I'm trying to create a program where I open a file using a open file dialog and take the information from a text file and output them into various listboxes and textboxes
The first problem I had encountered was at :
With CurrentCustomer
.EmployeeID = ToInt32(Fields(0))
.Name = Fields(1)
I need a code for the open file dialog that if a file is not supported then a message box appears stating the error. This is my open file dialog code. [code] The message box pops up like it is suppose to, when you click ok the open file comes back up like it is suppose to. When you put in the correct file the message box comes back up again. Also the message pops up even if the correct file is put in the open file. but if you close the file dialog the image is where it is suppose to be.I believe the code for the public sub wrongfile is what is the problem. can some one look it over and let me know what changes are needed.
code snippet that would allow a progress bar to track the input of a text file? Normally I would not bother with this, but the text files are > 10,000 lines long, which is noticable even on a fast machine. The number of lines is variable, so I would assume that one would not use a fixed value to calculate when the progress bar goes 100%.
im making a simple program that will copy a single file. im trying to get the name of the file that i selected in the open file dialog but i get the location and file name (C:Users****Documents est est.txt) im trying to just get (test.txt)
I am trying to use the open file dialog box in VB 2005 to open up an existing txt, or rtf file from a directory into a rich text box. I am able to get the Open file dialog to appear and the directories, but when I try to open the file it doesnt import it into the text box. Here is the code I am using
I'm making an alarm program, and I want the user to be able to choose their alarm sound. To do that, I want to use the openfiledialog box, but I don't know how to play it. Here's the code:
I am using this, to read 1+ files from the openFileDialog, but I am having a problem getting just the file name, I can get the location "C:My Documentsfilename.jpg" but how do I get just the name "filename.jpg"?
I want to replace it with this line: can.Text = Regex.Replace(file, ".+\$", "")
vb.net Private Sub OpenToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OpenToolStripMenuItem.Click
I am trying to open a Dialog box to select a file. I then need to drop that value into a FileStream StreamReader to read it so the combo box will show a list of values in the selected .ini file. I've got pieces of it but I am not sure of the glue that will connect the two. I am posted what code I have below.
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim FileParser() As String
and have successfully got a file name from the open file dialog when coded as part of the "Public Class Form1" -> Private Function btnOpenXML_Click function that was generated automatically by vb. The openFD was generated by adding the OpenFileDialog to the pane underneath the form.
Private Function btnOpenXML_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnOpenXML.Click Dim strFileName As String
[Code]....
I'd like to move this code to a module so that it does not clutter my main form1 layout.
However when copy the code to a new module, the openFD is not recognised.
how to I re-declare this openFD or pass it into the function so that it can be used?
i have wrote a program that allows users to open and save text files etc and it all works fine. All i was hoping to find out is if it is possible to specify the initial folder you are taken to when using the OpenFileDialog. This would be useful as the users only open and edit files from one folder which takes quite a bit of drilling down to to find.
Public Partial Class MainForm Dim i As Integer = 0 Sub OpenToolStripMenuItemClick(sender As Object, e As EventArgs)
What code will I put in the open file dialog box_fileok if the multi select feature is enabled. I currently have this code, but it only shows in the textbox the last file that has been selected.
Dim strm As System.IO.Stream strm = OpenFileDialog3.OpenFile() TextBox3.Text = OpenFileDialog3.FileName.ToString()
I have the following code that generates a csv file on a button click. [Code] What I want to do is open a download dialog box that will allow the user to open or save that file it has just created.
I want to clear the history in an open file dialog, so that previous opened files won't be shown if a user clicks on the drop down arrow behind "File name". I have created an open file dialog and named it "ofd_openen".
Then I 've tried:
ofd_Openen.SafeFileNames = False and also ofd_Openen.FileNames.Clear()
I'm building a simple Notepad where users can open CSS & HTML files & was wondering how I can program it to open the file in the main text box like the regular Windows Notepad does.
I am doing setup project in VS 2008. I used custom action to select file from local drives. On the button click of custom action form, I am launching Open file dialog as ofdGetNetPath.ShowDialog When I run the setup on Vista, and click the button to open the openFileDialog, it hanged, form becomes non responsive and I have to cancel the setup.
on debugging I got following error "Current thread must be set to single thread apartment (STA) mode before OLE calls can be made. Ensure that your main function has STAThreadAttribute marked in it. This exception is only raised if a debugger is attached to the process."
so I used the following code:
Dim ofdThread As Thread ofdThread = New Thread(New ThreadStart(AddressOf ShowOpenFileDialog)) ofdThread.SetApartmentState(ApartmentState.STA) ofdThread.Start() Private Sub ShowOpenFileDialog() Me.ofdGetNetPath.ShowDialog() End Sub
now on button click, OpenFileDialog is shown but it is not showing Mapped drive or Network location... what should I need to do to show the mapped drive or network locations?
im learning vb.net and i am trying to build a program for practice.in this program you can open word files with an open file dialog, after the word files were opened the document is added to a listbox. then you can open it again, but from the list box by clicking a Button. everithing is fine, exept one thing, even if i add 5 documents to the list,when i try to open them from the list it only open the last one thant was open by the open file dialog.
I am a newbie trying to make a application but i am having difficulties. No matter what i do i cannot get the open file dialog and the one fo saving to work. I just want them to open and save ones a web browser usually can do. I have tried so much but can't figure out what to change when i look at other people's stuff on this and other sites.