Is there a better way of finding the path of a file that was opened with the open file dialogue? This is what I did. It works, but it seems like there should be a way to get the path through one of the open dialogue options.
Code:
'm_PicSource = OpenFileDialog1.FileName
'm_PicSource is a global var
Dim strCnt As Integer = m_PicSource.Length - 1
[Code].....
I in my project i have two text box and 1 button and 1 openfile dialogue Event on Command Button in textbox1 i want a file directory with the file name & extension, which i have done well (like C:\files\readme.txt) but in textbox2 i want only the directory of the same file, means under which directory it stored (like C:\files\)
Here's my example code
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
[Code].....
I in my project i have two text box and 1 button and 1 openfile dialogue
Event on Command Button in textbox1 i want a file directory with the file name & extension,which i have done well (like C:files eadme.txt) but in textbox2 i want only the directory of the same file, means under which directory it stored (like C:files)
Here's my example code
Code:
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
[Code]....
I in my project i have two text box and 1 button and 1 openfile dialogue Event on Command Button in textbox1 i want a file directory with the file name & extension,which i have done well (like C:files eadme.txt)butin textbox2 i want only the directory of the same file, means under which directory it stored (like C:files)
Here's my example code
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
End Sub
[code]....
i would like to do FILE I/O without a dialogue. the file always be the same and the location will always be the same, therefore i dont need a dialogue. i would like to know how can i do this? what is the code to open, write, and save to a file without the dialogue.
View 2 RepliesSo I open files and do whatever with them right. I've set the initial directory to equal the last directory, but whenever I open multiple files, it never sets the directories properly. It acts as though nothing was opened there, so it takes the previous directory as the last one. Thoughts on what's not working? Here's the code.
Code:
With FileOpenDialog1
.InitialDirectory = LastDirectory
If .ShowDialog = DialogResult.OK Then
[code]....
I have multiselect enabled earlier and everything else works but this. When you open a single file, the last directory works fine. It only happens with multiselect.On another note, does anyone know why it freezes when I try to do a lot of files and use another program? I opened 700+ files to see what would happen. When I switched to a IM convo, it froze. When I left it to run, it worked.
I've created an application that saves files with an extension of "*.pbca". When i click the saved file in Windows Explorer, it opens my application, as it should, but i now need the code that finds the file path of this file once my application has loaded.[code]...
View 14 RepliesI'm trying to convert a path/file to a url to be opened in webbrowser1.[code]
View 2 Repliesi made a program that is associated with the .map file type. What I need to do is find out the path of the .map file that opened the application(including the file name for the .map file).
View 13 Repliesi have an application that used for entering some modification on images but what i want is that when somebody open any image using right click then "open with" and choose my application program then the image translated to the picturebox in my program so i need to know the code of the image path?
View 3 RepliesI am trying to get the file path that opened my application. So if I opened my application by making the text file open with my application, how could I get the file path of that text file? Lets put it this way, you have a text file. Ex: MyFile.txt, so when you click that it opens in NotePad and loads the text in MyFile.txt. How can I do that but just get the file path?
View 6 RepliesI made a quick search program so when I browse for a text file, it adds that text file to a listbox1. And then when you search result will be placed in listbox2 Now I'm wondering how to force the program to automaticly load last opened text file on startup.I tried with this and then I stuck.
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Dim reader As IO.StreamReader = _
New IO.StreamReader(winDir & "system.ini")
[code].....
I've been doing a lot of coding latley and I'm interested in some things that vb can do. I was wondering if vb has the ability to search a directory for a file or mutipule files within a folder. Like in dos I can do C:user*.* and I can get all files that have . in them. Is there a similer way to do this in VB, I don't think VB has a wildcard or I've not heard that it does so I'm comfused on how I would find a file if I didn't know the path.
View 2 RepliesWell im making a program that will Add the Safe File Name of the File opened in the Open File Dialog to the first column of the listview and the File name and path to the second. What i want it so when i double click on the Safe file name it will open the file specified in the path in the second column.i already got the add file to it.
View 4 Repliesi wanna list all the path of every folders contained in a main folder in a listbox Here's my problem
For Each level1 As String In My.Computer.FileSystem.GetDirectories("C:Documents and SettingsAll UsersDesktopdatabase")
ListBox1.Items.Add(level1)
Next
[Code]...
I suppose technically this isn't .NET specific but I suspect this is something to do with the registry and I'm using .NET!I'm trying to find out how to get the fully qualified path relating to a file type.For example, the system knows that to open a PDF file it needs to launch C:Program FilesAdobeAdobe Reader 10.0Readeracrord32.exe
I've had a good long search through the registry and found a lot of references to the adobe path probably too many - and I've edited them to try and "break" the process so I can identify which one is used to discover the path but with no luck. I'm assuming this has something to do with HKEY_CLASSES_ROOT?
how do i return the file path to a variable when using open file dialog to browse and open a file?
