Open File Retain The Directory Of The Last Opened File?
Jan 10, 2010
So I open files and do whatever with them right. I've set the initial directory to equal the last directory, but whenever I open multiple files, it never sets the directories properly. It acts as though nothing was opened there, so it takes the previous directory as the last one. Thoughts on what's not working? Here's the code.
Code:
With FileOpenDialog1
.InitialDirectory = LastDirectory
If .ShowDialog = DialogResult.OK Then
[code]....
I have multiselect enabled earlier and everything else works but this. When you open a single file, the last directory works fine. It only happens with multiselect.On another note, does anyone know why it freezes when I try to do a lot of files and use another program? I opened 700+ files to see what would happen. When I switched to a IM convo, it froze. When I left it to run, it worked.
Is there a better way of finding the path of a file that was opened with the open file dialogue? This is what I did. It works, but it seems like there should be a way to get the path through one of the open dialogue options.
Code: 'm_PicSource = OpenFileDialog1.FileName 'm_PicSource is a global var Dim strCnt As Integer = m_PicSource.Length - 1
I made a quick search program so when I browse for a text file, it adds that text file to a listbox1. And then when you search result will be placed in listbox2 Now I'm wondering how to force the program to automaticly load last opened text file on startup.I tried with this and then I stuck.
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim reader As IO.StreamReader = _ New IO.StreamReader(winDir & "system.ini")
I have a WinForms application that I have taken over support for and it was build using Visual Studio 2005 with VB.Net. The application makes use of an Access database. It runs fine when it is installed as a standalone application, but the install cd for the application also allows for a network install and this is where I am currently encountering issues.
To test the network install I created a folder on my server (Windows Server 2003 SP2) and copied the Access database to this folder. I created a share for this folder and gave everyone full permissions to the share. Then on the workstation I installed the application and gave the path to the database as follows:
\myservermysharemydb.mdb
(The install steps here are as per the instructions given on the installation cd)The workstation that I installed it on is Windows 7 Ultimate. When I run the application, I get the error message given in the title when the application tries to read the database file. I have confirmed that I am able to write to the shared folder on the server, so I don't think this is a permissions issue. Also, the database file is not in use at all, so it is definitely not opened exclusively.
UPDATE:I have tested the workstation installation on a computer with a fresh install of Windows XP SP3 and it is able to access the database file without a problem. So it seems that this error that I am getting is somehow specific to Windows 7. Is there maybe a known issue with Oledb drivers on Windows 7? My version of Windows 7, btw is 32 bit.
The fact is I'm making an application, which users can install by using a Setup file...once installed the data in the database can be updated by a centralized server. To do this, they can insert a DVD/CD-ROM and export the necessary data towards it. I need to do it that way, because some of the users who really need this data will be using stand alone computers.The application gets it's data from a mdb-file and the connection remains open as long a person works with the application (maybe not the best way to do, but I know :-) )...when the user uses the application, he can perform an export...this exports the .ini-file and pictures (which works fine), but he also needs to export the mdb behind the application...I already tried connection.close() before and connection.open() after the System.IO.File.Copy...but that doesn't seems to work.
how can i open file .exe in the same my application directory i tried Call Process.Start(IO.Path.Combine(Application.StartupPath, filename))but it open my application not anther one?
How do I get a file's directory when open with or send to event happens?I want it like media player, the application can get the file name & path when the user runs it with Open With.
I'm running in to a bit of a strange error with an application I'm writing. I have a number of shortcuts on my computer desktop that take me to my various folders (documents, music, etc) and have always been able to navigate using them when I open a file through applications such as Word. However when I use an OpenFileDialog box in VB.NET and select one of these shortcuts to take me to the file I'm after I am getting the following error message...
I have several groups of files with idential names, but the files inside may or may not have identcal names, and may differ only in the size or date stamp. I want to combine them to save all unique directory names, and unique file names, and if the date/sizes are unique, then add some number on the end of the file name to make them unique as well. Only idential file sizes and names and dates will be discarded. How do you open directories to compare directory/file names and other properties?
I want my program to be able to create a '.txt' file when it is run for the first time, with the date and time the program was accessed, and to be able to add new 'logs' of program history every time it is accessed. What i mean is that i want my program to be able to create a '.txt' file, and then fill in the dates and times when the program is opened.
I have a small requirement and that is as follows: I have opened a file using the "openFileDialog" provision and i have set the filer as (*.txt). Now when the openFileDialog is displayed, only the test files are visible, but the user can also select "All Files" and choose any other file type.Now what is require is that, if a file type other than .txt is selected by the user, i want to display an error message. So is there any provision by which i can get to know the file type that is selected by the user.
i just want to ask how can i save the file location or directory of a file in mysql without deleting its slashes...i tried to save it directly.. for example: the original directory is c:folderimg.jpg and when i checked it on mysql it is save as c:folderimg.jpg
Anyways, i have coded a video downloaded and i want to include a converter as a separate exe file. But obviously people may have different file directories so a simple piece of code i have used won't work. This is what i have: Also where would i place the exe file?
I can't connect to my database now, although yesterday it was perfectly fine. An error message comes up saying "...A database with the same name exists, or specified file cannot be opened, or it is located on UNC share" this has never happened before. Why can't I access my database?
I have created a windows application which creates a database file and saves it to disk, it uses a custom file extension so that when the file is clicked it opens the application. In order for the application to use the data in the file it needs to rename the file so that it has a .mdb extension. My problem is that I cannot see how to get the name of the file which opens the application.
I'm exporting my Dataset to an excel file, and I want to make sure I keep any file errors under control. One in particular that I'm concerned about is accessing a file that's already open. A general IOException occurs that says: "The process cannot access the file 'C:Reports eport300.csv' because it is being used by another process."
Here is the line in which the error will occur: Dim output As New IO.StreamWriter(path, False, UnicodeEncoding.Default)
I guess I could just throw a try catch around it, but what if an IOException happens that isnt related to this particular incident? Is there a way I can check to see if the file is already open before allowing this code to run? Especially when I'm using excel.
How can I upload an image 1.png into the program and then once the program is opened, that image gets saved here:LibrariesDocumentsand if there is already a file called 1.png in that directory.
After I started running my code, I was told "Error opening file". Can anybody tell me what's wrong? Also how to retrieve each byte on each line to array HexValue?
I'm creating a simple .NET console application where I want to save a file in a folder that's part of the root project, like so: SolutionName.ProjectNameTestData. I want to put test.xml into the TestData folder. However, when I go to save my XDocument, it saves it to SolutionName.ProjectNameinx86Debug Console est.xml.
I want to have an icon / image of a folder on my form and I want it to operate just the same as a desktop shortcut to a directory does. If clicked, it opens directory, if file / folder is dropped onto it it sends those to the specified directory.I am however going to need to use something like this:[code]
copying the file from one Directory to another directory by create the folder if that folder is not exists in destination directory.Example:
Source path: C: emp est1.txt destination path: C:Data if C:Data doesn't contains "temp" or "test" folder, it should create the folder before copy the 1.txt.[code]....
I'll tell you what I'd like to do which is to create a directory listing of every file inside a specified directory and then use a loop to upload each file in this directory to a remote folder via FTP.