would like to know if it is possible to have my application launch and open a file which will be called todays date. its just a simple text file and i am basing it on the streamreader style function.
View 9 RepliesI get mixed results in Google, so I'm wondering how can I simply launch a ReadMe.txt file in Notepad thats in the same directory as my application?
View 1 RepliesI am trying to use the open file dialog box in VB 2005 to open up an existing txt, or rtf file from a directory into a rich text box. I am able to get the Open file dialog to appear and the directories, but when I try to open the file it doesnt import it into the text box. Here is the code I am using
[Code]...
I would like to open the excel file after create the excel file. The creating file function is done, but the system unable to open the excel file. My coding as below:
Dim xlApp As Excel.Application
Dim xlWorkBook As Excel.Workbook
Dim misValue As Object = System.Reflection.Missing.Value
[code]....
I am writing an updater for our application and having an issue overwriting the files. Here is a long drawn out example. Test.exe is our main app and update.exe is our updater application. Test.exe needs to launch update.exe and then close test.exe. Update.exe will download the new updates from our website to a temp directory and then copy in the new updates. The problem I have is when Test.exe has an update and I try to copy in the new file it says it can't because test.exe is still in use. I "believe" this happens because test.exe is still running in the appdomain because update.exe was launched from test.exe before I closed that app.
View 1 RepliesI have this
[Code]...
That codes will execute the "xsentinel.bat".. But, is there any ways that I can use to made the "xsentinel.bat" will running in background (Sys Tray)?
I'd like to know how you can actually select(highlight) a program from a list of programs displayed in a list box in Windows Form. I've done research and most results end up with openFileDialog condition or have to manually type the directory path. But what I have currently is the display of a list of programs in a list box(like Add/Remove Programs) but I'd like to have the user launch it upon double-clicking or clicking on a button(after a program is highlighted).
In short, it's like selecting a program in Add/Remove Program but instead of the Uninstall button, I want it to be a Launch button. I believe I already have the executable path behind the codes with the registry so I just need to know how you can select, and launch.
(Below contains an example of the kind of code I'm having)
Public Partial Class MainForm
Public Sub New()
' The Me.InitializeComponent call is required for Windows Forms designer support.
Me.InitializeComponent()
[Code]....
I have a text box in which a file path is displayed. A button to click and open the file. Code executes properly but the file doesn't open. [Code]
View 4 RepliesOn my computer I've VB.net 2005. and also office 2007. I try to open an excel file like that
Imports Excel = Microsoft.Office.Interop.Excel
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, _
ByVal e As System.EventArgs) Handles Button1.Click
[Code].....
How can i open chm file in VB.net 2005 ?
View 1 RepliesHow to open Executable File in VB.Net 2005
View 2 RepliesThe following code works to check if a file exist, but I need to also check if the file is open.How would I do that?
If System.IO.File.Exists(Application.StartupPath & "players.txt") = False Or System.IO.File.Exists(Application.StartupPath & "preferences.txt") = False Then
bla bla bla
End if
When the main program is doing it's routine, it is looking at, and using, data from the two files.So, when the user pauses the program by opening the control panel, one or both of the files may still be opened. When the control panel tries to open them, it causes an error.(I am guessing that to just tell it to close them will cause the same problem if they are already closed.)
At home I use Visual Studio 2008 Pro but a class of mine is trying to have us use Visual basic 2005 express edition. Since we need to submit source code files will there be a problem if I just submit the .vb file instead of the whole solution?
[Code]...
I'm looping through a csv file. For each line, I'm reading certain values, generating a filename, and writing the record to that file. Here is some logic
If <something that doesn't matter happens> Thendo somethingElseIf File.Exists(strOutFile & (strOutputFileName & "__" & strPrefixFileName & ".txt")) Then
strFullFileName = strOutputFileName & "__" & strPrefixFileName & ".txt" '** Double Underscores after app name
tsOutfile = New StreamWriter(strOutFile & strFullFileName)
[Code] .....
Now, obviously with the above code, there's no reason for the elseif, since they both do the same thing. The problem, however, is if I need to create a new file and write to it, everything works fine. In fact, everything will work perfectly until I need to write to a file that I already created. If I go ahead and just try "tsOutfile = New StreamWriter(strOutFile & strFullFileName)" and point it to the already existing file, I get a permission error (says the file is already open). Is streamwriter keeping an open connection to all of these files that I create? Nothing else in the program is touching these files, only streamwriter.
Here's a quick example to illustrate what is happening
Record 1 goes to file A
Record 2 goes to file A
Record 3 goes to file A
Record 4 goes to file B
Record 5 goes to file B
Record 6 goes to file B
Record 7 goes to file C
Record 8 goes to file A (Error will occur here)
I m developing an application, where I would like the user to open an existing excel file inside the Application itself (Form)
View 1 RepliesIn my scheduling app I am exporting information to an excel file. When the first export runs it opens a new instance of an excel workbook. I have decided to save each schedule (AMRN, PMRN, AMTech, PMTech etc) to separate works sheets instead of appending the first worksheet. This way when the shedules need to be printed the whole workbook can be selected to print. When I try to open the existing workbook if it exist I get an error. Here is what I am trying to do.
vb.net
Dim xlApp As excel.Application
Dim xlWorkBook As excel.Workbook
Dim xlWorkSheet As excel.Worksheet
[Code].....
