VS 2010 - How To Get Part Of String
Dec 10, 2010
Public Class Form1
Private Sub but_convert_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles but_convert.Click
Dim input_string As String
Dim output_string As String
Dim fkey_string As String
[Code] .....
So, the big thing is that I want to use that code to transform this:
if(strcmp(cmd, "/quitjob", true) == 0) {
if(IsPlayerConnected(playerid)) {
if(GetPVarInt(playerid,"job") > 0) {
[Code] .....
The problem is that I get an empty text box when I click the button.
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Oct 9, 2010
I have a file location as a string. How can i remove the path from the string and just use the file name? For example:c:filesfile.zip - is the stringhow can i just make it so it's file.zip?keep in mind that the location is found by using anpenfiledialog(), so it needs to be able to remove the location wherever the file is.
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Apr 17, 2012
I have a string of 5 characters out of which the first two characters should be in some list and next three should be in some other list.How could i validate them with regular expressions? [code]My Strings are going to be: VBBEG, CSBEG, etc.My regular expression should find that the input string first two characters could be either VB, CS, HT and the rest should also be like that.
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Sep 14, 2011
One number is represented with four hex values.First two hex parts are my "whole number" part, third and fouth hex numbers are my "decimal" part. I just wanted to store my complete number (whole and decimal) in an excel table.My problem is following when I am storing whole part and decimal part of my number separately, then it works fine am getting f.e. 3017 and 0,9445123 in my excel table, but when I am concatenate them, then I am getting following expression in my excel table f.e. 30,179,445,123 but I want 3017,9445123.
rx_str_buf(str_cnt) = CStr(Convert.ToInt64((Hex(rx_str_buf(Factor + 7)) & Hex(rx_str_buf(Factor + 8))), 16) +
(Convert.ToInt64((Hex(rx_str_buf(Factor + 9)) & Hex(rx_str_buf(Factor + 10))), 16) / 65536))
[code].....
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Dec 10, 2011
I need to retrieve an html page and then isolate part of the code. First, I have a large bit of html. I need to find this:
[Code]...
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Feb 11, 2011
I am trying to find the best way to extract parts of a string within a string. Take the following line:
[Code]....
How can I say extract just "16" for the height field?
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Jul 6, 2009
How do i detect a part of a string from a string? For example: i want to check if the part of the string "mummy" exists in a string:"Mummy loves Daddy and loves me too"
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Jul 12, 2009
how do I get a bit of a string? Here is an example:
I have a string:
Hello, my name is James, and I was born on 10.5.1990
How can I get the last part of the string (10.5.1990)
note that the last part could vary in length and could be any other date (but in that format)
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Jun 15, 2012
How to cut part from this string..."abb.c.d+de.ee+f.xxx+qaa.+.,,s,"... where i know position by this: Result is always between "." (left side of result) and "+" (right side).I know number of "." from left side and number of "+" from right side, to delimit resulting string.Problem is right side, cause i need to count "+" from end.
Say...
from left side: begining is at 4th "."
( this is easy ), result is =
[code].....
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Sep 7, 2009
I would like to display only part of string. I am able to do that as long as my string is constant, how the string is not constant. How would display only the last part of my string. The string will actually be displayed by using a browse button and selecting a file.
[Code]...
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Sep 16, 2010
I'd like to be able to store the word swimming, the 2 words either side are always the same but the text before and after that is different each time.
Basically I'd like to be able to grab a piece of text in between 2 strings.
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Sep 23, 2011
I want to extract part of a string starting at a specific character, in this case the asterisc[code]...
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Sep 5, 2010
I want to make a function that takes a string and then returns only a specific part of that string.
The string the function will take is a path to a file such as
D:FolderFolder2Untitled Document_1_2.tif
What i want the function to do is return the
Untitled Document_1
Portion of the supplied string.
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Jun 2, 2009
how do I remove a certain part of a string, but I don't know what it will be, I only know that it will start with: [Code]
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Jan 6, 2011
i have the folowing problem: i made a combobox on my form and in order to add items to it i use a normal textbox and a string in application settings, the textbox add's the item in both the combobox( with this code ComboBox1.Items.Add(TextBox1.Text) ) and the string in application settings with the folowing code:
[Code]....
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Apr 9, 2011
How can I remove all of the text to the right of the second to last / in a string.
Before = ftp://sylenttechnologies.com/text/test/another test/
After = ftp://sylenttechnologies.com/text/test/
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Jan 23, 2010
I would like to have a only part of a string... I have a string[URL] and i want only the part thats past the last / so i would actualy get only "file.part4.rar"I know that this can be done through Regex, But I have never used that, and I read the documentation on it, but I do not understand the part of...
