Trim Last Delimiter Of A String In .net?

Apr 27, 2010

this is my code -

With ad.Tables(2)
For i As Integer = 0 To .Rows.Count - 1
If .Rows(i)("name") & "" <> "" Then
temp &= .Rows(i)("name") & ", "

[Code]...

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Trim A String In A Textbox With Delimiter?

Sep 22, 2010

When the user clicks any item in the listbox ie lviproducts it passes that item to a textbox. The problem is that I want everything before the $ sign not to appear so only the amount ie 4.50 etc would appear in the textbox. So far I have no idea how to do this, but have the following code which is not working at all.

[Code]...

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Apr 15, 2009

Whats the best way to convert a list(of string) to a string with the values seperated by ,

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I have the following problem in VB.net. I have a string like Dim str as String = "ABCDEFGHIJKLMNOPQRSTUVWX" now i want to add a delimiter from any one of them (Comma, Hyphen, Slash, Tab) into the string at the specified position like after every One, Two and so on characters. i WANT THE RESULTANT STRING LIKE

[Code]....

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Oct 18, 2011

I am working on finishing up a mvc 3 vb.net app... I have to parse about 2000 entries in a database and get the string value to the right of a " : " delimiter from one of the columns... Everything to the left I am not worried about but I need the value that is to the right of the colon for that item.. I have more issues involving needing to select string characters to the right or left of a delimiter... But if someone can show me how to achieve the above I can figure out the rest from there...

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Nov 17, 2010

I want to split a string at a delimiter, but I don't want to discard the delimiter; It needs to become its own variable. [code] Is there any way of achieving this short of writing my own method?

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Find Which Delimiter Was Used During String Split?

Apr 26, 2010

lets say I have a string that I want to split based on several characters, like ".", "!", and "?". How do I figure out which one of those characters split my string so I can add that same character back on to the end of the split segments in question?

Dim linePunctuation as Integer = 0
Dim myString As String = "some text. with punctuation! in it?"
For i = 1 To Len(myString)

[Code].....

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I have an string that is returned from an xml file and looks similar to this name1="test 1" name2="test2" name3="test 3".I want to split this into 3 elements of key=value. I can't just split using a space because some of my values may contain spaces, e.g., test 1.So, I'd like to split the string using the " before the space. I've tried many variations but can't figure out the correct syntax to specify that my split characters are a " followed by a space. For instance, I've tried text.split({""" "}) but that returns elements split by " and ignores the space after the ".It shouldn't be this difficult. Can someone please help me with the correct syntax?

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Split String At First Instance Of Delimiter Only?

Aug 13, 2010

The Data looks like this:

Quote:

057359-001 Pip Drt329 Auburndale, Fl (aub) - Pompano Beach, Fl (pob) 1:0 10gbe Lan Phy.
MyArr(0) ends up "057359-001" which is correct.
MyArr(1) ends up "Pip" only which is incorrect.

[Code]....

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Finding The Position Of Certain Delimiter Using String.IndexOf?

Jul 28, 2009

What would be the simplest way to find the n-th position of delimiter in a string.For example, say, I have a string variable called FullFilePath that contains the path of a file, like, C:SourceFiles<mthyr><subject><filename>.txt From this, I would like to extract out mthyr, subject, and filename, using the delimiter, "".

I was hoping string.IndexOf would let me find the n-th position of the delimiter "", in which case I can use the result to do a string.Substring. But it looks like IndexOf only finds the first occurence of a certain string, which means I would have to interate this somehow to look for the n-th occurence.

Or is there another method that will help me do this more efficiently.

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How should I split a string separated by a multi-character delimiter in VB?

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I have a multiline textbox which I need to split into an array using new line as a delimiter, I've tried what I think should work but it doesn't:

HTML
Dim strArr() As String
strArr = TextBox2.Text.Split(Environment.NewLine)

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[2008] Splitting A String With A Variable Delimiter?

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eally been struggling with this one, and i cant seem to find a simple method of doing it...surely there must be one? I have a list of values that i am loading into a variable. I am trying to split that variable by the whitespace that separates each value...the only thing is the whitespace varies in size. eg.

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Jul 12, 2010

I'm working with this new API that returns some XML. The problem is that the developer has chosen to indent his returned XML and it's driving me nuts. So, I thought I'd just trim it and then use it that way. But it's not working. here is what I'm getting back from the API:

<response>
<result>success</result>
<session_guid>33434343556</session_guid>
</response>

The code, of course, comes back in a StreamReader object called reader. So my plan is to write the UNTABBED XML to a text file. I thought this would work:

dim output as String = reader.ReadToEnd()
dim xml as String

'open the file in a try/catch statment. Won't include that here

....
....

