Returing File Path To A Variable When Using Open File Dialog?
Nov 10, 2009how do i return the file path to a variable when using open file dialog to browse and open a file?
View 14 Replieshow do i return the file path to a variable when using open file dialog to browse and open a file?
View 14 RepliesMy question is as follows: The user has clicked File>Open in Notepad and also clicked on a file/folder. My Application in VB.NET needs to know the path and filename of the selected file/folder before the user selects the OK button of the Open Dialog box. How can I do this with VB.NET (VS2010).
View 5 RepliesI need a code for the open file dialog that if a file is not supported then a message box appears stating the error. This is my open file dialog code. [code] The message box pops up like it is suppose to, when you click ok the open file comes back up like it is suppose to. When you put in the correct file the message box comes back up again. Also the message pops up even if the correct file is put in the open file. but if you close the file dialog the image is where it is suppose to be.I believe the code for the public sub wrongfile is what is the problem. can some one look it over and let me know what changes are needed.
View 7 RepliesWhat i am trying to do is open a save file dialog and write to a .txt firl the contents of my listview. so far:
[Code]...
i have this, but i'm not to sure how to write to the .txt file i know i need to use a for each to loop the contents of the list view
I have a checked list box that is populated with the text from a text file. I started off with this code:
Dim FileToLoad As String
FileToLoad = TextBox3.Text
Dim fs As FileStream = New FileStream(FileToLoad, FileMode.Open)
[code].....
code snippet that would allow a progress bar to track the input of a text file? Normally I would not bother with this, but the text files are > 10,000 lines long, which is noticable even on a fast machine. The number of lines is variable, so I would assume that one would not use a fixed value to calculate when the progress bar goes 100%.
View 4 Replieshow can i specify dynamically by using open file dialog box
View 1 RepliesFile I/O and Registry :: VB newb Open File Dialog
View 2 Repliesim making a simple program that will copy a single file. im trying to get the name of the file that i selected in the open file dialog but i get the location and file name (C:Users****Documents est est.txt) im trying to just get (test.txt)
View 2 RepliesWell im making a program that will Add the Safe File Name of the File opened in the Open File Dialog to the first column of the listview and the File name and path to the second. What i want it so when i double click on the Safe file name it will open the file specified in the path in the second column.i already got the add file to it.
View 4 RepliesIs there a better way of finding the path of a file that was opened with the open file dialogue? This is what I did. It works, but it seems like there should be a way to get the path through one of the open dialogue options.
Code:
'm_PicSource = OpenFileDialog1.FileName
'm_PicSource is a global var
Dim strCnt As Integer = m_PicSource.Length - 1
[Code].....
I'm making an alarm program, and I want the user to be able to choose their alarm sound. To do that, I want to use the openfiledialog box, but I don't know how to play it. Here's the code:
[Code]...
I am using this, to read 1+ files from the openFileDialog, but I am having a problem getting just the file name, I can get the location "C:My Documentsfilename.jpg" but how do I get just the name "filename.jpg"?
I want to replace it with this line: can.Text = Regex.Replace(file, ".+\$", "")
vb.net
Private Sub OpenToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OpenToolStripMenuItem.Click
[Code]....
When opening the file browser over and over, I want it to show the directory I opened a file from last time. But it always goes back to the initial directory every time I open it. How do I do it?
View 4 RepliesHow do i make it that when i hit a button file dialog opens and i can select a text file from my computer
then output the text file into listbox1.text
I am trying to open a Dialog box to select a file. I then need to drop that value into a FileStream StreamReader to read it so the combo box will show a list of values in the selected .ini file. I've got pieces of it but I am not sure of the glue that will connect the two. I am posted what code I have below.
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Dim FileParser() As String
[Code]....
I type in openfiledialog1.showdialog() and it says theres in error when i have a openfiledialog on my form Please Respond Quick
View 3 RepliesI have code that fills in a webbrowser form selecting pdf files to download. The files are then requested with:
Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click
[code].....
I have completed the vb tutorial on
[URL]
and have successfully got a file name from the open file dialog when coded as part of the "Public Class Form1" -> Private Function btnOpenXML_Click function that was generated automatically by vb. The openFD was generated by adding the OpenFileDialog to the pane underneath the form.
Private Function btnOpenXML_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnOpenXML.Click
Dim strFileName As String
[Code]....
I'd like to move this code to a module so that it does not clutter my main form1 layout.
However when copy the code to a new module, the openFD is not recognised.
how to I re-declare this openFD or pass it into the function so that it can be used?
I'm trying to display the file path of the file I select using an OpenFileDialog box in a text box on my form.
View 3 RepliesI'm trying to create a program where I open a file using a open file dialog and take the information from a text file and output them into various listboxes and textboxes
The first problem I had encountered was at :
With CurrentCustomer
.EmployeeID = ToInt32(Fields(0))
.Name = Fields(1)
[Code].....
I am using VS2010 release edition with Windows XP, Vista, 7
my programme works fine in XP but fails in Vista and 7.
All I am trying to do is open a OpenFileDialog to get a filename. [code]...
[Code]...
'Show the Open dialog and if the user clicks the Open button, 'load the file If OpenFileDialog1.ShowDialog = Windows.Forms.DialogResult.Ok Then
[Code]...
i have wrote a program that allows users to open and save text files etc and it all works fine. All i was hoping to find out is if it is possible to specify the initial folder you are taken to when using the OpenFileDialog. This would be useful as the users only open and edit files from one folder which takes quite a bit of drilling down to to find.
Public Partial Class MainForm
Dim i As Integer = 0
Sub OpenToolStripMenuItemClick(sender As Object, e As EventArgs)
[Code].....
is it possible to select a whole folder in vb.net open dialog box?
View 1 RepliesWhat code will I put in the open file dialog box_fileok if the multi select feature is enabled. I currently have this code, but it only shows in the textbox the last file that has been selected.
Dim strm As System.IO.Stream
strm = OpenFileDialog3.OpenFile()
TextBox3.Text = OpenFileDialog3.FileName.ToString()
[Code]....
I am relativel new to using the .Net framework. I am trying to learn how to set the path of a file to a variable, and having no luck. I keep getting a message that indicates that the path can't be set. The error seems to be a runtime error. Here is the code
[Code]...
i m creating a simple application that will open files which located in the CD rom... this is wat i got now
System.Diagnostics.Process.Start("F:Test\testing 1-test.pdf")
its works well.. but then not everyone CD rom drive is the same,anyway to do it as open the file without concerning the cd rom path??
I'm dealing with image files so I need to have the image with the item.
I have an image list which is called img and the open file dialog is ofd1.
I have the following code that generates a csv file on a button click. [Code] What I want to do is open a download dialog box that will allow the user to open or save that file it has just created.
View 2 Replies