I am building an internal web page which retrieves binary data from a SQL database, converts the binary to an image file, then opens the file on the clients PC.In debug mode, this works fine, because the program downloads the file successfully into a temporary directory, converts it to the image then uses System.Diagnostics.Process.Start() to launch the image file in the associated image viewing program.However, as soon as I upload it to the server, two undesired things happen:
a. The file gets saved on the servers temporary directory, instead of the client temporary directory (I kind of expected this to happen, so this wasnt much of a suprise)
b. System.Diagnostics.Process.Start() does not launch the file successfully. Nothing actually happens when it gets to this part of code, however I suspect that it is trying to launch the process on the server end, instead of the client end.
how I can get System.Diagnostics.Process.Start() to launch on the client end OR how I could get the image to just appear in the clients web browser instead?
I am trying to open an excel file and write to it as data becomes availableI can create an instance of excel and write to the selected worksheet once. But, I can't seem to write back to the existing file. I keep on getting a null reference error when I try to send new data to the file.The function I am using will run once, but when it returns to the main form, I lose the values of xlApp and xlWorksheet. It appears that going in to the function makes the original values null.
View 2 RepliesI am using TextFieldParser to read a .txt file and create a DataTable I then filter the table and create 4 new tables I then bind those tables to BindingSources Then Bind ComboBoxs to the BindingSource Then bind TextBoxes to BindingSource I like the user to be able to Open a new file without having to close the program So upon opening a new file I have a sub routine that clears the tables the rows and the columns of each table as well the DataBindings to each control The problem is once I do the Text Binding as such
Me.list1_MLStxt.DataBindings.Add("Text", Subject_Values.BindingSource1, Form10.mls_txt.Text)
Then when I open a new file I get an error message conversion from string"""" to type double is not valid.If I never perform the binding I can open and reopen different files without a problem. So this is causing me to think that the problem is with the way I am clear something? But I am obviously not sureIs there something I am missing to clear everything properly in order to open and read and bind a new file?
I need to make an E-Search engine for collage library , i can make it by using streamReader and streamWriter , but unfortunately i have to use Binary to make this project ... i've to many fields to put it on DAT file , and i've to use SPLIT to split lines and make arrays ..
what is the best way to do that ? how can i write an opened binary file on textbox and convert text to array ?
Suppose I have this Dim proc As Process proc = Process.Start("Notepad.exe", "C: est.txt") Now, if I want to use Notepad.exe to open another text file (ie. C:2ndTextFile.txt) without closing it, how am I going to do it?
View 7 RepliesI'm trying to write a program that will open a solidworks file in EDrawings and print it and so far the only way I can find to do that with an edrawings ActiveX Control displayed on my form.Does anyone know if it's possible to print drawings via EDrawings 2009 without the ActiveX Control having to be displayed on the form as that is drastically slowing down my program?
View 5 RepliesI have a open and file save dialog which I use to open and save file. There are also some labels in the application. During the time a file is open or saved, the file open /save dialog becomes blurred by the background labels. Is there any way to prevent this? The attached pic is given as an example to explain the dilemma.
View 1 RepliesI'm building a program to launch certain windows tools for administrators, but I can't get it to launch the Windows Memory Diagnostics Tool.
Public Class Hardware_Tools
Private Sub btnWMDT_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnWMDT.Click
System.Diagnostics.Process.Start("C:WindowsSystem32MdSched.exe")
End Sub
End Class
Gives me an error saying the "The system cannot find the file specified". I copied the name and path exact.I'm using Visual Basic 2010 Express and advanced compiler option set for the .net framework 4 . On a Windows Vista Ultimate 64 Bit pc.
It am trying to launch this code that would normally run from a batch file
Batch file code:
@ECHO OFF
SET BINDIR=%~dp0
CD /D "%BINDIR%"
"%ProgramFiles%Javajre6injava.exe" -Xincgc -Xmx1G -jar craftbukkit-0.0.1-SNAPSHOT.jar
PAUSE
[code]....
When I run the code cmd.exe opens but then nothing happens?
I have a program with an associated file type. However, when I double-click a file to launch the program, I can't figure out where that path was passed to the program.Initially I thought the file path would be in Environment.CommandLine, but the command line only contained the program path.I specified the file association using the Publish Options in visual studio like so: extension: .ext, Description: Some File, ProgId: ProjectName, Icon: SomeIcon.ico.
View 2 RepliesBasically, what I want to do is launch an *.exe file when I click on a button. I want this done in VB.NET. I have Microsoft Visual Basic 2008 Express Edition.The button I have is called 'btnYES'.How can I launch an *.exe file from the click of this button?
View 1 Repliesi would like to know how i would make a button make an application launch
i have seen people say use the shell command but i cant get it right the button code name is Button1
When running an executable file (written in FORTRAN) directly, there is no problem creating output text files. However, when launched from Visual Basic Express 2008, those reports are not generated. I also observe that the program launched from VB does not wait for a user prompt as it should. What am I missing?
Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click
Process.Start("c:applicationpistonsimulator.exe")
[code].....
Whenever I use this code, I get a File Not Found exception, even though the file paths are all correct. [code]...
View 3 Replies