'Now, we're going to remove whitespace using String.Trim() and write it to a file:

xml = output.Trim()

Then I close the file and move on. The problem is that the String.Trim command isn't working! When I open the file, the indentations ARE STILL THERE and it's throwing everything off.

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Apr 9, 2010

I have this string that shall come in from another file. The string has maximum length of 102 digits. I need to compare the string with numbers in a pair and delete those from that string.

e.g - 6125223659587412563265... till 102

numbers that compare with this string-

first set - 61

new string = 25223659587412563265

second set - 36

new string = 252259587412563265

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How do I trim " out of a string? Because the following doesnt work:

[Code]...

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I need to trim everything preceding the last / in a string. for example if the string were "C:FilesNewprogram.exe" all I want is the "program.exe portion.

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How can I trim MyString to be MyStr?

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What code can I use to trim a word from a string in Visual Basic.NET?

for example, If I had the following string: Dim str As String = "Hello World"

And I want to trim this string so it only displays "Hello"

I have tried a few trim functions but can;t work it out.

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I'm working in Microsoft Access attempting to concatanate the results of a query into a single string. The code looks like this:rtn = Trim(rs.Fields(0).Value) Trim$(rs.Fields(1).Value)When I display the string in a list box, I only see the value for Fields(0) I cannot see the value for Fields(1).When I run the code in debug mode, I can see the value of rtn and it contains these non-alphanumeric boxes like this:"Earth4[] Admin[]" (where [] indicates the non-alphanumeric character)What can I do to cleanup the string, remove the [] and then display in my list box?

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I have a large text field taken from a databasers.Item("content")How can I limit this to say 100 characters but not cut off the last word. eg "limit this to 100 cha..."

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how to trim the first character of a string? I found some examples on how to trim the end or how to trim spaces but nothing on trimming a character off the front.

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[2008] How To Trim 2 Parts Of A String

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I currently have a string

<TEXT default_lang="en" str="Button text"/>

and I wish to remove parts of the string, I want to remove

<TEXT default_lang="en" str="
from the beginning and from the end:
"/>

so I am just left with Button Text in a text box

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Jul 17, 2011

I have a DGV and a button to open a browser window to an ip address and also a button to open the ip address gateway. I can open the ip address that is displayed in the DGV no problem. What I am stuck on is opening the gateway address. So for example I click a record in DGV then the button and my browser opens to 10.15.2.248 What I need to do is replace 248 with 1 The ips will all end differently though for example 10.20.2.34 , 10.256.34.4 and so on. So as far as I know I will have to trim to the last period and add a 1 How can I do this?

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If you assign a string that is longer than the current value of the MaxLenght property, VB6 automatically trims the value to MaxLength characters, whereas VB.NET doesn't. Is there any way to achieve the same in VB.Net.

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VS 2010 Doesn't Trim Get Rid Of Null Bytes In String?

Jun 17, 2010

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Once I had realised that was what was happening (which took a long time as these null bytes are completely invisible when you are looking at the data in String form) I thought fine I'll just use Trim on the string but I've found that this doesnt make any difference at all. I thought Trim was supposed to remove any blank space from the start/end of a string, which I assumed would include empty bytes as well.

So is there any alternative I can use that will trim the empty bytes off the end or do I have to do it the 'manual' way and loop through my byte array before converting it to string and remove any null bytes? One thing that has just popped into my head as I'm typing this is to try using the Chr method and pass it 0 and combine that with Trim like so:

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I know how to cut off characters at the end of a string using vb script, which uses the LEFT(string, #) syntax, however, how do i do this using vb.net?

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VS 2008 - Take A String Of Variables With A Common Delimiter And Break It All Back Out Into Separate Variables

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Last year (2010) I came across a FANTASTIC command that allowed me to take a string of variables with a common delimiter and break it all back out into separate variables (possibly an array) with one statement.

[Code]...

As long as the delimiter was a unique specifiable character, this one-statement command could break it out into elements. my memory and point me in the right direction.

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I have this string that i would like to remove all the ""

Here's the string:
form name="comment_form${form_id}" id="comment_form${form_id}" onsubmit="return false;" method="post" action="/comment_servlet?add_comment=1&comment_type=V"><input type="hidden"

[code].....

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I'm working with VB.Net. I have imported some data into the Data Set.I have four columns of data.

[Column 1]This is a test[/Column 1]
[Column 2]This is a comma, Test.[/Column 2]
[Column 3]This is a double quote " test.[/Column 3]

[code].....

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