending the first worksheet. This way when the shedules need to be printed the whole workbook can be selected to print. When I try to open the existing workbook if it exist I get an error. Here is what I am trying to do.
vb.net
Dim xlApp As excel.Application
Dim xlWorkBook As excel.Workbook
Dim xlWorkSheet As excel.Worksheet
[Code].....
I have a open and file save dialog which I use to open and save file. There are also some labels in the application. During the time a file is open or saved, the file open /save dialog becomes blurred by the background labels. Is there any way to prevent this? The attached pic is given as an example to explain the dilemma.
View 1 RepliesI have a form that I am calling by using showdialog(). In that form, there is a button that will call another form by using showdialog(). When I close the second dialog box, it also closes the first dialog box. Is there some way to keep the first dialog open?
View 10 RepliesI would like to open the excel file after create the excel file. The creating file function is done, but the system unable to open the excel file. My coding as below:
Dim xlApp As Excel.Application
Dim xlWorkBook As Excel.Workbook
Dim misValue As Object = System.Reflection.Missing.Value
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I am trying to open a folder using the above code. But the folder is not getting opened when the button is clicked. ie after description part, the execution is not going ahead
I have a text box in which a file path is displayed. A button to click and open the file. Code executes properly but the file doesn't open. [Code]
View 4 RepliesOn my computer I've VB.net 2005. and also office 2007. I try to open an excel file like that
Imports Excel = Microsoft.Office.Interop.Excel
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, _
ByVal e As System.EventArgs) Handles Button1.Click
[Code].....
How can i open chm file in VB.net 2005 ?
View 1 RepliesHow to open Executable File in VB.Net 2005
View 2 Replieswould like to know if it is possible to have my application launch and open a file which will be called todays date. its just a simple text file and i am basing it on the streamreader style function.
View 9 RepliesThe following code works to check if a file exist, but I need to also check if the file is open.How would I do that?
If System.IO.File.Exists(Application.StartupPath & "players.txt") = False Or System.IO.File.Exists(Application.StartupPath & "preferences.txt") = False Then
bla bla bla
End if
When the main program is doing it's routine, it is looking at, and using, data from the two files.So, when the user pauses the program by opening the control panel, one or both of the files may still be opened. When the control panel tries to open them, it causes an error.(I am guessing that to just tell it to close them will cause the same problem if they are already closed.)
At home I use Visual Studio 2008 Pro but a class of mine is trying to have us use Visual basic 2005 express edition. Since we need to submit source code files will there be a problem if I just submit the .vb file instead of the whole solution?
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I'm looping through a csv file. For each line, I'm reading certain values, generating a filename, and writing the record to that file. Here is some logic
If <something that doesn't matter happens> Thendo somethingElseIf File.Exists(strOutFile & (strOutputFileName & "__" & strPrefixFileName & ".txt")) Then
strFullFileName = strOutputFileName & "__" & strPrefixFileName & ".txt" '** Double Underscores after app name
tsOutfile = New StreamWriter(strOutFile & strFullFileName)
[Code] .....
Now, obviously with the above code, there's no reason for the elseif, since they both do the same thing. The problem, however, is if I need to create a new file and write to it, everything works fine. In fact, everything will work perfectly until I need to write to a file that I already created. If I go ahead and just try "tsOutfile = New StreamWriter(strOutFile & strFullFileName)" and point it to the already existing file, I get a permission error (says the file is already open). Is streamwriter keeping an open connection to all of these files that I create? Nothing else in the program is touching these files, only streamwriter.
Here's a quick example to illustrate what is happening
Record 1 goes to file A
Record 2 goes to file A
Record 3 goes to file A
Record 4 goes to file B
Record 5 goes to file B
Record 6 goes to file B
Record 7 goes to file C
Record 8 goes to file A (Error will occur here)
I m developing an application, where I would like the user to open an existing excel file inside the Application itself (Form)
View 1 RepliesI am trying to open an excel file and write to it as data becomes availableI can create an instance of excel and write to the selected worksheet once. But, I can't seem to write back to the existing file. I keep on getting a null reference error when I try to send new data to the file.The function I am using will run once, but when it returns to the main form, I lose the values of xlApp and xlWorksheet. It appears that going in to the function makes the original values null.