View 14 RepliesI have a WinForms application that I have taken over support for and it was build using Visual Studio 2005 with VB.Net. The application makes use of an Access database. It runs fine when it is installed as a standalone application, but the install cd for the application also allows for a network install and this is where I am currently encountering issues.
To test the network install I created a folder on my server (Windows Server 2003 SP2) and copied the Access database to this folder. I created a share for this folder and gave everyone full permissions to the share. Then on the workstation I installed the application and gave the path to the database as follows:
\myservermysharemydb.mdb
(The install steps here are as per the instructions given on the installation cd)The workstation that I installed it on is Windows 7 Ultimate. When I run the application, I get the error message given in the title when the application tries to read the database file. I have confirmed that I am able to write to the shared folder on the server, so I don't think this is a permissions issue. Also, the database file is not in use at all, so it is definitely not opened exclusively.
UPDATE:I have tested the workstation installation on a computer with a fresh install of Windows XP SP3 and it is able to access the database file without a problem. So it seems that this error that I am getting is somehow specific to Windows 7. Is there maybe a known issue with Oledb drivers on Windows 7? My version of Windows 7, btw is 32 bit.
I'm trying to get a save file dialogue to overwrite a file with the same name.
Private Sub Button6_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button6.Click
If RadioButton16.Checked Then
[code]....
I keep getting an error saying "Unhandled exception has occurred in your application." Then the next paragraph says "The process cannot access the file 'E:Copy of Release+Fontsob.txt' because it is being used by another process."
The fact is I'm making an application, which users can install by using a Setup file...once installed the data in the database can be updated by a centralized server. To do this, they can insert a DVD/CD-ROM and export the necessary data towards it. I need to do it that way, because some of the users who really need this data will be using stand alone computers.The application gets it's data from a mdb-file and the connection remains open as long a person works with the application (maybe not the best way to do, but I know :-) )...when the user uses the application, he can perform an export...this exports the .ini-file and pictures (which works fine), but he also needs to export the mdb behind the application...I already tried connection.close() before and connection.open() after the System.IO.File.Copy...but that doesn't seems to work.
View 2 Repliesi m creating a simple application that will open files which located in the CD rom... this is wat i got now
System.Diagnostics.Process.Start("F:Test\testing 1-test.pdf")
its works well.. but then not everyone CD rom drive is the same,anyway to do it as open the file without concerning the cd rom path??
i want to open a html file. i need the file name to show in textbox2 and the full file path without file name or extension in textbox3 , while the file content is opened in textbox1. the file content opens fine. this is the code i have:
Private Sub open_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles open.Click
OpenFileDialog1.InitialDirectory = "C:Documents and SettingsOwnerDesktopweb design"
[Code]....
i want to open a html file. i need the file name to show in textbox2 and the full file path without file name or extension in textbox3 , while the file content is opened in textbox1. the file content opens fine.this is the code i have:
Private Sub open_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles open.Click
OpenFileDialog1.InitialDirectory = "C:Documents and SettingsOwnerDesktopweb design"
OpenFileDialog1.CheckPathExists = True
[code]....
I need to delete certain files in a directory so if the file is opened....suppose a xx.doc file i wont be able to delete.
View 6 RepliesI want to make my program so when you click button2 an explorer window opens up going to C:Users. How DO i do that?
View 7 RepliesI have a problem on my project homework to make data CRUD files from drive which files upload using openfiledialog.my problem is I don't know source code how to open file from table, if I click path then open file (likes links url. I try to search but until now I can't found it.
View 3 RepliesI have a database that contains a file path in 4 of the columns. I am using VB Express 2008 on Windows 7 (I have already figured out the 32bit to 64bit problem while working with access databases). This path is generated from code on another form. I have a datagridview that contains the path in a columns. i want to be able to click on the file path column and the file (in this case it is either a .jpg or .pdf) opens.
View 6 RepliesI am working with Visual Studio 2008 to concieve a small program.pdf file is supposed to open when a button is pressed. It work great with the code:
System.Diagnostics.Process.Start("<Full File Path>")
Only, I would like to place the pdf file in the project's folder and that would open wherever the project's folder is (on the Desktop, a USB port, anywhere).
1- How to get this relative path?
2- in which folder to put the pdf?
Is there a way to write a list of all paths and file names of currently open files. The best I can do is use the System.Diagnostics.Process class to grab the processes of the applications in which I am interested and then get the file name from the main window title for each process. There is no way to get the path for these files, however, with this approach.
View 5 RepliesUsing Application.GetOpenFilename I'm wanting to direct the user to a url file location but cannot get the chdir function to change to a valid url. Is there another method for this?thanksegchdir "http://mysite/reports/" (this bit doesn't work)Application.GetOpenFilename ("*.csv,*.csv")
View 1 Replies
