Generate Random Double Values Between Range?
Dec 21, 2009how do i generate random double values between range, for example:value between 2.50 to 3.50?
View 7 Replieshow do i generate random double values between range, for example:value between 2.50 to 3.50?
View 7 RepliesThe object of this project is to write a computer program that will allow the computer to guess a number that you have selected. The computer will make a guess and you, the player, will tell the computer if it guessed too high, too low, or that it guessed the number.The program will also allow the player to start a new game or to exit the program. PROJECT INSTRUCTIONS:
1. Create a form with a labeled box to display the computers guess.
2. Create a new game and an exit button.
3. Create objects to indicate if the guess was too high, too low, or right on target.
4. Create program code to respond to the player�s indication by selecting and displaying a new computer guess.
5. When the computer guesses the player�s number, reset the so that a new game may begin.
I have done all as above and so far my code looks like so
Public Class Form1
Dim Guess As New Random()
Dim HGuess As Integer, LGuess As Integer, current As Integer
[code]....
The problem i ran into is that if for example a user has a number 24, when the program makes an initial guess of 50,i want to be able to click low, and the program should generate a lower number say example 22. If i then click higher as my actual number uis 24, the program should not shoot higher than a number it has previously guess incorrect (in this case 50) it should guess anywhere from 22 - 49 and in turn limit the range of the next consecutive guesses it till hits the right number. My code right is guessing as it shuold but not within the limited ranges.
Why isn't this possible? NextDouble(-0.75, 0.76)
How can I do it another way?
I know that there is a way in which you can generate any random number between any range using the random variable. But my question is that is there any way to do the same thing but with letters?
View 1 RepliesI am coding a lottery number generator for a homework assignment. My project needs to have functions that return random values based on a range given. The first function I am coding is for a pick 3 lottery game.The function should return three random numbers between 1 and 9. I have coded the function but it only returns one number. When the debugger runs it says my function does not return a value on all codepaths.
[Code]...
how can i do this ? i new how to but i forgot and i need it right now
View 2 RepliesI am using the following code in the Load method of a VB form to generate random numbers in the range 1 to 8. Without fail after enough loops the range is exceeded and 9 is the random number returned every time. The line using the Rnd function is from: Rnd Function (Visual Basic)
[Code]...
I am trying to make a texas hold em game and it is of the utmost importance that my code generate a random number. But using a random number function that I always end up with a lot of the same numbers over and over again. Any ideas on how to make it "TRULY" random? [code]
View 3 RepliesVS2010 (SP1) / .NET 4 on Windows XP. The question is simple, the answer; not so much. When generating a salt, should the LENGTH of the salt be random, fixed or a random number within a (min/max) range? I am using RNGCryptoServiceProvider to generate the salt, just unsure of the length of the salt.
View 12 RepliesGenerate a list of IPs from a range
View 18 RepliesHow would I go about generating a unique receipt number in the following range:
GA00000-GZ99999? I am not allowed to use the 'I' and 'O' letters so GI00000-GI99999 & GO00000-GO99999 would be excluded. Ideally, I'd like to create this in T-SQL but can also do it in VB.Net. This number will be stored in SQL and I can access it prior to generating the next one. They do not have to be sequential.
I'm using VB.NET 2008 Express Edition and I'm trying to create a simple program that will roll a number of dice I choose. It does this by generating a random number within a specified range (I'm rolling 3-sided dice in this case so I'm generating numbers between 1 and 3) and adding each number to a textbox to create a total of all the dice rolled so far.
This is my
Private Sub butRoll_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles butRoll.Click
Dim RandNum, i As Integer
Dim RandomClass As New Random()
'if at least one dice is rolled
If txtD3.Text > 0 Then
[Code] ......
Now the problem I am having is that although my random number generator is generating the right numbers (confirmed by checking the txtLastRoll textbox), when I add it to txtTotal, it seems to be getting another number from somewhere and adding that to my random number then adding it to the total and I have no idea how this is possible! txtTotal always starts as 0 but txt1 is not showing that. Normally I would just set txtTotal to 0 there but if I do that, I won't be able to add the numbers together. I've tried finding a pattern in the mystery numbers appearing in txtTotal but they just seem to be random.
How could I limit the random number range? For instance, limiting the number within the range of 1-100.
