im learning vb.net and i am trying to build a program for practice.in this program you can open word files with an open file dialog, after the word files were opened the document is added to a listbox. then you can open it again, but from the list box by clicking a Button. everithing is fine, exept one thing, even if i add 5 documents to the list,when i try to open them from the list it only open the last one thant was open by the open file dialog.
I have been having some problems with my Visual Basic. In trying to figure that out, un-installing, and reinstalling, running virus scans, etc, I have lost a lot of my time to get this assignment done. I would just keep messing around with it and try to be further along, but I must move on.
We have a form application with 3 tab pages. The first tab page takes input for first name, last name, phone, birth month, and birth year in textboxes. This info is to be written to a file. The next tab page has a read button that then displays the data into a list box. The next tab page has a text box to take input for a birth month and then searches through the file and lists any file that matches that birth month.
The whole thing then needs to be serialized and deserialized.I will post what I have so far. My first question is what do I need to do to get it to read into the listbox? I have tried multiple things. None work. After the issues I had with my visual basic, I don't know if for sure it is me, (most likely), or the software.For the display, we are supposed to use an overloaded ToString method in another class. Do I have to use an array?
I need a code for the open file dialog that if a file is not supported then a message box appears stating the error. This is my open file dialog code. [code] The message box pops up like it is suppose to, when you click ok the open file comes back up like it is suppose to. When you put in the correct file the message box comes back up again. Also the message pops up even if the correct file is put in the open file. but if you close the file dialog the image is where it is suppose to be.I believe the code for the public sub wrongfile is what is the problem. can some one look it over and let me know what changes are needed.
how do i read the first line of text of every text file in a folder and populated in a list box. Also how do I get it to show the file name in a text box when you select an item in the listbox
code snippet that would allow a progress bar to track the input of a text file? Normally I would not bother with this, but the text files are > 10,000 lines long, which is noticable even on a fast machine. The number of lines is variable, so I would assume that one would not use a fixed value to calculate when the progress bar goes 100%.
im making a simple program that will copy a single file. im trying to get the name of the file that i selected in the open file dialog but i get the location and file name (C:Users****Documents est est.txt) im trying to just get (test.txt)
At the present moment I have four list boxes that save into one text file each seperated by a number telling me how many items are in each. The code is as follows[code]...
I'm making an alarm program, and I want the user to be able to choose their alarm sound. To do that, I want to use the openfiledialog box, but I don't know how to play it. Here's the code:
I am using this, to read 1+ files from the openFileDialog, but I am having a problem getting just the file name, I can get the location "C:My Documentsfilename.jpg" but how do I get just the name "filename.jpg"?
I want to replace it with this line: can.Text = Regex.Replace(file, ".+\$", "")
vb.net Private Sub OpenToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OpenToolStripMenuItem.Click
I am trying to open a Dialog box to select a file. I then need to drop that value into a FileStream StreamReader to read it so the combo box will show a list of values in the selected .ini file. I've got pieces of it but I am not sure of the glue that will connect the two. I am posted what code I have below.
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim FileParser() As String
and have successfully got a file name from the open file dialog when coded as part of the "Public Class Form1" -> Private Function btnOpenXML_Click function that was generated automatically by vb. The openFD was generated by adding the OpenFileDialog to the pane underneath the form.
Private Function btnOpenXML_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnOpenXML.Click Dim strFileName As String
[Code]....
I'd like to move this code to a module so that it does not clutter my main form1 layout.
However when copy the code to a new module, the openFD is not recognised.
how to I re-declare this openFD or pass it into the function so that it can be used?
I am creating a text file using a save file dialog and copying the path to the text box which file is used to write from vb.net. when i try to write i get an error "The process cannot access the file '....fileName.txt' because it is being used by other program".
The code is below
Public Sub writeInTextFile() Try Dim oWrite As New StreamWriter(TxtOutputPath.Text)
I'm trying to create a program where I open a file using a open file dialog and take the information from a text file and output them into various listboxes and textboxes
The first problem I had encountered was at :
With CurrentCustomer .EmployeeID = ToInt32(Fields(0)) .Name = Fields(1)
i have wrote a program that allows users to open and save text files etc and it all works fine. All i was hoping to find out is if it is possible to specify the initial folder you are taken to when using the OpenFileDialog. This would be useful as the users only open and edit files from one folder which takes quite a bit of drilling down to to find.
Public Partial Class MainForm Dim i As Integer = 0 Sub OpenToolStripMenuItemClick(sender As Object, e As EventArgs)
What code will I put in the open file dialog box_fileok if the multi select feature is enabled. I currently have this code, but it only shows in the textbox the last file that has been selected.
Dim strm As System.IO.Stream strm = OpenFileDialog3.OpenFile() TextBox3.Text = OpenFileDialog3.FileName.ToString()