I have a multiline textbox which I need to split into an array using new line as a delimiter, I've tried what I think should work but it doesn't:
HTML
Dim strArr() As String
strArr = TextBox2.Text.Split(Environment.NewLine)
I want to split a string at a delimiter, but I don't want to discard the delimiter; It needs to become its own variable. [code] Is there any way of achieving this short of writing my own method?
View 3 Replieslets say I have a string that I want to split based on several characters, like ".", "!", and "?". How do I figure out which one of those characters split my string so I can add that same character back on to the end of the split segments in question?
Dim linePunctuation as Integer = 0
Dim myString As String = "some text. with punctuation! in it?"
For i = 1 To Len(myString)
[Code].....
I have an string that is returned from an xml file and looks similar to this name1="test 1" name2="test2" name3="test 3".I want to split this into 3 elements of key=value. I can't just split using a space because some of my values may contain spaces, e.g., test 1.So, I'd like to split the string using the " before the space. I've tried many variations but can't figure out the correct syntax to specify that my split characters are a " followed by a space. For instance, I've tried text.split({""" "}) but that returns elements split by " and ignores the space after the ".It shouldn't be this difficult. Can someone please help me with the correct syntax?
View 2 RepliesThe Data looks like this:
Quote:
057359-001 Pip Drt329 Auburndale, Fl (aub) - Pompano Beach, Fl (pob) 1:0 10gbe Lan Phy.
MyArr(0) ends up "057359-001" which is correct.
MyArr(1) ends up "Pip" only which is incorrect.
[Code]....
How should I split a string separated by a multi-character delimiter in VB?
i.e. If my string is say - Elephant##Monkey, How do I split it with "##" ?
I have word : "Banana". And i want it to split into :
B
a
n
[code].....
my code is :
[Code]...
The error is Value of type '1-dimensional array of string' cannot be converted to 'String'.
I have a csv file which I am populating to a datagridview. I am delimiting it using "," and "space". My csv file has "," at first instance and "space" in next two instances. I want to delimit the first instance using "," and the second instance using "space" and the third instance though has "space" I wanna ignore that space.
My CSV file :
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jarnvagstag,Mantel,Mantel1,Mantel2
100tag,01/01/1750 11:45:32 PM
200tag,01/02/1750 12:57:57 AM
[Code].....
Okay so what I'm trying to do is get the filename from OpenFileDialog/SaveFileDialog, only without the full path, and dump said filename into a variable so I can use it for other things.
Using the Split function, I can get any part of the array between the delimiters (""), but what I'm trying to do is get all the information after the LAST delimiter in the string.
A word document has several pages. How to split this pages into separate documents using VB.Net ?
I wish to automate this process.I used ms tutorial for basic learning: [URL]..But i do not know how to find page breaks in a document and move content of that page to separate document.
Is there a way to use the string.split command to get a section of a string without using an intermediary array?for example, if my string is "1 2" and I want to get the "2" part using string.split(" "), is there a way to avoid creating a new array, and just get the bit of the string I want in a single line?
View 4 RepliesI have a long string like this
dim LongString as String = "123abc456def789ghi"
And I want to split it into a string array. Each element of the array should be in 3 characters length[code]...
I have a string which I've split into an array. I need to change a value in the array and join the string together. However I cannot set the value of the array variable as it's read only.Is there any way to do this without creating another array?
Dim LineOfText As StringDim aryTextFile As String[code...]
I want to take a string from a text box and split each letter of the string into an array. Then, I want to take the first item in the array(the first letter of the string)and capitalize it. Once I've done all that, I want to combine the array and convert it back to the original string it was, except I want the first letter to be capitalized(I've already placed this into a variable.)
Here's what I've come up with so far:
[Code].....
how to combine the array back to a string except I replace the first letter of the original string with the "firstLetter" variable I created.
i want to split a string in a array() i.e. if i enter "input" in the textbox it should stored like.......
s(0)=i
s(1)=n
and so on..
after that the value of s(0) in changed to his ascii code and increment by one then again changed from ascii code to char and should be changed again from a array to string.
for example if i enter a then it should change to b.
it is a just a little prob the bigger one i am facing is to store a file bytes to database and retrieve it back,and i reached to decision that its not possible with ms-access but how to do with mysql and oracle?
I have a string of email [url]...
How can I split it so that I can add to this object[code]...
i know how to split a string(with only one char as the dilimiter)but what i want to do is for example i have a textbox (text1.text)i enter the info heresteve<split>tim<split>eva<split> and so on (7 times )
View 2 RepliesI've got a string like
Car//Bike//Train//Plane//Foot
How can i split them into an array?
Dim objStreamReader As New StreamReader(Server.MapPath(".eof_uploads") & tfile)
Dim arrText As New ArrayList
Do While objStreamReader.Peek() >= 0
[Code]....
I have a string from a text document that would be formatted for example: "this, is, an, example" and i would like to add this to a gridview on my aspx page.
The above populates the gridview like this:
|this |
|is |
|an |
|example|
how can i get it to add a new colum instead of a new line? For Example:
|this |is |an |example|
I am importing a string into my database using the following [code]...
View 9 RepliesI am trying to split a long string of data into an array:
[Code]....
Ive tried a few ways to write out the regex, but to no avail. Also, sometimes responseFromServer2 contains newlines, and sometimes it does not, depending on the response I get from the server...
How can I assign a split parts of a string into an array list directly ?
View 1 RepliesFor example, I have string variable (MyString) as below.MyString = "First word || second order || third example || fourth item || fifth stuff"
There are separator "||" at MyString variable. I want MyString variable is spited based on separator "||"and stored it into new array variable.
Could you advise me the most efficient code to do this job in VB?
Trying to split a giant string that is the source of an HTML document after performing an httpget and read the lines into an array while removing empty lines. The following code does not work for me just puts the same string into the array at position (0) without splitting it.[code]...
View 1 Repliesi'm using Regex.Split to convert a text file's string to System.Array. The end result is System.Array of 211 strings.
Now what i need is to convert System.Array to a Byte of 211. How would I accomplish this?
System.Array to Dim x(211) as Byte?? Sample code would be great here. I've already visited many sites on this subject with no luck. code below.
[Code]...
Whats the best way to convert a list(of string) to a string with the values seperated by ,
View 3 RepliesI have a string builder that has a structre like[code]...
View 6 RepliesI have the following problem in VB.net. I have a string like Dim str as String = "ABCDEFGHIJKLMNOPQRSTUVWX" now i want to add a delimiter from any one of them (Comma, Hyphen, Slash, Tab) into the string at the specified position like after every One, Two and so on characters. i WANT THE RESULTANT STRING LIKE
[Code]....
I am working on finishing up a mvc 3 vb.net app... I have to parse about 2000 entries in a database and get the string value to the right of a " : " delimiter from one of the columns... Everything to the left I am not worried about but I need the value that is to the right of the colon for that item.. I have more issues involving needing to select string characters to the right or left of a delimiter... But if someone can show me how to achieve the above I can figure out the rest from there...
a example of the string is Jackson Smokehouse Fish Food:John Jacob JinggleHimer Schmit I would want to eliminate the first part of the string or just select the second part and put it in a variable for later processing...