Split String At First Instance Of Delimiter Only?
Aug 13, 2010
The Data looks like this:
Quote:
057359-001 Pip Drt329 Auburndale, Fl (aub) - Pompano Beach, Fl (pob) 1:0 10gbe Lan Phy.
MyArr(0) ends up "057359-001" which is correct.
MyArr(1) ends up "Pip" only which is incorrect.
[Code]....
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Nov 29, 2010
Okay so what I'm trying to do is get the filename from OpenFileDialog/SaveFileDialog, only without the full path, and dump said filename into a variable so I can use it for other things.
Using the Split function, I can get any part of the array between the delimiters (""), but what I'm trying to do is get all the information after the LAST delimiter in the string.
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Nov 17, 2010
I want to split a string at a delimiter, but I don't want to discard the delimiter; It needs to become its own variable. [code] Is there any way of achieving this short of writing my own method?
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Apr 26, 2010
lets say I have a string that I want to split based on several characters, like ".", "!", and "?". How do I figure out which one of those characters split my string so I can add that same character back on to the end of the split segments in question?
Dim linePunctuation as Integer = 0
Dim myString As String = "some text. with punctuation! in it?"
For i = 1 To Len(myString)
[Code].....
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Jan 11, 2012
I have an string that is returned from an xml file and looks similar to this name1="test 1" name2="test2" name3="test 3".I want to split this into 3 elements of key=value. I can't just split using a space because some of my values may contain spaces, e.g., test 1.So, I'd like to split the string using the " before the space. I've tried many variations but can't figure out the correct syntax to specify that my split characters are a " followed by a space. For instance, I've tried text.split({""" "}) but that returns elements split by " and ignores the space after the ".It shouldn't be this difficult. Can someone please help me with the correct syntax?
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Jun 21, 2010
How should I split a string separated by a multi-character delimiter in VB?
i.e. If my string is say - Elephant##Monkey, How do I split it with "##" ?
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Mar 4, 2010
I have a multiline textbox which I need to split into an array using new line as a delimiter, I've tried what I think should work but it doesn't:
HTML
Dim strArr() As String
strArr = TextBox2.Text.Split(Environment.NewLine)
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Dec 11, 2011
I have word : "Banana". And i want it to split into :
B
a
n
[code].....
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May 30, 2012
I have a csv file which I am populating to a datagridview. I am delimiting it using "," and "space". My csv file has "," at first instance and "space" in next two instances. I want to delimit the first instance using "," and the second instance using "space" and the third instance though has "space" I wanna ignore that space.
My CSV file :
HTML
jarnvagstag,Mantel,Mantel1,Mantel2
100tag,01/01/1750 11:45:32 PM
200tag,01/02/1750 12:57:57 AM
[Code].....
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Nov 22, 2011
A word document has several pages. How to split this pages into separate documents using VB.Net ?
I wish to automate this process.I used ms tutorial for basic learning: [URL]..But i do not know how to find page breaks in a document and move content of that page to separate document.
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Apr 15, 2009
Whats the best way to convert a list(of string) to a string with the values seperated by ,
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Apr 16, 2010
I have the following problem in VB.net. I have a string like Dim str as String = "ABCDEFGHIJKLMNOPQRSTUVWX" now i want to add a delimiter from any one of them (Comma, Hyphen, Slash, Tab) into the string at the specified position like after every One, Two and so on characters. i WANT THE RESULTANT STRING LIKE
[Code]....
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Oct 18, 2011
I am working on finishing up a mvc 3 vb.net app... I have to parse about 2000 entries in a database and get the string value to the right of a " : " delimiter from one of the columns... Everything to the left I am not worried about but I need the value that is to the right of the colon for that item.. I have more issues involving needing to select string characters to the right or left of a delimiter... But if someone can show me how to achieve the above I can figure out the rest from there...
a example of the string is Jackson Smokehouse Fish Food:John Jacob JinggleHimer Schmit I would want to eliminate the first part of the string or just select the second part and put it in a variable for later processing...
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Apr 27, 2010
this is my code -
With ad.Tables(2)
For i As Integer = 0 To .Rows.Count - 1
If .Rows(i)("name") & "" <> "" Then
temp &= .Rows(i)("name") & ", "
[Code]...
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Dec 15, 2010
I am trying to split a long string based on an array of words. For Example:Words: trying, long, array Sentence: "I am trying to split a long string based on an array of words."Resulting string array:Multiple instances of the same word is likely, so having two instances of trying cause a split, or of array, will probably happen.
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Sep 22, 2010
When the user clicks any item in the listbox ie lviproducts it passes that item to a textbox. The problem is that I want everything before the $ sign not to appear so only the amount ie 4.50 etc would appear in the textbox. So far I have no idea how to do this, but have the following code which is not working at all.
[Code]...
