Open Last Opened File?

Mar 15, 2012

I made a quick search program so when I browse for a text file, it adds that text file to a listbox1. And then when you search result will be placed in listbox2 Now I'm wondering how to force the program to automaticly load last opened text file on startup.I tried with this and then I stuck.

Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Dim reader As IO.StreamReader = _
New IO.StreamReader(winDir & "system.ini")

[code].....

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Finding The Path Of A File That Was Opened With The Open File Dialogue?

Jun 5, 2009

Is there a better way of finding the path of a file that was opened with the open file dialogue? This is what I did. It works, but it seems like there should be a way to get the path through one of the open dialogue options.

Code:
'm_PicSource = OpenFileDialog1.FileName
'm_PicSource is a global var
Dim strCnt As Integer = m_PicSource.Length - 1

[Code].....

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Jan 10, 2010

So I open files and do whatever with them right. I've set the initial directory to equal the last directory, but whenever I open multiple files, it never sets the directories properly. It acts as though nothing was opened there, so it takes the previous directory as the last one. Thoughts on what's not working? Here's the code.

Code:
With FileOpenDialog1
.InitialDirectory = LastDirectory
If .ShowDialog = DialogResult.OK Then

[code]....

I have multiselect enabled earlier and everything else works but this. When you open a single file, the last directory works fine. It only happens with multiselect.On another note, does anyone know why it freezes when I try to do a lot of files and use another program? I opened 700+ files to see what would happen. When I switched to a IM convo, it froze. When I left it to run, it worked.

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Sep 1, 2011

I have a WinForms application that I have taken over support for and it was build using Visual Studio 2005 with VB.Net. The application makes use of an Access database. It runs fine when it is installed as a standalone application, but the install cd for the application also allows for a network install and this is where I am currently encountering issues.

To test the network install I created a folder on my server (Windows Server 2003 SP2) and copied the Access database to this folder. I created a share for this folder and gave everyone full permissions to the share. Then on the workstation I installed the application and gave the path to the database as follows:

\myservermysharemydb.mdb

(The install steps here are as per the instructions given on the installation cd)The workstation that I installed it on is Windows 7 Ultimate. When I run the application, I get the error message given in the title when the application tries to read the database file. I have confirmed that I am able to write to the shared folder on the server, so I don't think this is a permissions issue. Also, the database file is not in use at all, so it is definitely not opened exclusively.

UPDATE:I have tested the workstation installation on a computer with a fresh install of Windows XP SP3 and it is able to access the database file without a problem. So it seems that this error that I am getting is somehow specific to Windows 7. Is there maybe a known issue with Oledb drivers on Windows 7? My version of Windows 7, btw is 32 bit.

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May 14, 2010

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Currently i'm opening childforms like this:

Dim backupform As backup
backupform = New backup()
backupform.MdiParent = Me
backupform.Show()
MenuStripFix()
backupform = Nothing

How can I make it so if the menubar is clicked and if the childform is open, the open childform is showed and not a new one.

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Forms :: Open Link In Opened Tab?

Feb 2, 2010

I have multiple tabs opened in 'any browser' and one of it is titled 'LAME', how can i make links open(by buttons) in that tab? I have a simple form with two buttons,

Button one:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Process.Start("http://www.google.nl/sub1")
End Sub

[code]....

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I want my program to be able to create a '.txt' file when it is run for the first time, with the date and time the program was accessed, and to be able to add new 'logs' of program history every time it is accessed. What i mean is that i want my program to be able to create a '.txt' file, and then fill in the dates and times when the program is opened.

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I can't connect to my database now, although yesterday it was perfectly fine. An error message comes up saying "...A database with the same name exists, or specified file cannot be opened, or it is located on UNC share" this has never happened before. Why can't I access my database?

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Apr 24, 2009

I have created a windows application which creates a database file and saves it to disk, it uses a custom file extension so that when the file is clicked it opens the application. In order for the application to use the data in the file it needs to rename the file so that it has a .mdb extension. My problem is that I cannot see how to get the name of the file which opens the application.

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May 26, 2010

I'm exporting my Dataset to an excel file, and I want to make sure I keep any file errors under control. One in particular that I'm concerned about is accessing a file that's already open. A general IOException occurs that says:
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Here is the line in which the error will occur:
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I have the following code to open an Intel format hex file. The file is like this

:020000040000FA
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:1000100000000000000000000000000000000000E0
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[code]....

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Nov 29, 2011

I tired this code to check if the Excel File is already open but didn't succeed

vb
Dim exl As New Excel.Application
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I have the following line of code used to input the name of a text file to be opened and during development this was working without a problem. However when I create an executable this is not working and I was hoping someone would be able to give me a tip on resolving this matter.

Dim fileName As String = Application.StartupPath & "" & TextBox1.Text

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Public Class ExtendedDateTimePicker Inherits DateTimePicker

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I am trying to write text to a file in this path "C:\Test\test.txt" and when I want to save image filenames to this path I need to check if the file is opened and if it is opened I need to close the ".txt" file and write the text to the text file.[code]...

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Oct 21, 2011

I'm working through an example in a programming book and stumbling across a problem that I can't seem to figure out. The program in question is basically a very basic 'level viewer' for a tile based bitmap game (its a game creation book). The source code from the author was written for Visual Studio 2005, and I am using 2010. The source code imports fine and the program runs correctly.

I built the same program on my own, starting from scratch in VS2010. The program works like this: It opens a tile set palette (bitmap form), then uses an XML file to create a 'level'. The XML file indicates which tile goes where on the 'level'. The XML file is roughly 1.9MB and has roughly16,000 entries (the program creates a level that is 4096 x 4096 pixels using 32 x 32 pixel tiles).

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I've tried to track down any differences between the source code and my code, and the only thing that I have found is that the References in mine are all using .NET version 4.0 and the references in the source are using mostly 2.0 and some 3.5 (System.Data.DataSetExtensions, System.XML.Ling.dll, and System.Core.dll)

The code for the entire form is:

Imports System.Xml
Public Class Form1
Public Structure tilemapStruct

[Code].....

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HTML
System.Diagnostics.Process.Start("C:up.exe")

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i have an application that used for entering some modification on images but what i want is that when somebody open any image using right click then "open with" and choose my application program then the image translated to the picturebox in my program so i need to know the code of the image path?

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