View 5 RepliesEDIT: I am so sorry! I have added my thread to the C# discussion thread instinctively wherein in fact I have been creating my application in VB.NET so sorry! Please transfer my thread to the appropriate location! I am currently trying to mess around with a simple mp3 player and am in the process of creating a shuffle list from all the songs in my playlist.
View 2 RepliesI generate csv content type export.
added columns like "A","B","C","D" by
columns = string.format("""{0}"",""{1}"",""{2}""","A","B","C")
stream.writeline(columns);
the csv file was exported but the first column don't having the double quotes. i need double quote with every column. i tried so many ways with in that one of the way is working fine that is columns = string.format(" ""{0}"",""{1}"",""{2}""","A","B","C") -- put space before first column.
but i need result without space.
Sample Code:
Public Class CSVExporter
Public Shared Sub WriteToCSV(personList As List(Of Person))
Dim attachment As String = "attachment; filename=PerosnList.csv"
[Code]....
'm attempting a program and need to generate 10 random numbers between 1 and 52. However all the numbers must be different. I'm trying this in a For Loop. I'm not terribly amazing at this so all I have so far is:
Dim B, I, J, max, min, card() As Interger
max = 52
min = 1
Randomise()
[Code].....
What am I doing wrong and what is the ultimately simple solution I know the internet can provide for me?
I've published a different take on a log in system on CodeProject [URL] and I've got some free time, so I thought I'd have a look at password recovery/reset.It was suggested on the article that I look into sending the account owner a single use, random url where they can reset their password if the account gets locked because of too many invalid login attempts/forgotten password.So far, I'm thinking I just have to generate a random string in a "recovery" field in the database table for the user's row and then check if the requested URL on the site is the same as the value for that field, then dynamically draw the page server-side.
View 1 Repliesi need to create a random string (length of 6) out of the following chars:
"0123456789abcdefghijklmnopqrstuwvxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
How could i do this?
My Sharepoint and Enterprise 2.0 Blog [URL]
This code is in VB6.0I have 28 numbers in sequence (eg 1-28), they are randomly generated and displayed in a label. I dont want a duplicate number displayed in the label. Pls how do I do this. Below is how I generate numbers at random. Now I want to make sure there is no duplicate number displayed in the label.[code]
View 12 RepliesHow to generate random letter but it must between a-z only, I mean is no aa,ab just 1 letter like a,b,c, ..... z.except letter e, because letter e cannot be use as a variable.
View 13 RepliesI need to generate a lot of random 2 character strings for my application. it's a VB console application. basically what I have tried for random strings is this:
[Code]...
I need to generate random strings in vb.net, which must consist of (randomly chosen) letters A-Z (must be capitalized) and with random numbers interspersed. It needs to be able to generate them with a set length as well.
View 5 RepliesSo if you have one button and one textbox; whats the code so when you press the button the textbox comes up with a random number?
View 13 RepliesI have this school assignment to generate random numbers.Can someone please check if this is the right.Also i am not able to Generate this many numbers in the specified range and keep track of how many of each are generated in an array of counters.[code]....
View 35 RepliesI need to generate two different random numbers but this:
Dim r1 As New RandomDim
r2 As New Random
l1 = r1.next (0,1000)
l2 = r2.next (0,1000)
give me random numbers, but they are same any suggestions?
i'm beginer in this forum and new in vb6.how to generate random number in vb6?
is it posible to represent variable in binary?
I have an attribute that I just added to my database to hold confirmation numbers. The only problem is they are all null so I am getting errors. Thus I need a method to generate random confirmation numbers (no duplicates). The column entries have a max size of varchar(20)
Solution:
randNum = Replace(Guid.NewGuid().ToString(), "-", "")
randNum = randNum.Substring(0, 19)
[code].....
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles [code]...
Im getting "overload resolution failed because no access "getobject" accepts this number of arguments. "
Im trying to generate 7 different images in a group box out of 26 images when the form loads.
Generating random numbers in an array HELP
View 6 RepliesI have a code that can generate from letter a to z
here it is
Private Sub GenerateRandomNumbers()
Dim randomObjectName As New Random
randomObjectName.Next(97, 122)
[Code]....
The problem is I'm expecting that the output will be the dim of the letter.
for example the random generated letter is 'a' the output in label1 will be "hi?"