View 2 RepliesI am using TextFieldParser to read a .txt file and create a DataTable I then filter the table and create 4 new tables I then bind those tables to BindingSources Then Bind ComboBoxs to the BindingSource Then bind TextBoxes to BindingSource I like the user to be able to Open a new file without having to close the program So upon opening a new file I have a sub routine that clears the tables the rows and the columns of each table as well the DataBindings to each control The problem is once I do the Text Binding as such
Me.list1_MLStxt.DataBindings.Add("Text", Subject_Values.BindingSource1, Form10.mls_txt.Text)
Then when I open a new file I get an error message conversion from string"""" to type double is not valid.If I never perform the binding I can open and reopen different files without a problem. So this is causing me to think that the problem is with the way I am clear something? But I am obviously not sureIs there something I am missing to clear everything properly in order to open and read and bind a new file?
I need to make an E-Search engine for collage library , i can make it by using streamReader and streamWriter , but unfortunately i have to use Binary to make this project ... i've to many fields to put it on DAT file , and i've to use SPLIT to split lines and make arrays ..
what is the best way to do that ? how can i write an opened binary file on textbox and convert text to array ?
Suppose I have this Dim proc As Process proc = Process.Start("Notepad.exe", "C: est.txt") Now, if I want to use Notepad.exe to open another text file (ie. C:2ndTextFile.txt) without closing it, how am I going to do it?
View 7 RepliesI'm trying to write a program that will open a solidworks file in EDrawings and print it and so far the only way I can find to do that with an edrawings ActiveX Control displayed on my form.Does anyone know if it's possible to print drawings via EDrawings 2009 without the ActiveX Control having to be displayed on the form as that is drastically slowing down my program?
View 5 RepliesI want to open an existing VB class file, add a few properties and close it again.
Simple enough, I thought: Take the CodeDom, a VBCodeProvider, parse the code (using the Parse-method), then identify the location where I want my stuff added (doubtless using some nifty LINQ expressions), add a bit of code and then have it generated and here we go.
Now I see that Microsoft apparently added the Parse method only for the fun of it but never implemented it.
What's the story here? Can I only generate code from scratch? Is it not possible to load existing code?
I want to use my word add in to open an existing file, the code is:
currentDoc = app.Documents.Open(currentFile)
where currentFile is a string containing the path to the file I want to open, when ever this code runs, there are no errors, but I also cannot see the document
edit: the program first closes the 'currentFile', adds something to the package, then tries to open it again with the line above, when it closes the document the word application stays open with no document in it, but when it opens it again it is not seen in the application, but the document is open
How do i make it that when i hit a button file dialog opens and i can select a text file from my computer
then output the text file into listbox1.text
I'm trying to create a program where I open a file using a open file dialog and take the information from a text file and output them into various listboxes and textboxes
The first problem I had encountered was at :
With CurrentCustomer
.EmployeeID = ToInt32(Fields(0))
.Name = Fields(1)
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I have a program that runs some data manipulation on a file when it is double-clicked and then displays this to the user.However, when I double click on the same file type of a different file it opens in a separate instance of my program instead of the same instance already running, i.e. some message that says would you like to reload file, YesNo, and then given the answer perform the action required.I have found some code to stop a second instance from opening, but this is inconvienient for the user to close out of the program everytime they want to view a new file.[code]
View 6 RepliesI am trying to open a Dialog box to select a file. I then need to drop that value into a FileStream StreamReader to read it so the combo box will show a list of values in the selected .ini file. I've got pieces of it but I am not sure of the glue that will connect the two. I am posted what code I have below.
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Dim FileParser() As String
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I type in openfiledialog1.showdialog() and it says theres in error when i have a openfiledialog on my form Please Respond Quick
View 3 RepliesI have code that fills in a webbrowser form selecting pdf files to download. The files are then requested with:
Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click
[code].....
I have completed the vb tutorial on
[URL]
and have successfully got a file name from the open file dialog when coded as part of the "Public Class Form1" -> Private Function btnOpenXML_Click function that was generated automatically by vb. The openFD was generated by adding the OpenFileDialog to the pane underneath the form.
Private Function btnOpenXML_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnOpenXML.Click
Dim strFileName As String
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I'd like to move this code to a module so that it does not clutter my main form1 layout.
However when copy the code to a new module, the openFD is not recognised.
how to I re-declare this openFD or pass it into the function so that it can be used?
I'm trying to display the file path of the file I select using an OpenFileDialog box in a text box on my form.
View 3 Replies