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Jul 28, 2009
What would be the simplest way to find the n-th position of delimiter in a string.For example, say, I have a string variable called FullFilePath that contains the path of a file, like, C:SourceFiles<mthyr><subject><filename>.txt From this, I would like to extract out mthyr, subject, and filename, using the delimiter, "".
I was hoping string.IndexOf would let me find the n-th position of the delimiter "", in which case I can use the result to do a string.Substring. But it looks like IndexOf only finds the first occurence of a certain string, which means I would have to interate this somehow to look for the n-th occurence.
Or is there another method that will help me do this more efficiently.
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Mar 7, 2009
eally been struggling with this one, and i cant seem to find a simple method of doing it...surely there must be one? I have a list of values that i am loading into a variable. I am trying to split that variable by the whitespace that separates each value...the only thing is the whitespace varies in size. eg.
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Mar 11, 2010
my code is :
[Code]...
The error is Value of type '1-dimensional array of string' cannot be converted to 'String'.
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Dec 28, 2011
I'm trying to split a Yahoo historical stock price csv file, downloaded into a string, by what looks like a space character. I want a new row for each split. The split function works for other characters I see in the string. I suspect the characters may be a non breaking space character but I've been unable to split on them. This is the test csv file that is downloaded into the string: [URL] I'm trying to split the string like this:
[Code]...
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Dec 11, 2011
Last year (2010) I came across a FANTASTIC command that allowed me to take a string of variables with a common delimiter and break it all back out into separate variables (possibly an array) with one statement.
[Code]...
As long as the delimiter was a unique specifiable character, this one-statement command could break it out into elements. my memory and point me in the right direction.
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Dec 5, 2011
These is the content of my txt file which is saved in D drive in my pc abc,1,2,3..I tried the flowing but it didn't work:[code]I am getting error on this line.. data = line.Split(","c)...it says this line isn't in use anymore or something and that I rather use LineInput but thats asks for filenumber and i don't know what that is. I am sorry but I am a complete beginner. what else can I try? [code]ok that error is gone now but now if I want to add these values to a list box..how can i do that?
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Aug 27, 2009
Is there a way to use the string.split command to get a section of a string without using an intermediary array?for example, if my string is "1 2" and I want to get the "2" part using string.split(" "), is there a way to avoid creating a new array, and just get the bit of the string I want in a single line?
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Jul 29, 2010
After having some trouble in my own code using String.Split and the Split(String(), Int32, StringSplitOptions) overload, I decided to look to the MSDN.I copied the entire VB.NET code example from this link: url...I placed it in a new class, and received the following errors (same errors as my own code example):[code]Why can my code not recogognize the string() parameter overloads to String.Split? Remember, i took the code from the MSDN link above, copied and pasted and it still did not work.I am counting on using the string() instead of char() overloads shown here: url...
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Apr 11, 2011
Background: I have a winForm app that registers a user in the database based on the information provided, auto-generates a random password and username, and e-mails the user a link to take an application based on the marketing company selected. Problem: hen the user clicks "Send Invitation" with data inputted iton all fields except the bundles listbox in debug, the NullReferenceException Error is thrown highlighting the line: Dim MCShort As String = Trim(splitMC(0))How do I fix this issue Here's a screenshot of the web app: Here's the code of the Send_Button_Click method off default.asx.vb:
Private Sub Send_Button_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Send_Button.Click
'TODO Add code to validate that all selections that are reaquired are met.
[code].....
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Nov 12, 2010
I have some code that splits a session into strings by a -
My session looks something like this 123-456-789- and I split it like this
Dim MyString As String() = Session("MySession").Split("-"C)
And i've got a some code like this
Dim x as Integer
For x = 0 to MyString - 1
Response.write("Ref: " & MyString(x) & "<br>")
Next
This writes the code like this
Ref: 123
Ref: 456
Ref: 789
Ref:
So it's adding an extra Ref where it shouldn't be because there is no data after the last -
Is there a way to stop this adding in the extra one?
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Sep 11, 2011
I have a long string like this
dim LongString as String = "123abc456def789ghi"
And I want to split it into a string array. Each element of the array should be in 3 characters length[code]...
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Apr 29, 2009
I have a string which I've split into an array. I need to change a value in the array and join the string together. However I cannot set the value of the array variable as it's read only.Is there any way to do this without creating another array?
Dim LineOfText As StringDim aryTextFile As String[code...]
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Aug 19, 2009
I want to take a string from a text box and split each letter of the string into an array. Then, I want to take the first item in the array(the first letter of the string)and capitalize it. Once I've done all that, I want to combine the array and convert it back to the original string it was, except I want the first letter to be capitalized(I've already placed this into a variable.)
Here's what I've come up with so far:
[Code].....
how to combine the array back to a string except I replace the first letter of the original string with the "firstLetter" variable I created.
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Jan 22, 2010
I want split a gridview row on an html tag. How can i do this preferably in C#??.row.cells[1].Text.Split("htmltag")
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