Dim rx As New Regex("^-?d+(.d{2})?$")
What dose each of those characters do and how dose it effect the output...
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Feb 3, 2011
I have a load of content as shown below:
<td width="20%"><a href="/search?tbs=shop:1&q=camping+lantern&sampleq=1">camping lantern</a></td>
<td width="20%"><a href="/search?
[code].....
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Jun 16, 2009
I have a string which look like this
dim abc as string
abc = "example=1234"
I would like to remove everything before "=" and "=" so that i would only get "1234". How can i do this.
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Sep 21, 2009
I am thinking of the best way to remove part of a string. Here is my String value[code]...
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Jan 12, 2011
is there anyway i can remove part of a string? if i had this string here "REMOVETHISPART-KEEPTHISPART" in a listbox how can i just remove "REMOVETHISPART-"
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Feb 10, 2010
I have an object folder, which has an atributte name path, that contains a string with it's current path, say "folder1folder2folder3"
I need to remove the last ocurrence beginning on the last "" (in this case, 'folder3'). The new string would be "folder1folder2"
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Aug 5, 2011
I have several values in a column like: [code]I would like to retrieve only the values (I mean without KB, Bytes..etc).How can I do that?
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Oct 26, 2009
I'm looking for a way to cut out unneeded text from a string. The remains of the string should be "Result: Sucesfull".
Example strings:
[Download Report]
26 october 2009
Result: Succesfull
[Code]....
As you can see the string in my first example contains 3 lines, and the second example contains 5 lines. In my application they differ depending on the situation. I want to cut out all lines, except for the line starting with 'Result:', which I want to display to the user of the application.
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Jun 10, 2010
I have an ArrayList, and i wish to search it for a specific part of a string. Like the InStr() function.I can only find the WHOLE string. The ArrayList has strings like "This=Is A String", so if i do a check with ArrayList.Contains. It will only search for the whole string, and not something IN the string. Perhaps i need something like Starts With .
Code:
dim wordArr as New ArrayList
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
If wordArr.Contains(TextBox1.Text) Then
[code]....
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Sep 7, 2010
i am trying to locate the id of a field using the binding source, if i type the full id, it is locating it successfully no problem, but that is not what i want, i want to type 3 digits of the end of the id and be able to still locate that record. i triedusing wildcards with it "%" with no success any suggestions?
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Jun 12, 2012
For removing trailing part is I use the code
str.substring(0,str.length -2)
Is there a better way? I especially dislike using str.length.
Edit I wanted the question to be as short and simple as possible and I supposed that I just overlooked some String method. I try to be more precise.
I need to remove given number of characters from the end of a string. I don't want to care what the characters are and I don't want to introduce a risk of removing more characters.
If the number is larger then string length let's there is an exception (the string should be validated earlier).
I don't have the problem especially with length, but with referencing a variable twice (imagine a function instead of a variable). I also don't like necessity of subtraction but it is only a personal preference.
The question is taged vb.net so there is vb.net code (should be in a module):
<System.Runtime.CompilerServices.Extension> _
Public Shared Function RemoveFromEnd(stringValue As String, removedCharacters As Integer) As String
Return stringValue.Substring(0, stringValue.Length - removedCharacters)
End Function
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Aug 31, 2010
I am trying to extract the bracketed region of a string into another string. For example
(abc) - (xyz)
How would I extract the 'abc' and 'xyz' into two separate strings?This is what I have tried to do so far:
If (operation.Contains("(")) Then
Dim first = operation.Split("(")
Dim firsteb = operation.Split(")")
But I then got confused because I could not work out how to avoid it from going to the first and last brackets in the above example?
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Aug 12, 2009
Using vb.net 2003 asp.net 1.1. I have this C# function that I converted and I gettinga squiggley saying full and partial not part of string, this is converted from a .cs file.
Here is the function, maybe I'm not seeing something:
Code:
Public Function RefundTransactionCode(ByVal refundType As String,
ByVal transactionId As String,
ByVal amount As String,
ByVal note As String) As String
Dim caller As CallerServices = New CallerServices
[Code] .....
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Jun 9, 2011
I am trying to make a program which outputs an Invoice Number, which consists of the first 3 letters of a person's first name and the last 3 digits of their zip code. The user enter their first and last name, then enters their city, state, and zip such as:
Name: Billy Jones
City, State, Zip: Chicago, Illinois 42349
Therefore, the invoice would look like:
Invoice: Bil349
I can get the first 3 letters of the first name fine using the substring function, but I have been stumped on how to get past all of the text to get the last 3 digits of the zip code entered.
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