Pay Pal Button Will Not Link To Pay Pal / It Only Refreshes Page
Apr 27, 2010
I have the following code in my registration page to go to a paypal button.But when I click on the button it just refreshes the page. Is their something I am missing? I should be able to include a paypal button on an aspx page right? [code]
I have a basic page which has fields that I read from the database and write to it. I would like to know where I should call the insert and read commands. I know about age_load but heard about page_loadcomplete.I noted that when the user refreshes the page, for some reason the sqldatasource loads the old data(before the write) even though new data has been loaded on the form.
I had a problem with WebBrowser component. Basically, it works improperly when try to log in on one web-site (Forex Trading Social Network | Online Forex Trading Forum and Social Networking Site). I am working with Visual Studio 2010 Professional. I created a simple WebBrowser trying to access the indicated web-site. The problem begins. Well, the website loads, but when you go to the login page (Forex Trading Social Network | Online Forex Trading Forum and Social Networking Site) and try to log in, it doesn't work. I mean, when I enter the login details the login page just refreshes itself and the login wasn't proceed. The same login page appear with every login attempt. The is the current problem!I check with Google, it works. But, it doesn't work with Forex Trading Social Network | Online Forex Trading Forum and Social Networking Site! Why?
I have the following code which should go to a particular company page from the request page. In the website folder Company page is under a folder called Companies and the request page is under Requests folder.
Dim strUrl As String = "/Companies/Details.aspx?Company_ID=" & .Company_id litlCompany.Text = "<a href=" & strUrl & ">" & .Company.Name & "</a>"
How to make a link button visible after another button has been clicked in asp.net(vb) in button_click()
it says error as "Object reference not set to an instance of an object."
i've done this in my code
Protected Sub InsertButton_Click(ByVal sender As Object, ByVal e As System.EventArgs) Dim receipt As LinkButton = FormView1.FindControl("LinkButton1") ' receipt.Enabled = "true"
I want to extract the link in this code: <a class="i_link dominantcol" href="http:rapidgen.net/get/3lt4c/megakey.exe">Download</a>.Using webbrowser1. getelementbyid - how do i do it? I just want the link as dim x as string = http:rapidgen.net/...t4c/megakey.exe
I'm trying to open a PDF document from a hyperlink to a certain page. So I set the link to this:I can type the #Page=14 to the end and press enter and it will work but for some reason it will not work the first way.
I have an asp.net website that is using update panels on the page that i cant get to reload from the server. I have this for the disable page cache on the master page.
When I click the browser back button to go back to the page it says the page has expired. the other pages on my web site work and call the page load, the only solution i found but cant use is to wrp the whole page in an update panel, but i cant do this becuase i have a report viewer on the page that does not work with ajax.
I have master page in ASP.NET. I have added two asp controls to master page i.e. _EmpDROPDOWN and _findBUTTON.I have one content page. FindEmployee.aspx which shows result list of employees (Gridview) based on the selection made in _EmpDROPDOWN when _FindBUTTON is clicked on Master Page.I dont know how to read Master Page button click evenet in Content page.How to read master page button click event (VB.NET syntax) in Content Page?
I have a vb app with a webbrowser, and I am trying to search a page with about 1,000 links to click on the right one. Hereare some links from the page source:
HTML <tr> <td align="center"><input type="checkbox" name="checkedfund" value="9950::Custom"></td> <td>ING LifeStyle Moderate Growth Portfolio - Service Class</td>[code].....
I want to be able to find and click on a link in the page based on its name, like "ING LifeStyle Moderate Growth Portfolio - Service Class" for the first one. Also, I want the second link in each block, with the onClick=notesWindow function. How can I do this?
My office is developing a password-protected based site with thousands of pages. I'd like to be able to send an email to a client directing them to a particular page within the site. Assuming they are not already logged in, what happens is that they are directed to the login page, then, regardless of what link I put in the email, they end up at the default start page after the login.Is there a way that, when clicking on a link to an internal page on a password protected site
I am trying to create a link in a user area of my website. After logging in, the users info is passed to the allow access to specific areas of the site. What I would like to do is create an html link that is controlled by a conditional statement.
for example, after a user logs in, I want to check whether they have credentials to click on a link which will allow them to advance to something new. If they don't have the credentials, the link will be blocked out or not appear at.I am looking for a place to start on this task, any documentation or keywords would be helpful. Also code samples would help greatly.
I have a User registration form. On that form the user supply all his contact details and he can upload a image with the normal file upload control in ASP.net.
This is my problem. If anything goes wrong on the page then i give the User a error message saying what he left out or what went wrong. But the page refresh when that does happen. NOW the link to the image the user selected is gone. NOW when the user fix his error he thinks that he is uploading a picture but he never did because when the page re loaded it removed the link to his image inside the file upload control.
Note, the user don't have to upload a image, so there will be no error when the field is blank.
3. Find & Select an element(mostly element ID or div ID) on a web page like buttons etc.
4. Then extract data from a webpage . Like there's a word for example "Yellow" word in the web page . I need it to find it and copy it then paste into a textbox in my application.
I started a Zork like program in school last year out of boredom. I have a button the needs to be clicked to activate the events of the button. How do I link the Enter button to the button to launch the event.
i have a login page link above the page /// i want if user already loggedin then anybody click on loginlink then the user will automatically redirect to default.aspx ..
I'm building a quiz with VB 2010 for a school exam.I don't know how to link a button.Like from a button going to a presentation inside of the database.
Ive done this before but i forget now , all i want to do is , , when i click a button on my form it directs me to a website , my for doesnt have a browser on it , so it will be bringing me to a webpage externally, firefox or IE etc
In an application I have, when a user types in a textbox, the data in a listview is refreshed to reflect what the user is typing.As it stands, it does a refresh after each key is entered.Is there any way to smartly wait until the user has finished typing before initiating a data refresh?
I am developing an application, for a university project, which is using GDI to draw a flag, my application is also equiped with an undo stack, which is, essensially, where the problem is, so what happens is: I push the draw button to draw a box, when I do that, the solution normally creates the box and stores the object to the undo stack; however, when I ask it to undo the box, and refresh the panel, it randomly adds, endless threads to the undo stack, additionally, everytime that I set the panel to refresh in the undo procedure, it affects the draw procedure; therefore, when I tell it to draw a box, it fills the undo stach with five threads at a time, sometimes, it fills it with much more than five, and sometimes it keeps filling up the undo stack, untill I stop the debugging proccess. This is my code: